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Geometric Sequences Section 3.2.1

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Page 1: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

Geometric Sequences

Section 3.2.1

Page 2: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

Vocabulary

Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant.

Common Ratio: The constant ratio between consecutive terms of a geometric sequence, denoted by r.

Page 3: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

Investigation 1: Recall: An arithmetic sequence is a sequence in which the difference between two consecutive terms is constant.

The constant difference between terms of an arithmetic sequence is denoted d and the explicit formula to find the nth term of a sequence is: an = a1 + d(n – 1).

Page 4: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

1. Identify the next three terms of the arithmetic sequence, then write the explicit formula for the

sequence: 3, 7, 11, 15, an = 3 + 4(n – 1) or an = 4n – 1

2. Use the formula from example #1 to find the 27th term of the sequence.

a27 = 3 + 4(27 – 1) =

19, 23, 27, . . .

107

Page 5: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

In an arithmetic sequence, the terms are found by adding a constant amount to the preceding term. In a geometric sequence, the terms are found by multiplying each term after the first by a constant amount. This constant multiplier is called the common ratio and is denoted r.

For each geometric sequence, identify the common ratio, r.3. 2, 6, 18, 54, 162, . . .

4. 5, 50, 500, 5000, . . .

5. 3, , , , . . .

6. -4, 24, -144, 864, -5184, . . .

3

2

3

43

8

r = 3

r = 10

r = ½

r = -6

Page 6: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

Tell whether the sequences is arithmetic, geometric or neither. For arithmetic sequences, give the common difference. For geometric sequences, give the common ratio.  7. 5, 10, 15, 20, 25, …. 8. 1, 1, 2, 3, 5, 8, 13, 21, …

9. 1, -4, 16, -64, 256, …

10. 512, 256, 128, 64, 32, …

arithmetic; d = 5

neither

geometric; r = -4

geometric; r = ½

Page 7: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

Check for Understanding:  11. Find the first four terms of a geometric sequence in which a1 = 5 and r = -3.

_____ , _____ , _____ , _____.  

12. Find the missing term in the geometric sequence: -7, _______ , -28, 56, _______ , . . .

5 -15 45 -135

× -3 × -3 × -3

56 ÷ -28 = -2So, r = -2

× -2

14

× -2

-112

Page 8: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

Investigation 2: The explicit formula used to find the nth term of a geometric sequence with the first term a1 and the common ratio r is given by: an = a1∙ rn-1

Write a rule for the nth term of the sequence given. Then find a10.  

  

Page 9: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

13. 1, 6, 36, 216, 1296, …

Rule: an = 1∙6n-1

a10 = 1∙610-1 = 10077696

  14. 14, 28, 56, 112, …

Rule: an = 14∙2n-1

a10 = 14∙210-1 = 7168

Page 10: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

Check for Understanding: 15. If a5 = 324 and r = -3, write the explicit formula for the geometric sequence and find a10.

_____ , _____ , _____ , _____, 324 

Rule: an = 4∙(-3)n-1

a10 = 4∙(-3)10-1 = -78732 

÷ -3

-108

÷ -3

36

÷ -3

-12

÷ -3

4

5 1

1324 3a

1324 81a

14 a

OR

Page 11: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

16. If a3 = 18 and r = 3 write the explicit formula for the geometric sequence and find a10.

Rule: an = 2∙(3)n-1

a10 = 2∙(3)10-1 = 39366

3 1

118 3a

118 9a

12 a

Page 12: Geometric Sequences Section 3.2.1. Vocabulary Geometric Sequence: A sequence in which the ratio of any term to the previous term is constant. Common Ratio:

20. If r = 2 and a1 = 1 for a geometric sequence, a. Write a rule for the nth term of the sequence.

b. Graph the first five terms of the sequence. (1, 1), (2, 2), (3, 4), (4, 8), (5, 16)

c. What kind of graph does this represent? exponential

11 2

n

na