gas power cycles 1 (1)
TRANSCRIPT
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Classification of Thermodynamic
Cycles
We can classify thermodynamic cycles
according to their desired output:
the state of the working fluid:
or whether or not the working fluid is
replaced in each cycle
Power cycles vs. refrigeration cycles
Gas cycles vs. vapor cycles
Closed cycles vs. open cycles
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Heat engines
Internal combustion:
the heat is supplied tothe working fluid by
burning the fuel within
the system boundaries
e.g. automobile
engines
External combustion:
heat is supplied to theworking fluid from a
source external to the
system
e.g. steam power
plants
We can also classify heat engines in terms of
how the heat is supplied to the working fluid.
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Analysis of gas cycles
actual gas power cycles are difficult to
analyze because of non-idealities such asfriction and non-equilibrium conditions
We make simplifications and strip thecycle of internal irreversibilities. Then we
end of with an ideal cycle that closely
resembles the actual cycle.
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Simplification of a real process to allowfor analysis
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Analysis of gas power cycles The working fluid remains a gas through
out the entire cycle.
Examples of such cycles: spark-ignitionengines, diesel engines, conventional gas
turbines. All of these engines are internal
combustion engines. This means that the
working fluid undergoes chemicalreactions in the cycle:
air + fuel combustion gases
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Air standard assumptionsSet of assumptions that we make in the analysis
of internal combustion engines: the working fluid is air which is an ideal gas
all processes of the cycle are internally
reversible the combustion process is replaced by a heat-
addition process from an external source
the exhaust process is replaced by a heatrejection process that restores the working fluidto its initial state (i.e. we consider a closed cycle)
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Reciprocating engines
top dead center: position
of piston when it forms
smallest volume in cylinder
bottom dead center:position of piston when it
forms largest volume in
cylinder
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Volumes
TDC
BDC
min
max
VV
VVr ==
Compressionratio:
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Mean effectivepressure
A fictitious pressurethat, if it acted on
the piston over the
entire power stroke,
would produce the
same amount of net
work as the actual
cycle.
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Classification of reciprocating engines
Spark ignition (SI): combustion is
initiated by a spark plug. Ideal cycle is theOtto cycle.
Compression ignition (CI): air-fuelmixture is self ignited as a result of
compressing the mixture above its self
ignition temperature. Ideal cycle is theDiesel cycle.
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4 stroke spark ignition engine
Actual
cycle
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4 stroke spark ignition engine
Ideal cycle
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2 stroke reciprocatingengine
Same for 4 functionsare executed in just 2
strokes: the power
stroke and the
compression stroke.
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Otto CycleApply the air-standard assumptions to SI engines we
get the idealized version: the Otto cycle
Process 1-2: isentropic compression, Process 2-3: constant
volume heat addition, Process 3-4: isentropic expansion,
Process 4-1: constant volume heat rejection.
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Analysis of Otto Cycle:
Ideal gas w/ constant Cv.
The cycle is
executed in aclosed system,
i.e. a cylinder.
( )23v
23in
TTc
uuq
==
( )14v
14out
TTcuuq=
=
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Thermal efficiency of the Otto cycle
Constant Cv
1k
in
netotto,th
r11
qw
==
How do we derive this?
compression ratio
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Isentropic relations for ideal gas
with constant specific heat
k
2
1
consts1
2
k)1k(
1
2
consts1
2
1k
2
1
consts1
2
v
v
P
P
PP
TT
vv
TT
=
=
=
=
=
=v
p
C
Ck=
These equations are used torelate the properties of the states
before and after the isentropic
expansion and compression
processes.
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th of the ideal Otto cycle
k=1.4
The maximum
feasible compressionratio is limited by
engine knock. This is
when the fuel and air
mixture is compressedbeyond its autoignition
temperature and
premature ignition
occurs.
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Specific heat ratio and th
Air at room temperature
smaller molecule, argon
larger molecule, ethane
Working fluid in real engines contains
larger molecules and it is used at much
higher temperatures. Both result in lower
th. A typical value is about 25 to 30%.
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Analysis of isentropic processes when
specific heat varies with temperature
Cannot use the isentropic ideal gas relations
Instead we use Table A.17 and reduced pressure (Pr)or reduced volume (vr) to relate the properties of thestates before and after an isentropic process.
We can also use ideal gas law to find temperature
We find u from Table A.17
1r
2r
ttanconss1
2
P
P
P
P == 1r
2r
ttanconss1
2
v
v
v
v ==
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Example 8-2 An ideal Otto cycle has a compression ratio of 8.
At the beginning of the compression process, air
is at 100 kPa and 17C, and 800 kJ/kg of heat istransferred during the heat addition process.
Accounting for the variation in specific heats with
temperature, determine (a) the maximum temperature and pressure that
occur during the cycle,
(b) the net work output,
(c) the thermal efficiency and
(d) the mean effective pressure for the cycle.
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Example 8-2