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University of Waterloo Department of Electrical and Computer Engineering
GENE 123: Electrical Engineering
Mid-Term Exam W’03 February 07, 2003
Time Allowed: 2 Hours Instructor: David Brush
Instructions:
1. Answer all questions. 2. The exam is a closed book examination. 3. Electronic calculators are allowed. 4. Aid Sheet is attached at the end of the examination paper. 5. Clearly show all steps used in solution. No marks will be given for numerical
results unless accompanied with correct solution method. 6. Use correct SI units in all your answers,
Question Q1 Q2 Q3 Q4 Q5 Q6
Mark
Name:
I.D.#:
Question 1 page 2/10 Two point charges q1 = Q C and q2 = 4 Q C are located along the x-axis at (0,0) and (3,0) respectively as shown in figure 1.
(a) Calculate the magnitude and direction of the electric
field vector at (1,0). (b) Find the location, magnitude and sign of a third point
charge so that the entire system of charges is in equilibrium. (Net force acting on each charge =0)
Figure 1
Question 2 page 3/10 Three point charges are placed at the three corners of a right angle triangle as shown in Figure 2. Calculate: (a) The potential at the point marked p. (b) The potential energy of q1
q1= 5q
q2= - 3q
--
+
q3= - 3q
d = 0.05mp
d
Figure 2
Question 3 page 4/10 A straight piece of wire (mass = 10.5 g, length = 50 cm) rests on top of two rails and completes the circuit shown in figure 3. A uniform magnetic field of 0.206 T acts parallel to the rails (into the page) and perpendicular to the wire. (a) What is the value of i just before the wire lifts off the rails? (b) Will the wire levitate if the magnitude of i is increased?
50 cmLeft Rail Right Rail
10.5 g section of wire
0.206 T (into page)
i Figure 3
Question 4 page 5/10 Figure 4 shows an electric circuit that comprises a 36V Voltage source, a dependent source and three resistors R1= 3 ohms, R3=14 ohms and R2 (unknown). (a) Compute the power supplied or absorbed by each
source. (b) Apply the power balance equation (∑ Power supplied =
∑ Power absorbed) to determine the magnitude and direction of the current through element 2.
(c) What is the value of R2?
Figure 4
Question 5 page 6/10 (a) Find i in the network shown in figure 5 using KCL.
4 Ω
+
12 V
−
3 Ω4 Ω
2 Ω
2 Ω12 A
2 A
i
Figure 5
page 7/10 (b) Find v in the network shown in figure 6 using KCL & KVL.
Figure 6
Question 6 page 8/10 (a) Find: RAB of the resistive network shown in Figure 7.
R1= 1kΩ
B
R ABR2= 1kΩ
R 3= 1
k Ω
R 7= 1kΩ
R4=
1kΩ
R 5= 1kΩ
R6= 1kΩ
A
Figure 7
page 9/10
(b) Find Vo across R3 for the resistive network shown in Figure 8.
Is = 24mA
Vo
+
-
R1= 6kΩ
R2= 3kΩ
R3= 3kΩ
R4= 6kΩ
Figure 8
page 10/10 Formula Sheet: (Winter 2003) ME123 & GENE123
19
212
0 2
70 2
1.602192 10 [ ]
8,85419 10 [ ]
4 10
1. Constan
t
[
s
e C
C
N mN
A
ε
µ π
−
−
−
= − ×
= ×⋅
= ×
1 212 2
0 12 1
20
0
2Coulomb's Law [ N]
4
N [ ]C
NPoint Charge [ ]
C4
[ V]
2. Electrostatic
(Zero Voltage at )4
.
Field
pp
P
f
f ii
q qF
r
FEq
qE
r
qV
r
V V E ds
rπε
πε
πε
∧⋅=
=
=
= ∞
− = − ∫
urr
ur uur [V]
[3. Magn
Netic Fiel
]
[
d
N]v
i
Magentic Forceon particleinmotion F qv B
Magentic Forceoncurrent carryingwire F iL B
= ×= ×
1 2
1 2
[V]
Re : ( ) ...
Re :1/ 1 / 1 / ...1/
tan ( ) 1 / ( )
( ) [W]
dW dq.
4. Ohms
dq dtdd
a
Wt
L w
s N
p N
V I Ristors inseries R R R R
istors in parallel R R R R
Conduc ce G R
Power WattP V I
= ⋅Ω = + +
= + +
= Ω
= ⋅
=
=
J
2
2
in .
in /
Also terms of current P I R
And terms of voltage P V R
=
=