head start lecture mathematics extension 1 · • mathematics is a skill based subject – your...
TRANSCRIPT
• 2018 Graduate from Baulkham Hills High School
• HSC All-Rounder, achieving a Band 6 across 12 units of
subjects:
– Biology
– Business Studies
– English (Advanced)
– Mathematics Extension 1
– Mathematics Extension 2
– Modern History
• 99.45 ATAR
• Internally ranked 1/187 for Maths Ext 1
• 100/100 HSC Assessment Mark and 99/100 Overall HSC
Mark for Maths Ext 1
Who am I?
2
• Section 1:
– Syllabus Overview
– Study tips and advice
– Some special tricks for Permutations and Combinations
• Section 2
– Mathematical Induction
• What is induction?
• Equality and Divisibility Type Questions
• False Proof by Mathematical Induction
• Section 3
– Trigonometry
• Auxiliary Angle Method
• T-formulae
• Trigonometric Identities
• Derivatives of Inverse Trigonometric Functions
• Primitive of sin2 𝑥 and cos2 𝑥
Today’s Schedule
I’m sorry but the old syllabus can’t come to the phone right
now. Why? Oh, ‘cause it’s dead!
Syllabus Overview
• The syllabus is your best friend!
• You are first cohort to do the new syllabus therefore it is
crucial that you have a clear understanding of what is on
it
– You don’t want to be surprised in the exam!
• It is important to know what topics are new and what
topics have been moved in order to utilise past
resources effectively
Syllabus Overview
• Also keep in mind that the 3U course is done
concurrently with the 2U course so you’ll need to be
familiar with 2U content in order to do some 3U topics
• E.g. Integral calculus (Integration)
Syllabus
Yr 12 topics:
• Proof (Mathematical Induction)
• Vectors
• Trigonometric functions
• Calculus (which includes differential equations)
• Statistical Analysis
*RED = new topic
Syllabus Overview
Examples of what has changed?
• The 4U Graphs topic has been moved into the 3U Yr 11 course
• Volumes of revolution have been moved from the 2U/4U course into
the 3U Yr 12 course
• Vectors is a new topic but there is slight overlap with 4U complex
numbers
• Pigeonhole Principle added to existing 3U Yr 11 perms and combs
topic
• Slope fields added to existing 3U differential calculus topic
• Simple Harmonic Motion moved to 4U
• Circle geometry, parametric/locus focused questions, binomial
identity proofs among other topics are now GONE
Syllabus Overview
• You’ve already had Year 11 to experiment with different
ways of studying
• Different people learn more effectively in different ways
e.g. visual learner, auditory learner, kinaesthetic learner
• I’ve compiled some tips which I found useful but the
most important thing is that you do what works for you!
Study Tips
How I studied for maths:
• Consistent effort for maths throughout the entire year =
less stress come exam time
• I didn’t use the reference sheet but I made sure I knew
what was on it just in case!
• Before exams, my routine for studying maths purely
consisted of doing past papers!
• Maths was the subject I dedicated the least time towards
in the lead up to Trials and the HSC
Study Tips
Effective studying:
• Mathematics is a skill based subject
– Your brain is a muscle that must be trained
– Reading over notes will not cut it to get a Band 6 in Mathematics
– Effective study involves:
Practice
Practice
Practice
Balance in studying:
ApplyConsolidate
• Topic focused
revision
• Past papers
• Reteach yourself
content
(exercises)
• Teach others!
• Derive formulas
Tips on past papers:
1. Grab a Paper
2. Read in 15 minutes
Circle questions that you don’t know
how to do
3. Use circled questions as exercise
Study should never be easy!
Using the formula sheet: Pros/Cons
• The formula sheet:
• Good: Less to remember, less silly mistakes, less stress
• Bad: Over-reliance, lose time, may lead to harder exams
• Don’t rely on your formula sheet! Use it as a backup!
• Deriving your formulae is another great way to
study...
• Some other ways to study for Mathematics:
1. Record Video Lessons for Your Own Revision Later (or
watch our free ATARNotes Videos!)
2. Race Through Quick, Short Exercises
3. Derive your Formulas
• Past papers/practice will always be the best way!
Other helpful methods of study:
• Make a list in a notebook/exercise book of questions you
continually get wrong, challenging questions, fast
methods of solving questions etc.
