frame dr.jafar etaps steps1

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    Modeling frame have 4 floors which include one column at the middle:

     

    Where it sides:

    Length = 10 m

    High = 3 m for each floor

    Width = 10 m

    Compressive strength shall be not less than 17 MPa; so for normal concrete:

     f'c column =32 MPa

    f'c beam /slab = 28MPa

    One way slab = short length/long length =< 0.5 "one way slab"

    So our case 2 way slab:

    The minimum thickness of two way slab are shown in ACI code 9.5.3.3

     Take slab thickness = 130 mm

    Cross section for the beam and column = 100*100 mm.

     

    For the support: fixed support

    Before entering the load we get this model:

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    Now:

    Live load-1 unit load- will be present in three cases for each case position which means

    direction.

    Fx=1KN (Case ONE)

    Fy=1 KN (Case TWO)

    Mxx= 1 KN.m (Case THREE)

    Live load:

    Case 1:

    Case 1 have four cases under it ,while live Load-Fx=1 KN- will apply on the middle of the

    column for first floor and get the displacement , then we will remove the unit load to the

    next floor and see the effect on the displacement, repeat this steps for each floor except a

    base .

    Case 1-1:

    When the unit load apply on the first floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame :

     

    The displacement at the center of the floor:

    Story 1 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    1.2mm -1.833E-11mm

    0mm 0 0.000007 0

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    Case 1-2:

    The unit load applies on the second floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame :

     

    The displacement at the center of the floor:

    Story 2 :

    Ux = Uy= Uz= ϴx= ϴy=  ϴz= 

    3.7mm -9.635E-11mm

    0mm 0 0.000009 0

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    Case1-3: The unit load applies on the third floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame :

     

    The displacement at the center of the floor:

    Story 3 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    3.8mm -1.101E-10

    mm

    0mm 0 0.000009 0

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    Case1-4: the unit load applies on the fourth floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame :

     

    The displacement at the center of the floor:

    Story 4:

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    9mm -2.564E-10mm

    0mm 0 0.000011 0

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    Case 2:

    Like case 1 but the unit load will take different position- called Fy in y direction - Case 2 have

    four cases under it. Live load-Fy=1KN- will apply on the middle of the column for first floor

    and get the displacement , then we will remove the unit load to the next floor and see the

    effect on the displacement, repeat this steps for each floor except a base .

    Case 2-1:

    When the unit load apply on the first floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame:

     

    The displacement at the center of the floor:

    Story 1 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    -1.833E-11mm

    1.2mm 0mm -0.000007 0 0

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    Case 2-2:

    The unit load applies on the second floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame :

     

    The displacement at the center of the floor:

    Story 2 :

    Ux = Uy= Uz= ϴx= ϴy=  ϴz= 

    -6.329E-11mm

    2.5 mm 0 mm -0.000009 0 0

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    Case2-3: The unit load applies on the third floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame :

     

    The displacement at the center of the floor:

    Story 3 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    -1.101E-10

    mm

    3.8 mm 0 mm -0.000009 0 0

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    Case2-4: the unit load applies on the fourth floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame:

     

    The displacement at the center of the floor:

    Story 4:Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    -1.35E-10mm

    5.1 mm 0 mm -0.00001 0 0

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    Case 3: This case will take z-direction and the same steps that we did at previous cases will

    be repeat.

    Case 3-1:

    The unit load applies on the first floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame:

    The displacement at the center of the floor:

    Story 1 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    0mm 0mm 9.874E-03mm

    0 0 0

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    Case 3-2:

    The unit load applies on the second floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame:

    The displacement at the center of the floor:

    Story 2 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    0mm 0mm 1.813E-02mm

    0 0 0

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    Case 3-3:

    The unit load applies on the third floor:

    Deformation of the Frame :

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    Show The Displacement of the Frame

    The displacement at the center of the floor:

    Story 3 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    0mm 0mm 2.610E-02mm

    0 0 0

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    Case 3-4:

    The unit load applies on the third floor:

    Deformation of the Frame :

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     Show the Displacement of the Frame

    The displacement at the center of the floor:

    Story 4:

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    0mm 0mm 3.504E-02mm

    0 0 0

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    Case 4-1:

    Now we will move from transitional to rotational load. The unit load will be applied on the

    first floor in X direction,Mx=1 KN.m:

    Deformation of the Frame :

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     Show the Displacement of the Frame

    The displacement at the center of the floor:

    Story 1 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    0mm -7.493E-03mm

    0mm 0.000072 0 0

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    Case 4-2:

    The unit load will be applied on the second floor:

    Deformation of the Frame :

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    Show the Displacement of the Frame

    The displacement at the center of the floor:

    Story 2 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    0mm -8.609E-03mm

    0mm 0.000072 0 0

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    Case 4-3:

    The unit load will be applied on the third floor:

    Deformation of the Frame :

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    Show the Displacement of the Frame

    The displacement at the center of the floor:

    Story 3 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    0mm -9.229E-03mm

    0mm 0.000072 0 0

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    Case 4-4:

    The unit load will be applied on the fourth floor:

    Deformation of the Frame :

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    Show the Displacement of the Frame:

    The displacement at the center of the floor:

    Story 4 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    0mm -9.642E-03mm

    0mm 0.000074 0 0

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    Case 5-1:

    The unit load will be applied on the first floor in y direction,My=1 KN.m:

    Deformation of the Frame :

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    Show the Displacement of the Frame

    The displacement at the center of the floor:

    Story 1 :Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    7.493E-03mm

    0mm 0mm 0 0.000072 0

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    Case 5-2:

    The unit load will be applied on the second floor:

    Deformation of the Frame :

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    Show the Displacement of the Frame:

    The displacement at the center of the floor:

    Story 2 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    8.609E-03mm

    0mm 0mm 0 0.000072 0

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    Case 5-3:

    The unit load will be applied on the third floor in y direction:

    Deformation of the Frame :

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    Show the Displacement of the Frame 

    The displacement at the center of the floor:

    Story 3 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    9.229E-03mm

    0mm 0mm 0 0.000072 0

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    Case 5-4:

    The unit load will be applied on the fourth floor :

    Deformation of the Frame :

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     Show the Displacement of the Frame:

    The displacement at the center of the floor:

    Story 4 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    9.642E-03mm

    0mm 0mm 0 0.000074 0

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    Case 6-1:

    The unit load will be applied on the first floor in Z direction,MZ=1 KN.m:

    Deformation of the Frame :

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    Show the Displacement of the Frame 

    The displacement at the center of the floor:

    Story 1 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    1.375E-12mm

    0mm 0mm 0 0 0.000045

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    Case 6-2:

    The unit load will be applied on the second floor:

    Deformation of the Frame :

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     Show the Displacement of the Frame 

    The displacement at the center of the floor:

    Story 2 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    5.201E-12mm

    -3.052E-12mm

    0mm 0 0 0.000086

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    Case 6-3:

    The unit load will be applied on the third floor:

    Deformation of the Frame :

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    Show the Displacement of the Frame 

    The displacement at the center of the floor:

    Story 3 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 5.355E-12

    mm-7.217E-12

    mm0mm 0 0 0.000126

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    Case 6-4:

    The unit load will be applied on the fourth floor:

    Deformation of the Frame :

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     Show the Displacement of the Frame 

    The displacement at the center of the floor:

    Story 4 :

    Ux1 = Uy1= Uz1= ϴx1= ϴy1=  ϴz1= 

    2.751E-12mm

    -1.536E-11mm

    0mm 0 0 0.000166