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Gases Chapter 9

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Gases Chapter 9. What parameters do we use to describe gases? pressure: force/unit area 1 atm = 101 kPa; volume: liters (L) Temperature: K. - PowerPoint PPT Presentation

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Page 1: Gases Chapter 9

Gases Chapter 9

Page 2: Gases Chapter 9

What parameters do we use to describe gases?

pressure: force/unit area 1 atm = 101 kPa;

volume: liters (L)

Temperature: K

Page 3: Gases Chapter 9

What is meant by % volume? In principle, the actual molecular volume of a gas is so small in comparison to the volume it will occupy that we treat gases at mathematical points.

Page 4: Gases Chapter 9

How do we measure pressure?

above 1 atmosphere

below 1 atmosphere

A column of air 1 m2 has a mass

of 10,300 kg, producing a

pressure of 101 kPa due to

gravity (14.7 pounds/in2)

1 atm = 76 cm Hg; 101 kPa

Page 5: Gases Chapter 9

Boyle’s Law is concerned with the relationship of pressure and volume using a fixed amount of gas ( a fixed number of mols of gas)

P*V = constant at constant temperature

Avogadro’s Law is concerned with the relationship between the number of molecules or mols (n) and the volume of a gas under conditions of constant pressure and temperature

V n at constant pressure and temperature

Charles’ Law is concerned with the relationship of temperature and volume when dealing with a constant amount of gas (mols)V T when T is expressed in K. The K temperature scale is derived from the behavior of gasesif V T then V = kT where k is a constant at constant pressure

Page 6: Gases Chapter 9

Ideal gas law: PV = nRT where R is a constant

R = 0.0821 L.atm/K.mol

Note that at constant n and T, PV = constant Boyle’s Law

Note that at constant P and T V/n = constant Avogadro’s Law

Note that at constant P and n, V/T = constant Charles’s Law

Page 7: Gases Chapter 9

Standard conditions of pressure and temperature

T = 0 °C (273 K)

Pressure: 1 atm

What volume does a mol of any ideal gas occupy at STP?

PV = nRT V = 1mol(0.0821 L*atm/K*mol)(273 K)/(1 atm)V = 22.4 L

This means that equal volumes of gases under identical conditions of temperature and pressure contain equal number of molecules

Page 8: Gases Chapter 9

What is the difference between an ideal gas and a real gas?

Page 9: Gases Chapter 9

The ideal gas equation was generated from the kinetic theory of gases making the following assumptions

1. The molecules could be treated as points (ie molecular volume = 0)

2. There are no attractive interactions between molecules.

3. Gas particles move around at random

4. Collision of gas molecules with the wall are totally elastic

5. The kinetic energy of the gas particle is to temperature (K)

In general, the ideal gas law works best at low pressures and high temperatures

Page 10: Gases Chapter 9

Real Gases: van der Waal’s equation

(P + an2/V2)(V-nb) = n RT

an2/V2 corrects for intermolecular attractions

nb corrects for the real volume of molecules

Page 11: Gases Chapter 9

Dalton’s Law of partial pressures:

Total atmospheric pressure = 1 atm;

How much of the pressure is contributed by N2?

Page 12: Gases Chapter 9

Pressure is a consequence of molecules colliding with each other and the walls of the container *062

Page 13: Gases Chapter 9

For air if

If PTV = nTRT and nT = (no2 + n N2 + ...)

at constant T, PTV = (no2 + n N2 + ...)RT

Since the actual volume of the molecules is small in comparison to the volume occupied by the gas, all molecule occupy the same volume V. The contribution to the total pressure is dependent on the number of collision of each gas with the wall and this is dependent on the number of molecule of each gas. Hence:

P = (PN2 + PO2 + ...)

PO2V = nO2RT ; PN2V = nN2RT ...

Page 14: Gases Chapter 9

Temperature: a measure of the average kinetic energy of molecules

Page 15: Gases Chapter 9

Distribution of molecular speeds as a function of temperature

Page 16: Gases Chapter 9

What are some of the consequences associated with the fact that molecules at the same temperature have different speeds?

The size of the pinhole needs to be small

*07

Diffusion: mixing of gases Effusion: escape through a small opening

Page 17: Gases Chapter 9

. . . . . . . . .. . . .. . . .. . .. .. . .

Two molecules of different mass at the same temperature effusing through an opening

Page 18: Gases Chapter 9

. . . . . . . . .. . . .. . . .. . .. .. . .

. . . .

. . . .

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Two molecules of different mass at the same temperature effusing through an opening

Page 19: Gases Chapter 9

From the kinetic theory of gases

speed of a molecule u = (3RT/M)1/2

For two gases at the same temperature

1/2maua2 = 1/2mbub

2 ua = average speed of molecule a

ub = average speed of molecule b

ma /mb = ub2 /ua

2

The rate at which molecule a hits the pinhole u if the comparisons are made at the same concentration and temperature.

ub /ua = (ma /mb )1/2

Page 20: Gases Chapter 9

Solving some problems involving gases

1. A sample of gas at 25 °C and 2 atm pressure in a 5 L vessel was found to have a mass of 18 g. What is its molecular weight?

PV = n RT

2 atm*5 L = n*0.0821 (Latm/K mol)*298 K

n = 10/(0.0821*298) mol; 0.4087

n = wt/ mw; 0.4087 = 18g/mw

mw = 44 g/mol

Page 21: Gases Chapter 9

Suppose the gas at the right exerted a pressure of 15 cm as shown.

Would the pressure of the gas be greater or less than 1 atm?

How many atm of pressure is the gas exerting?

15.2 cm

1 atm = 76 cm

76 - 15.2 = 60.8

Page 22: Gases Chapter 9

Suppose we have a sample of equal amounts of H2 and D2 in a vessel and a small opening is introduced. What will be the initial rates of effusion?

uH2/uD2 = mD2/mH2 = (4/2)0.5 = 1.42

Will the relative rate change with time?

Page 23: Gases Chapter 9

What is the density of natural gas (CH4) at STP?

PV = nRT

density is g/mL or g/L

We know the molar volume of any gas is 22.4 L at STP

How many g of methane in a mole?

16g/22.4 L = 0.714 g/l or 7.14*10-4 g/mL or

PV =(wt/mw)*RT; mw*P/RT = (wt/V)

Page 24: Gases Chapter 9

The surface temperature of Venus is about 1050 K and the pressure is about 75 Earth atmospheres. Assuming these conditions represent a “Venusian STP, what is the standard molar volume of a gas on Venus?

PV = nRT

75 atmV =1mol*0.0821(Latm/K mol)*1050 K; V = 1.15 L

Page 25: Gases Chapter 9

Natural gas is a mixture of a number of substances including methane (mol fraction, 0.94); ethane (mol fraction, 0.04); propane (mol fraction, 0.015). If the total pressure of the gases is 1.5 atm, calculate the actual pressure contributed by each of the gases described.

mol fraction = mol A/(mol A + mol B + ....)

PT = 1.5 = P CH4+ PC2H6 + ...

Px V = nxRT nCH4/nC2H6 = PCH4/PC2H6 = 0.94/.04

CH4 = 0.94*1.5

C2H6 = 0.04*1.5

C3H8 = 0.015*1.5