• Keep track of the silly mistakes you make to avoid
making them again!
• Continually add, revise and read this list until you are
confident with these topics
Note: this works well for ALL your subjects, not just MX1
’Dumb question’ bank:
• So you’ve covered permutations and combinations as
part of your combinatorics topics in the Year 11 course
• Before we dive into new Year 12 content, let’s discuss
some special things/tricks you should be aware of to
consolidate your knowledge!
Permutations and Combinations
Very quick recap:
• Recall: nPr = 𝑛!
𝑛−𝑟 !
nCr = 𝑛!
𝑛−𝑟 !𝑟!
• You can arrange ‘n’ different objects in a line in n! ways
• You can arrange ‘n’ different objects in a circle in (n-1)!
ways
• Divide by r! for ‘r’ number of repeated objects
Permutations and Combinations
A common area where people make mistakes in perms and
combs is when you are asked to divide things into equal
groups.
Perms and Combs – Equal Groups
How many ways can 5 people be chosen from a group of
10?10C5= 252 ways
How many ways can a group of 10 people be split into two
teams for a game of soccer?
10C5 x 5C5 = 252 ways?
Common silly mistake!
Perms and Combs – Equal Groups
WHY?
Let’s simplify the example to four people: A B C D
There are 4C2 = 6 ways of choosing 2 people out of the 4
1) A & B
2) A & C
3) A & D
4) B & C
5) B & D
6) C & D
Perms and Combs – Equal Groups
But look what happens when we are asked to divide
them into equal teams of two…
1) A & B VS C & D
2) A & C VS B & D
3) A & D VS B & C These are the same!
4) B & C VS A & D
5) B & D VS A & C
6) C & D VS A & B
There are only actually 3 different ways of dividing 4 people into 2 teams.
The other half are just repeating what we already have!
Perms and Combs – Equal Groups
REMEMBER: When splitting into equal groups, divide by
the (number of groups)!
How many ways can a group of 4 people be split into equal
teams of two?
Answer: 4C2 x 2C2
2!= 3 ways
Perms and Combs – Equal Groups
• Alternatively, you can also think this way:
• “From the perspective of one particular person, choose a
number of people from the remaining group to form a
team”
Let’s consider A B C D again from the perspective of A.
To be divided into equal teams, A needs one teammate. A
can choose from B, C or D. A has to choose 1 person from
3 i.e. 3C1 = 3 ways.
This gives us the same result as 4C2 x 2C2
2!= 3 using the
previous method
Perms and Combs – Equal Groups
So to answer that question… How many ways can a group
of 10 people be split into two teams for a game of soccer?
10C5 x 5C5
2!= 126 ways
Alternative method: 9C4 = 126 ways
Same answer!
Perms and Combs – Equal Groups
REMEMBER: This only applies when you are dividing into
equal groups!!!!
So for unequal groups…
E.g. How many ways can you divide 10 people into a group
of 8 and a group of 2?
10C8 x 2C2 = 45 ways
Perms and Combs – Equal Groups
• ‘Dividers’ or ‘slotting’ techniques are useful for some
types of perms and combs questions
Perms and Combs – ‘Dividers’ and ‘Slotting’
• ‘Dividers’ or ‘slotting’ techniques are useful for some
types of perms and combs questions
Ariana Grande asks, Q: How many ways can 7 different
rings be placed on the 5 fingers of a hand if:
i) There is no restriction on how many rings a finger can
have
ii) Each finger must have at least one ring
Give it a shot!
Perms and Combs – ‘Dividers’ and ‘Slotting’
Q: How many ways can 7 different rings be placed on the 5 fingers of a hand if:
i) There is no restriction on how many rings a finger can have
• For part i) we need to use ‘dividers’
• Permutate A B C D E F G | | | |
E.g. C|DAG|FE|B| = ||EAC|BGD|F =
Perms and Combs – ‘Dividers’ and ‘Slotting’
(‘|’ represents the space between a finger)
Q: How many ways can 7 different rings be placed on the 5 fingers of a hand if:
ii) Each finger must have at least one ring
• For part ii) we need to use ‘slotting’/’insertion’
• Permutate A B C D E F G
• Choose the spots to ‘slot’ the dividers in
A_B_C_D_E_F_G
• E.g. D_E_A_G_B_C_F =
Perms and Combs – ‘Dividers’ and ‘Slotting’
37
BREAK TIME!
