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TRANSCRIPT
GEOMATICS ENGINEERING
CHAPTER 5
Road Curve Design
1
Horizontal and vertical curve
• The center line of a road consists of series of straight lines
interconnected by curves that are used to change the
alignment, direction, or slope of the road.
• Curves that change the alignment or direction are
known as horizontal curves, and those that change the
slope are vertical curves.
2
Tangents and Curves
Tangents Curves
3
Horizontal curves
• Curves used in horizontal planes to connect two straight tangent sections are called as horizontal curves.
• When a highway changes horizontal direction, making the point of intersection. Change in direction would be too abrupt for the safety of modern, high-speed vehicles.
• It is therefore necessary to introduce a curve between the straight lines.
• The straight lines of a road are called tangents because the lines are tangent to the curves used to change direction.
• In practically all modem highways, the curves are circular curves; that is, curves that form circular arcs. The smaller the radius of a circular curve, the sharper the curve.
• For modern, high speed highways, the curves must be flat, rather than sharp. That means they must be large radius curves.
4
TYPES OF HORIZONTAL CURVES
• There are five types of horizontal curves.
• 1. SIMPLE. The simple curve is an arc of a circle connecting two tangents. The radius of the circle determines the sharpness or flatness of the curve.
• 2. COMPOUND. This curve normally consists of two simple curves of different radii joined together and curving in the same direction.
• 3. BROKEN BACK. The combination of short length of tangent (less than 100 ft) connecting two circular arcs that have center on same side.
• 4. REVERSE. It consists of two circular arcs tangent to each other, with their centers on opposite sides of the alignment.
• 5. SPIRAL. The spiral is a curve that has a varying radius. It is used on railroads and most modem highways. Its purpose is to provide a transition from the tangent to a simple curve or between simple curves in a compound curve.
5
TYPES OF HORIZONTAL CURVES
6
Degree of circular curve • Two definitions are used for the degree of curve.
Degree of Curve (Arc Definition) • The arc definition is most frequently used in high- way design.
• This definition states that the degree of curve is the central angle formed by two radii that extend from the center of a circle to the ends of an arc measuring 100 meters long.
• Therefore, if you take a sharp curve, mark off a portion so that the distance along the arc is exactly 100 m, and determine that the central angle is 12°, then you have a curve for which the degree of curvature is 12°; it is referred to as a 12° curve.
D
R
R
100 ft (D/360) = (100/2πR)
R = 5729.58/D = 5730/D
7
Degree of circular curve
Degree of Curve (Chord
Definition)
• The chord definition is used in railway
practice and in some highway work.
• This definition states that the degree of
curve is the central angle formed by two
radii drawn from the center of the circle
to the ends of a chord 100 meters long.
• If you take a flat curve, mark a 100-m
chord, and determine the central angle
to be 0°30’, then you have a 30-minute
curve.
8
ELEMENTS OF A HORIZONTAL CURVE • Point of Intersection (PI): the point at which the two
tangents to the curve intersect
• Delta Angle: the angle between the tangents is also equal to the angle at the center of the curve
• Back Tangent: for a survey progressing to the right, it is the straight line that connects the PC to the PI
• Forward Tangent: for a survey progressing to the right, it is the straight line that connects the PI to the PT
• Point of Curvature (PC): the beginning point of the curve
• Point of Tangency (PT): the end point of the curve
• Tangent Distance (T): the distance from the PC to PI or from the PI to PT
• External Distance (E): the distance from the PI to the middle point of the curve
• Middle Ordinate (M): the distance from the middle point of the curve to the middle of the chord joining the PC and PT
• Long Chord (LC): the distance along the line joining the PC and the PT
• Length of Curve: the difference in stationing along the curve between the PC and the PT
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ELEMENTS OF A HORIZONTAL CURVE
10
2cos
4tan
EM
TE
RLor
or
or
Δ is in radian
Circular Curve Stationing
• Initial route survey consists of establishing the PIs according to plan, layout the tangents, and establishing continuous stationing along them, from the start of the project, through each PI, to the end of the job.
• Starting point of any project is assigned a station value, and all other points along the reference line are related to it.
• If starting point is also the end point of a previous adjacent project, its station value may be retained.
• Otherwise an arbitrary value such as 10+00 for metric stationing is assigned.
• In Metric stationing, full stations are generally 1 km apart. Or Sometimes full station = Full length of tape or chain i.e. 30 m
• Staking at the closer spacing is usually done in urban situations, on sharp curves.
• Stakes are placed farther apart in relatively flat or gently rolling rural areas.
• After the tangents have been staked and stationed, the Δ angle is measured at each PI, and curves computed and staked.
