given: force (f) = 7.0 n, mass (m) = 3.2 kg unknown = acceleration (a) solve: a = f/m
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The net forward force on the propeller of a 3.2 kg model airplane is 7.0 N. What is the acceleration of airplane?. Given: Force (F) = 7.0 N, Mass (m) = 3.2 kg unknown = acceleration (a) Solve: a = F/m = 7.0 N/ 3.2 kg = 2.19 N/kg. - PowerPoint PPT PresentationTRANSCRIPT
The net forward force on the propeller of a 3.2 kg model airplane is 7.0 N. What is the acceleration of airplane?
Given: Force (F) = 7.0 N,
Mass (m) = 3.2 kg
unknown = acceleration (a)
Solve: a = F/m
= 7.0 N/ 3.2 kg
= 2.19 N/kg
What net forces is needed to accelerate a 1900 kg automobile forward at 3.0 m/s2 ?• Given: mass = 1900 kg,
• a = 3.0 m/s2
• Unknown = F
• Solve: F = m x a
• F = 1900 kg x 3.0 m/s2
• = 5700 kg . m/s2
• OR F = 5700 N (Newton)
A base ball accelerates downward at 11.3 m/s2. If the gravitational
force is the
3 mGiven: F = 2.9 N, a = 11.3 m/s2
Unknown: mass
Solve: mass = force/acceleration
m = F/a
= 2.9 N/11./S2
= 0.25 kg
A sailboat and its crew have a combined mass of 655 kg. If a net force of 895 N is pushing the sailboat forward, what is the sailboat’s acceleration?• Given: F = 895 N mass = 655 kg
• Unknown = acceleration• Solve: a = F/m
a = 895N / 655 kg
acceleration = 1.37 m/s2