Come ask questions
Check out our range of course notes outside –
All updated for the new syllabus!
When you hear the word ‘induction’, several images often
spring into mind.
Mathematical Induction
Induction cooking?
Workplace induction?
But what about Mathematical Induction?
• Mathematical Induction is a technique used in
mathematics to prove statements that are asserted by
natural numbers
– For example that 1+3+5+…+(2n-1)=n2 for all integers n≥1
• It works by proving that a statement is true for an integer
if it is true for the integer before it, thus creating a chain
effect
• Think about dominos!
Mathematical Induction
• There are three main types of induction questions
– Equality
– Divisibility
– Inequality
• All 3 types were previously tested in the HSC for Maths
Ext 1
• However, in the new syllabus, inequality type induction
questions have been moved to the Extension 2 course
• You will only need to worry about equality and
divisibility induction questions in Extension 1
Mathematical Induction
• There are four main steps to any induction question:
1. Prove true for the first integer of the domain (usually n=1)
2. Assume true for the general term n=k
3. Prove true for the general term n=k+1 USING the assumption
from part 2
4. Write a conclusion to sum up what is going on
• Step 1 forms the base element while Step 2 and 3 forms
the inductive element
• It is beneficial to have a strong, clear structure in your
working so that the marker can see that you understand
the rationale behind how mathematical induction works
Mathematical Induction
• Let’s see it in action by proving the geometric series
summation formula!
Mathematical Induction
𝑎 + 𝑎𝑟 + 𝑎𝑟2 +⋯+ 𝑎𝑟𝑛−1 =𝑎(𝑟𝑛 − 1)
𝑟 − 1
• ‘Short’ VS ‘Long’ Conclusion
• Short: By the principle of mathematical induction, the
statement is true.
• Long: The statement is true for n=k+1 if it is true for n=k.
Since it is true for n=1, it must be true for n=2 and n=3
and so on for all integers n≥1.
Mathematical Induction
Short Long
PROS • Takes less time to write
• Strong potential to still attain full marks
• Shows the marker you understand
what is going on
• Strengthens your proof
• Helps you to remember the actual
induction steps!
CONS • Slim risk of losing marks, especially if your
earlier sections were a little dodgy
• Takes more time to write
• “Unnecessary” and a “waste of
effort”?
• Now, let’s try a divisibility type question.
Prove using mathematical induction that 23𝑛 − 1 is
divisible by 7 for all n≥1
Mathematical Induction
Let’s do another question!
a) Show that 𝑘 + 3 3 = 𝑘3 + 9𝑘2 + 27𝑘 + 27
b) Prove that the sum of the cubes of three consecutive
positive integers is divisible by 9
Mathematical Induction
• Something to keep in mind is that n=1 isn’t necessarily
the default
• Always read the question carefully!
• E.g. take this question straight from a HSC paper
Mathematical Induction
• Remember: Induction only works if you’ve used all the
steps and satisfied both the base and the inductive
elements
• In the inductive element, you need to use the assumption
somewhere in Step 3
• You also can’t just do the inductive element by itself either
False proof by mathematical induction
Let’s say you were trying to prove:
1 + 2 + 3 +⋯+ 𝑛 =1
2(𝑛 − 1)(𝑛 + 2)
Mathematical Induction
50
BREAK TIME!
Come ask questions
Check out our range of course notes outside –
All updated for the new syllabus!
First, to get us in the mood for some trig, let’s start with a
fun mnemonic!
Trigonometry
Hey kids! Mnemonics are fun!
We all know the trigonometric identity: sin2 𝑥 + cos2 𝑥 = 1
By dividing both sides of this identity with cos2 𝑥 or sin2 𝑥 we
can also get these other two identities respectively:
• tan2 𝑥 + 1 = 𝑠𝑒𝑐2 x
• 1 + cot2 𝑥 = 𝑐𝑜𝑠𝑒𝑐2𝑥
All three of them are very useful in a variety of maths
problems and it is beneficial to be able to recall them in a
cinch.
If you have difficulty memorising these latter two identities,
there’s an easy mnemonic to help you remember them!
But first…a fun mnemonic!
53
Just remember:
“The one with the tan is sexy”
1 + tan2 𝑥 = sec2 𝑥
AND
“The one in the cot is cosy”
1 + cot2 𝑥 = 𝑐𝑜𝑠𝑒𝑐2𝑥
But first…a fun mnemonic!
