frequency distribution solution (1)
DESCRIPTION
wfcvsdvsdvTRANSCRIPT
The following data set gives the yearly food stamp expenditure in thousands of dollars for 25.households in Alcorn County:
2.3 1.9 1.1 3.2 2.7 1.5 0.7 2.5 2.5 3.1 2.52.0 2.7 1.9 2.2 1.2 1.3 1.7 2.9 3.0 3.2 1.72.2 2.7 2.0
Solution:
Array Ascending:
0.7,1.1,1.2,1.3,1.5,1.7,1.7,1.9,1.9,2.0,2.0,2.2,2.2,2.3,2.5,2.5,2.5,2.7,2.7,2.7,2.9,3.0,3.1,3.2,3.2
1: Range= Max – Min
R= 3.2-0.7 = 2.5
2: No.of Classes : (K)
K= 1+3.3221 Log N
Here N= 25
K= 1+3.3221 Log (25)
K=5.64 OR K= 6
3: Class Interval Size:
h= Range/No. of Classes
h= 2.5/5.64= 0.4 or h= 0.5
Frequency distribution Table:
C.I Tall Bar f C.B Mid.Pt (x) C.F
0.5-0.9 I 1 0.45-0.950.5+0.9/2=0.
7 1+0=1
1.0-1.4 III 3 0.95-1.451.0+1.4/2=1.
2 3+1+41.5-1.9 IIIII 5 1.45-1.95 1.7 5+4=92.0-2.4 IIIII 5 1.95-2.45 2.2 5+9=14
2.5-2.9 IIIIIII 7 2.45-2.95 2.77+14=2
1
3.0-3.5 IIII 4 2.95-3.55 3.24+21=2
5 ∑f=25
Note: Follow the instructions for Tally bar method guided in the class.
For C.B: 1.0-0.9/2 =0.05 ( Sub this value from Lower class limit and Add to Upper class limit then divide by 2 )