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Formulals, Conversions and Data required to solve gate problems 1litre= .001 cubic meter 1m^3=1000litres 1BTU(british thermal unit) = 1055 joules 1 btu/hr=3.412 joules/s Area 100 cents = 1 Acre 1 Acre = 4840 sq yards 1 yard = 3' or 36" 1 cents = 435.60 sq ft 1 sq. m = 10.76 sq. ft 1 Acre= 4047 sq m 2,47 cents = 1 are(100 sq meter) 2.47 acres = 1 hectare(10,000 sq meters) Fn= Fn1 + Fn2 0,1,1,2,3,5,8,13,21.... Slope/ Gradient http://en.wikipedia.org/wiki/Grade_(slope) Contour interval: the difference in altitude represented by the space between two contour lines on a map PERT Te(expected time)= (O +4M + P)/6 where O=optimistic time, M= most likely time, P=pessimistic time. V(variance)=( (PO)/6)^2 Project variance= sum of variances along the critical path Conversions Fibonacci series Golden Ratio

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  • Formulals,ConversionsandDatarequiredtosolvegateproblems

    1litre=.001cubicmeter1m^3=1000litres1BTU(britishthermalunit)=1055joules1btu/hr=3.412joules/s

    Area100cents=1Acre1Acre=4840sqyards1yard=3'or36"1cents=435.60sqft1sq.m=10.76sq.ft

    1Acre=4047sqm2,47cents=1are(100sqmeter)2.47acres=1hectare(10,000sqmeters)

    Fn=Fn1+Fn2

    0,1,1,2,3,5,8,13,21....

    Slope/Gradienthttp://en.wikipedia.org/wiki/Grade_(slope)

    Contourinterval:thedifferenceinaltituderepresentedbythespacebetweentwocontourlinesonamap

    PERTTe(expectedtime)=(O+4M+P)/6whereO=optimistictime,M=mostlikelytime,P=pessimistictime.V(variance)=((PO)/6)^2Projectvariance=sumofvariancesalongthecriticalpath

    Conversions

    Fibonacciseries

    GoldenRatio

  • Standarddeviation=sqrootofvariance

    unitmassofreinforcedconcrete=2400kg/m3unitwtofreinfircedconcrete=2400*10(9.8)N/m3densityofsteel=7850kg/m3

    http://www.youtube.com/watch?v=q0DghZBRAU

    http://www.youtube.com/watch?v=QMmOMLstGm0

    ScaleofAerialPhotograph=Focallength/AltitudeaboveGroundlevel

    ForecastingPopulation

    Arithmaticmethod

    dP/dt=KaP=P1+Ka(tt1)

    P=populationt=time

    Ka=arithmeticgrowthconstant

    Geometricmethod

    dP/dt=KgPlnP=lnP1+Kg(tt1)Kg=lnP2lnP1/t2t1=ln[P2/P1]/t2t1

    P=populationt=timeKg=geometricgrowthconstant

    Note:lim(1+K)1/K=e=2.718baseofthenaturallogarithms

    K0

    BMandSFdiagram

    HooksLaw,YoungsModulus,BulkModulus,Poisson'sRatio

  • 1lux=1lumen/sqmeterluxistheunitofilluminanceFlux=illuminationrequired(lux)xsurfacearea(sqm)Flux(lumenoutput)(received)=MF(maintenancefactor)xUF(utilizationfactor)xFlux(installed)depreciationfactor=reciprocalofmaintenancefactorlux=candela/d^2cd(candela)=lm(lumen)/(2(1cos(/2)))

    forisotrophiclightsource(alldirections),lumen=candelax4x22/7http://www.compuphase.com/electronics/candela_lumen.htm

    RoomIndex(RI)=LxW/[Hmx(L+W)]Hm=mountingheight

    SpacingtoheightratioSHR=1/Hmx[(A/N)^1/2]

