hawkes learning systems: college algebra
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Hawkes Learning Systems: College Algebra. Section 4.6: Inverses of Functions. Objectives. Inverses of relations. Inverse functions and the horizontal line test. Finding inverse function formulas. Inverses of Relations. Let R be a relation. The inverse of R , denoted , is the set - PowerPoint PPT PresentationTRANSCRIPT
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Hawkes Learning Systems:College Algebra
Section 4.6: Inverses of Functions
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Objectives
o Inverses of relations.o Inverse functions and the horizontal line test.o Finding inverse function formulas.
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Inverses of Relations
Let R be a relation. The inverse of R, denoted , is the set
In other words, the inverse of a relation is the set of ordered pairs of that relation with the first and second coordinates of each exchanged.
1R
1 , | , .R b a a b R
Consider the relation
The inverse of R is
, , ,7 01 2R .
1 1, ,7 0 2,R .
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Example 1: Inverses of RelationsDetermine the inverse of the relation. Then graph the relation and its inverse and determine the domain and range of both.
4, 1 , 3,2 , 0,5R
1 1,4 , 2, 3 , 5,0R
In the graph to the left, R is in blue and its inverse is in red. R consists of three ordered pairs and its inverse is simply these ordered pairs with the coordinates exchanged. Note: the domain of the relation is the range of its inverse and vice versa.
Dom 4, 3,0 , Ran 1,2,5R R
1 1Dom 1,2,5 , Ran 4, 3,0R R
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Example 2: Inverses of Functions
2y x
Determine the inverse of the relation. Then graph the relation and its inverse and determine the domain and range of both.
2, |R x y y x
1 2, |R x y x y
Dom , , Ran 0,R R
1 1Dom 0, , Ran ,R R
In this problem, R is described by the given equation in x and y. The inverse relation is the set of ordered pairs in R with the coordinates exchanged, so we can describe the inverse relation by just exchanging x and y in the equation, as shown at left.
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Inverses of Relations
Note:A relation and its inverse are mirror images of one another (reflections) with respect to the line Even if a relation is a function, its inverse is not necessarily a function.
Verify these two facts against the previous examples.
y x .
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Inverse Functions and the Horizontal Line Test
In practice, we will only be concerned with whether or not the inverse of a function f , denoted , is itself a function. Note that has already been defined: stands for the inverse of f , where we are making use of the fact that a function is also a relation.
1f
1f 1f
Caution! does not stand for when f is a function!1f 1
f
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Inverse Functions and the Horizontal Line Test
The Horizontal Line TestLet f be a function. We say that the graph of f passes the horizontal line test if every horizontal line in the plane intersects the graph no more than once.
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Inverse Functions and the Horizontal Line Test
One-to-One FunctionsA function f is one-to-one if for every pair of distinct elements and in the domain of f, we have . This means that every element of the range of f is paired with exactly one element of the domain of f.Note: If a function is one-to-one, it will pass the horizontal line test.
1x 2x 1 2f x f x
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Inverse Functions and the Horizontal Line Test
In Example 1 you have with and , then R is one-to-one, so its inverse must be a function. But, if you notice in Example 2, the graph of is a parabola and obviously fails the horizontal line test. Thus, R is not one-to-one so its inverse is not a function.
4, 1 , 3,2 , 0,5R Dom 4, ,3,0 R Ran 1,2,5R
2y x
Tip!The inverse of a function f is also a function if and only if f is one-to-one.
1f
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Copyright © 2011 Hawkes Learning Systems. All rights reserved.Example 3: Inverse Functions and the
Horizontal Line Test
Does have an inverse function?
No.
4f x x
We can see by graphing this function that it does not pass the horizontal line test, as it is an open “V” shape. By this, we know that f is not one-to-one and can conclude that it does not have an inverse function.
f x
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HAWKES LEARNING SYSTEMS
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Copyright © 2011 Hawkes Learning Systems. All rights reserved.Example 4: Inverse Functions and the
Horizontal Line Test
Does have an inverse function?