• The auxiliary angle method of solving trigonometric
equations involves changing an equation with a sine and
cosine component into another form to make it easier to
solve
• asin 𝑥 ± 𝑏𝑐𝑜𝑠 𝑥 = 𝑐 is changed into 𝑅𝑠𝑖𝑛 𝑥 ± α = 𝑐
• a𝑐𝑜𝑠 𝑥 ± 𝑏𝑠𝑖𝑛 𝑥 = 𝑐 is changed into 𝑅𝑐𝑜𝑠 𝑥 ∓ α = 𝑐
• This requires the use of sum or difference expansions
• a, b, and R are positive numbers
• α is called the auxiliary angle
Trigonometry – Auxiliary Angle Method
The auxiliary angle method is also useful for graphing!
Let’s say we are asked to graph the function
y= 3 sin 𝑥 − cos 𝑥 , for 0 ≤ 𝑥 ≤ 2𝜋
Trigonometry – Auxiliary Angle Method
• Remember that it doesn’t just have to be for θ and θ/2!
E.g. you can write sin(4θ) as 2𝑡
1+𝑡2where t=tan(2θ)
• An easy way to remember the t formulae is through the
tan double angle formula
• tan 2𝑥 =2tan x
1−tan2 𝑥
Trigonometry – t formulae
• The t formulae can also be used to solve trigonometric
equations!
• But a very important thing you must remember is that
tan(𝜃
2) is undefined for
𝜃
2=±
𝜋
2, ±
3𝜋
2, ±
5𝜋
2etc. so you’ll
need to test 𝜃=±𝜋,±3𝜋,±5𝜋 etc. independently to see if
it is a solution
Trigonometry – t formulae
• Let’s do the previous question again but with the t
formulae this time:
3 sin 𝑥 − cos 𝑥 = 1 , for 0 ≤ 𝑥 ≤ 2𝜋
Trigonometry – t formulae
TIP: As you saw in that previous question, a common hint
that there are actually more solutions is if the 𝑡2 cancels
out.
Trigonometry – t formulae
• You’ll need all those formulas you’ve learnt to be able to
prove trigonometric identities and solve equations!
Trigonometric Identities
• You’ll need all those formulas you’ve learnt to be able to
prove trigonometric identities and solve equations!
Let’s do this question:
a) Show that cos 3𝑥 = 4 cos3 𝑥 − 3 cos 𝑥
b) Hence solve cos 3𝑥 + cos 2𝑥 + cos 𝑥 = 0(for 0 ≤ 𝑥 ≤ 2𝜋)
Trigonometric Identities
• In the Year 11 course, you learnt about differential
calculus and how to find the derivative of an equation
A syllabus dot-point in the Yr 12 course is that you:
Differentiating Inverse Trigonometric Functions
How do we differentiate inverse trigonometric functions?
Let me show you…
Differentiating Inverse Trigonometric Functions
Differentiating Inverse Trigonometric Functions
By following the steps I did through the document
camera, we arrive at these results:
Now that we know that, we can go the other way and
integrate those values to get some of our standard
integrals:
Differentiating Inverse Trigonometric Functions
• In the Yr 12 3U course you’ll need to know how to
integrate sin2 𝑥 and cos2 𝑥
• But how do we do it?
Primitive of sin2 𝑥 and cos2 𝑥
• In the Yr 12 3U course you’ll need to know how to
integrate sin2 𝑥 and cos2 𝑥
• But how do we do it?
The answer lies in the cosine double angle formula.
Let me show you how…
Primitive of sin2 𝑥 and cos2 𝑥
Cosine Double Angle Formula
• cos 2𝑥 = 2 cos2 𝑥 − 1
= 1 − 2 sin2 𝑥
Can be rearranged to be:
• cos2 𝑥 =1
2(1 + cos 2𝑥 )
• sin2 𝑥 =1
2(1 − cos 2𝑥 )
• Know these formulas by memory! (Or at least how to
derive them)
• These used to not be on the reference sheet but they are
now for the new syllabus
Primitive of sin2 𝑥 and cos2 𝑥
• Good luck as you begin your Year 12 course!
• Your school assessments will count now
• This is your time to shine!
• Put in the effort and don’t give yourself any chance for
regret!
Good Luck!