frequency distribution solution (1)

2
The following data set gives the yearly food stamp expenditure in thousands of dollars for 25. households in Alcorn County: 2.3 1.9 1.1 3.2 2.7 1.5 0.7 2.5 2.5 3.1 2.5 2.0 2.7 1.9 2.2 1.2 1.3 1.7 2.9 3.0 3.2 1.7 2.2 2.7 2.0 Solution: Array Ascending: 0.7,1.1,1.2,1.3,1.5,1.7,1.7,1.9,1.9,2.0,2.0,2.2,2.2,2.3,2.5,2.5,2.5,2. 7,2.7,2.7,2.9,3.0,3.1,3.2,3.2 1: Range= Max – Min R= 3.2-0.7 = 2.5 2: No.of Classes : (K) K= 1+3.3221 Log N Here N= 25 K= 1+3.3221 Log (25) K=5.64 OR K= 6 3: Class Interval Size: h= Range/No. of Classes h= 2.5/5.64= 0.4 or h= 0.5 Frequency distribution Table: C.I Tall Bar f C.B Mid.Pt (x) C.F 0.5-0.9 I 1 0.45- 0.95 0.5+0.9/ 2=0.7 1+0=1 1.0-1.4 III 3 0.95- 1.45 1.0+1.4/ 2=1.2 3+1+4 1.5-1.9 IIIII 5 1.45- 1.7 5+4=9

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Page 1: Frequency Distribution Solution (1)

The following data set gives the yearly food stamp expenditure in thousands of dollars for 25.households in Alcorn County:

2.3 1.9 1.1 3.2 2.7 1.5 0.7 2.5 2.5 3.1 2.52.0 2.7 1.9 2.2 1.2 1.3 1.7 2.9 3.0 3.2 1.72.2 2.7 2.0

Solution:

Array Ascending:

0.7,1.1,1.2,1.3,1.5,1.7,1.7,1.9,1.9,2.0,2.0,2.2,2.2,2.3,2.5,2.5,2.5,2.7,2.7,2.7,2.9,3.0,3.1,3.2,3.2

1: Range= Max – Min

R= 3.2-0.7 = 2.5

2: No.of Classes : (K)

K= 1+3.3221 Log N

Here N= 25

K= 1+3.3221 Log (25)

K=5.64 OR K= 6

3: Class Interval Size:

h= Range/No. of Classes

h= 2.5/5.64= 0.4 or h= 0.5

Frequency distribution Table:

C.I Tall Bar f C.B Mid.Pt (x) C.F

0.5-0.9 I 1 0.45-0.950.5+0.9/2=0.

7 1+0=1

1.0-1.4 III 3 0.95-1.451.0+1.4/2=1.

2 3+1+41.5-1.9 IIIII 5 1.45-1.95 1.7 5+4=92.0-2.4 IIIII 5 1.95-2.45 2.2 5+9=14

2.5-2.9 IIIIIII 7 2.45-2.95 2.77+14=2

1

3.0-3.5 IIII 4 2.95-3.55 3.24+21=2

5 ∑f=25

Note: Follow the instructions for Tally bar method guided in the class.

Page 2: Frequency Distribution Solution (1)

For C.B: 1.0-0.9/2 =0.05 ( Sub this value from Lower class limit and Add to Upper class limit then divide by 2 )