Yes.
35g x x
We know that the standard cube shape passes the horizontal line test, so g has an inverse function. We can also convince ourselves of this fact algebraically:
1 2 1 25 5x x x x
3 31 25 5x x 1 2 . g x g x
g x
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Inverse Functions and the Horizontal Line Test
Consider Example 3 again:We stated in the previous slide that because f is not one-to-one, it does not have an inverse function. However, if we restrict the domain of f explicitly by specifying that the domain is the interval , the new function, with its restricted domain, is one-to-one and has an inverse function. Let’s think about this graphically: what shape does the graph f have now that we restricted the domain? Notice that it is a diagonal line beginning at the point or, simply, the right half of the graph.
This process is called restriction of domain.
4f x x
4,
0,4 ,
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Finding Inverse Function Formulas
To Find a Formula forLet f be a one-to-one function, and assume that f is defined by a formula. To find a formula for , perform the following steps:1. Replace in the definition of f with the variable y. The result is an equation in x and y that is solved for y.2. Interchange x and y in the equation.3. Solve the new equation for y.4. Replace the y in the resulting equation with .
1f
1f
1f x
f x
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For example, to find the inverse function formula for the function
1. Replace with y.
Finding the Inverse Function Formulas
5 1f x x 5 1y x 5 1x y
5 1y x 5 1y x
15
y x
1 15
f x x
f x
2. Interchange x and y.
3. Solve for y.
4. Replace y with 1f x .
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Finding the Inverse Function Formulas
If you noticed, finding the inverse function formula for with the defined algorithm was a
relatively long process for how simple the function is. Notice that f follows a sequence of actions: first it multiplies x by 5, then it adds 1. To obtain the inverse of f we could “undo” this process by negating these actions in the reverse order. So, we would first subtract 1 and then divide by 5:
5 1f x x
1 15
. x
f x
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Example 5: Finding Inverse Function Formulas
Find the inverse of the following function.
53 1f x x
1
1 51 3f x x
We can always find the inverse function formula by using the algorithm we defined. However, this function is simple enough to easily undo the actions of f in reverse order. The application of the algorithm would be:
As you might notice, for this particular function, “undoing” the actions of f in reverse order is much simpler than applying the algorithm.
5
5
5
5
3 1
3 1
3 1
3 1
f x x
y x
x y
y x
5
5
5
11 5
3 1
3 1
1 3
1 3
y x
y x
y x
f x x
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Example 6: Finding Inverse Function Formulas
Find the inverse of the following function.
13 2xg xx
1
3 2xyx
13 2yxy
3 2 1y x y
3 2 1xy x y
3 2 1xy y x
3 1 2 1y x x
2 13 1
xyx
1 2 13 1
xg xx
We will apply the algorithm to find the inverse.
Substitute y for
Interchange x and y.
Solve for y. Substitute
for y. 1g x
g x .
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Finding Inverse Function Formulas
The graph of a relation and its inverse are mirror images of one another with respect to the lineThis is still true of functions and their inverses.Consider the function , its inverse
and the graph of both: 3( ) 1 2f x x
1
1 3( ) 2 1f x x
y x .
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Finding Inverse Function Formulas
Note: the key characteristic of the inverse of a function is that it “undoes” the function. This means that if a function and its inverse are composed together, in either order, the resulting function has no effect on any allowable input; specifically:
For reference, observe the graph on the previous slide.
1 1f f x x x f for all ,Do m and
1 . f f x x x ffor ll Doma
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Finding Inverse Function Formulas
Consider the function for and its inverse
(you should verify that this is the inverse
of f ).
213
xf x
1 3 1f x x
1 3 1f f x f x
23 1 1
3
x
23
3
x
33x
x
21 1
3f x
xff
213 1
3x
21 1x
1 1x x
1f
1x
Below are both of the compositions of f and :