    T(reverbarationtimeinseconds)=.161xV(volumeinm3)/A(soundabsorptionpowerinm2sabine=areaxcoeffcientofabsorption)Lp=20log10(Prms/Pref)dBLp2=Lp1+20log10(r1/r2)lpsoundpressuresoundlevel10log10(Prms/Pref)dB

    Thehandlingcapacity(lifts)iscalculatedbytheformula:H=3OOxQx100/TXPwhereH=handlingcapacityasthepercentageofthepeakpopulationhandledduring5minperiod,Q=averagenumberofpassengerscarriedinacar,T=waitinginterval,andP=totalpopulationtobehandledduringpeakmorningperiod.(Itisrelatedtotheareaservedbyaparticularbankoflifts.)

    ThevalueofQdependsonthedimensionsofthecar.Itmaybenotedthatthecarisnotloadedalwaystoitsmaximumcapacityduringeachtripand,therefore,forcalculatingHthevalueofQistakenas80percentofthemaximumcarryingcapacityofthecar.

    Thewaitingintervaliscalculatedbytheformula:T=RTT/N

    Acoustics

  • ivwhereT=waitingintervalN=numberoflifts,andRTT=roundtriptime,thatis,theaveragetimerequiredbyeachliftintakingonefullloadofpassengersfromgroundfloor,dischargingtheminvariousupperfloorsandcomingbacktogroundfloorfortakingfreshpassengersforthenexttrip.

    Thermaltransmittance,alsoknownasUvalue,istherateoftransferofheat(inwatts)throughonesquaremetreofastructuredividedbythedifferenceintemperatureacrossthestructure.Itisexpressedinwattspermetressquaredkelvin,orW/mK.Wellinsulatedpartsofabuildinghavealowthermaltransmittancewhereaspoorlyinsulatedpartsofabuildinghaveahighthermaltransmittance.

    =AU(T1T2)

    whereistheheattransferinwatts,Uisthethermaltransmittance,T1isthetemperatureononesideofthestructure,T2isthetemperatureontheothersideofthestructureandAistheareainsquaremetres.

    Theformulaforventilationheatlossis:

    Q=N.V.Sp.ht.dt

    WhereQ=heatloss(Watts)(W)N=Numberofairchangesperhour.Anairchangeisoneroomvolume.V=Roomvolume(m3)Sp.ht.=Specificheatfactorforair.Thisisfoundfromthefollowingformula.Sp.Ht.Factor=(Specificheatcapacityofairx1000toconvertfromkJtoJoulesxdensityofair)/3600toconvertfromhrtosecs.Sp.Ht.Factor=(1.01x1000x1.2)/(3600)Sp.Ht.Factor=0.34dt=temperaturedifferencebetweeninsideandoutside(oC)

    DuctcrosssectionalareaA(m2)=q(airflowratem3/s)/v(airspeedm/s)

    q(flow=novehicles/time)=1/h(timeheadway=timebetweenrearbumpertorearbumper)densityk=n/distance(numberofvehiclesoccupyingagivenlengthnofhighway

    distanceheadway=distancebetweencorrespondingpointsintwo

    Trafficformulas

  • successivevehiclesk(density)=1/s(distanceheadway)

    usedforpipeslargerthan2"andsmallerthan6'india

    v=1.32.Ch.R^0.63.S^0.54v=averagevelocityft/sCh=HazenWilliamsCoefficientR=Hydraulicradiusofflowconduit(ft)s=ratioofhL/L,energyloss/headlenghthofconduit(ft/ft)

    inSIUnits

    v=0.85.Ch.R^0.63.S^0.54v=averagevelocity(m/s)Ch=HazenWilliamsCoefficientR=Hydraulicradiusofflowconduit(m)s=ratioofhL/L,energyloss/headlenghthofconduit(m/m)

    VolumeflowrateQ=Av

    r=rateofinterestasdecimaln=nooftimesinterestiscompoundedinayeart=noofyears

    PlumbingandWaterSupplyHazenWilliamsFormula

    Ammortisationformulaforsinkingfund

    CompoundInterest