• The station locations of points on any curve are based upon the stationing of the curves PI.
11
Example # 1
• Assume that a metric curve will be used at a PI where I =
8024’. Assume also that the station of the PI is 6 +
427.467, and that terrain conditioned require a minimum
radius of 900m. Calculate the PC and PT stationing, and
other defining elements of the curve. In this example 1 full
station = 1000 m.
• Sometimes, it is required to calculate curve data at 10 m, 20 m, or 30
m intervals or increments.
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ftxEM
mxTE
mxxRLC
stationPT
L
stationPC
T
stationPI
mxRT
mxradianinRL
416.2)2
'248cos(423.2
2cos
423.2)4
'248tan(092.66
4tan
829.131)2
'248sin(9002
2sin2
319.4936
947.131
372.3616
092.66
464.4276
092.66)2
'248tan(900
2tan
947.131)180
'248(900)(
0
0
0
0
0
Solution
(continued):
The arc distance from the PC to the next station 6 + 380 is (6380 – 6361.372) = 18.628
m. the arc distance for the final stationing is 6493.319 – 6480 = 13.319 m . All other
stations have 20 m stationing intervals.
13
What is degree of this
curve?
Example # 2 • Highway curve with R = 700.0 m, Δ = 13010’, and PI station = 5 +
784.850 m
• Calculate the PC and PT stationing, Long chord, Curve Length,
External and Middle Ordinate and degree of curve.
14
Vertical curves
• Curves exist in vertical plane are called as vertical curves.
• Vertical curves need to be inserted at peaks and troughs
on highways to smooth out gradient changes and provide
adequate sight lines.
• Generally, the simple parabola curve is used as the rate of
change of gradient.
• Function of each curve is to provide gradual change in
grade from the initial (back) tangent to the grade of
second (forward)tangent.
15
Profiles Curve a: Crest Vertical Curve (concave downward)
Curve b: Sag Vertical Curve (concave upward)
Tangents: Constant Grade (Slope)
16
17
BVC: Beginning of Vertical Curve
or PVC
V: Vertex or PVI
EVC: End of Vertical Curve
or PVT
G1 : percent grade of back
tangent (or g1)
G2 : percent grade of forward
tangent (or g2)
L: curve length (horizontal
distance) in m
x: horizontal distance from any
point on the curve to the BVC
r: rate of change of grade
Elements of Vertical Curve
Related Equations r = (g2 – g1)/L
where: g2 & g1 are grades in fraction and L in m
Yx = YBVC + g1x + (r/2)x2
where:
YBVC – elevation of the BVC in m, g1 in fraction
and x in m
Station of BVC = Station of Vertex (V) – L/2
Station of EVC = Station of BVC + L
Elevation of BVC (YBVC) = Elevation of Vertex (V) ± g1(L/2)
Elevation of EVC (YEVC) = Elevation of Vertex (V) ± g2(L/2)
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‘-’ sign for crest curve, and
‘+’ sign for sag curve.
g1 and g2 are in fraction
Example: Equal-Tangent Vertical Curve A +3.5% grade meets a -1.5% grade at station 60 +15 and elevation 250 m. An equal tangent
parabolic curve 300 m long has been selected to join the two tangents. Compute and tabulate
the curve for stakeout at full stations.
Assume 1 full station = 30 m.
g1 = 3.5%
g2 =1.5%
L = 300 m
Vertex station (V) = 60+15
=60*30+15 = 1815m
Vertex elevation (V) = 250 m
19
V
55 + 15
20
(55 + 15)
ElevEVC = 250 -1.5*150/100 = 247.75 m
Yx = YBVC + g1x + (r/2)x2
High and Low Points on Vertical Curves
Sag Curves:
Low Point defines location of catch basin for drainage.
Crest Curves:
High Point defines limits of drainage area for roadways.
21
mincurveoflengthL
ggA
A
LK
12
1./ gKxptlowhigh
Example: High Point on a Crest Vertical Curve
22
stationsormx
mK
A
70.21060*5.3
0.600.5
300
%0.55.35.1
Example • A grade of -3.5% meets another grade of +0.50%. The
elevation of the point of intersection is 267 m and
stationing is 780 m. Field coordinates require that the
vertical curve should pass through a point of elevation
268 m at stationing 780 m. compute a suitable equal
tangent vertical curve and full station (30 m) elevations
23
24
y = 268 m
x = L/2
yBVC = 267 +(3.5/100)*(L/2)
yBVC = 267 +(3.5L/200)
g1x = -3.5L/200
r/2 = 0.5+3.5/200L
rx2/2 = (0.5+3.5/200L)*(L/2)2
25
Yx = YBVC + g1x + (r/2)x2
g1 in fraction