hnrs 227 lecture #2 chapters 2 and 3

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HNRS 227 Lecture #2 Chapters 2 and 3 Motion and Patterns of Motion presented by Prof. Geller 29 August 2002

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HNRS 227 Lecture #2 Chapters 2 and 3. Motion and Patterns of Motion presented by Prof. Geller 29 August 2002. Recall from Chapter 1. Units of length, mass and time Metric Prefixes Density and its units The Scientific Method. Main Concepts for 2 & 3. Speed vs. Velocity Acceleration - PowerPoint PPT Presentation

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Page 1: HNRS 227 Lecture #2 Chapters 2 and 3

HNRS 227 Lecture #2Chapters 2 and 3

Motion and Patterns of Motionpresented by Prof. Geller29 August 2002

Page 2: HNRS 227 Lecture #2 Chapters 2 and 3

Recall from Chapter 1Units of length, mass and timeMetric PrefixesDensity and its unitsThe Scientific Method

Page 3: HNRS 227 Lecture #2 Chapters 2 and 3

Main Concepts for 2 & 3Speed vs. VelocityAccelerationForceFalling ObjectsNewton’s Laws of MotionMomentumCircular MotionUniversal Law of Gravity

Page 4: HNRS 227 Lecture #2 Chapters 2 and 3

Speed and VelocitySpeed

distance traveled in a unit of time a scalar quantity

Velocity speed and direction a vector quantity

Page 5: HNRS 227 Lecture #2 Chapters 2 and 3

Questions for ThoughtWhat is the difference between speed and

velocity?

Speed is a scalar, and velocity is a vector. Speed is the magnitude of the velocity vector.

Page 6: HNRS 227 Lecture #2 Chapters 2 and 3

Questions for ThoughtWhat is acceleration?

Acceleration is the ratio of the change in velocity per change in time.

Page 7: HNRS 227 Lecture #2 Chapters 2 and 3

Questions for ThoughtAn insect inside a bus flies from the back

toward the front at 5.0 miles/hour. The bus is moving in a straight line at 50 miles/hour. What is the speed of the insect?

The speed of the insect relative to the ground is the 50.0 mi/hr of the bus plus the 5.0 mi/hr of the insect relative to the bus for a total of 55 mi/hr. Relative to the bus alone the speed of the insect is 5.0 mi/hr.

Page 8: HNRS 227 Lecture #2 Chapters 2 and 3

ForceDefinition of force

something that causes a change in the motion of an objecta push or pullan electric, magnetic, gravitational effecta vector quantity

Net force - Resultant Force

Page 9: HNRS 227 Lecture #2 Chapters 2 and 3

InertiaDefining Inertia

tendency of an object to remain in its current state of motionthe more massive the more inertiathink of stopping a car vs. truck

Page 10: HNRS 227 Lecture #2 Chapters 2 and 3

Acceleration Due to GravityDirection of acceleration due to gravity

directed to center of EarthThink: scalar or vector?

a vector quantity

Why?

has magnitude and direction

Page 11: HNRS 227 Lecture #2 Chapters 2 and 3

Generalized MotionMotion can be viewed as a

combination of movements vertical component

typically gravitational acceleration horizontal component

some force from muscle, gunpowder, etc.

Page 12: HNRS 227 Lecture #2 Chapters 2 and 3

Question for ThoughtWhat happens to the velocity and acceleration

of an object in free fall?

Assuming a short free fall distance near the earth’s surface, the velocity increases downward as the acceleration remains constant.

Page 13: HNRS 227 Lecture #2 Chapters 2 and 3

Question for ThoughtIn the equation d=1/2*a*t2, if a is 9.8 meters

per second per second and t is in seconds, what is the unit of d?

Meters.

Page 14: HNRS 227 Lecture #2 Chapters 2 and 3

Question for ThoughtWhat is inertia?

Inertia is the property of matter that an object will remain in unchanging motion or at rest in the absence of an unbalanced force.

Page 15: HNRS 227 Lecture #2 Chapters 2 and 3

Question for ThoughtWhere does the unit s2 (or concept of “square

second”) come from?

Acceleration is change in velocity per change in time, with units of (m/s)/s. When the fraction is simplified, you get meters per second squared. The “seconds squared” indicates that something that changes in time is changing in time, that is, the ratio of change in distance per unit of time is changing in time.

Page 16: HNRS 227 Lecture #2 Chapters 2 and 3

Question for ThoughtNeglecting air resistance, what are the forces

acting on a bullet that has left the barrel of a rifle?

After it leaves the rifle barrel, the force of gravity acting straight down is the only force acting on the bullet.

Page 17: HNRS 227 Lecture #2 Chapters 2 and 3

Question for ThoughtHow does the force of gravity on a ball change

as a ball is thrown straight up in the air?

The force of gravity on the ball remains constant because the force of gravity is independent of the motion of the object near the surface of the earth.

Page 18: HNRS 227 Lecture #2 Chapters 2 and 3

Question B23 (p.46)An object falls from a bridge and hits

the water 2.5 seconds later. A) With what velocity did it strike the

water? B) What is the average velocity during

the fall? C) How high is the bridge?

Page 19: HNRS 227 Lecture #2 Chapters 2 and 3

Question B23 (p.46)23. These three questions are easily answered by using the three sets of relationships, or

equations, that were presented in this chapter:

(a) vf atvi

vf 9.8ms2

2.50s 0

ms

9.82.50 ms2 s

25m/s

(b) v vf vi

2

25m/s02

13ms

(c) v dt

d v t

d 13ms

2.50s

132.50 mss

33m

Page 20: HNRS 227 Lecture #2 Chapters 2 and 3

Newton’s Laws of MotionNewton’s First Law of Motion

body at rest tends to stay at rest and body in uniform motion will stay in straight line uniform motion unless acted upon by an outside force

Newton’s Second Law of Motion the acceleration of a body is

proportional to the force being applied•F = m*a

Page 21: HNRS 227 Lecture #2 Chapters 2 and 3

Newton’s Laws of MotionNewton’s Third Law of Motion

for every force there is an equal and opposite force (action and reaction)

Page 22: HNRS 227 Lecture #2 Chapters 2 and 3

Question for ThoughtHow can there ever be an unbalanced

force on an object if every action has an equal and opposite reaction?

The action and reaction forces are between two objects that are interacting. An unbalanced force occurs on a single object as the result of one or more interactions with other objects.

Page 23: HNRS 227 Lecture #2 Chapters 2 and 3

Question B 2 (page 65)What force would an asphalt road

have to be to give a 6,000 kilogram truck in order to accelerate it at 2.2 meters per second per second?

Page 24: HNRS 227 Lecture #2 Chapters 2 and 3

Question B 2 (page 65)

2 .F = m a

F 6 , 000 kg 2 . 2ms 2 1 . 3 10 4 N

Page 25: HNRS 227 Lecture #2 Chapters 2 and 3

MomentumBy definition momentum is the product

of mass and velocityConservation of momentum total momentum of a closed system remains constant

Page 26: HNRS 227 Lecture #2 Chapters 2 and 3

Question for ThoughtIs it possible for a small car to have the

same momentum as a large truck? Explain.

Yes, the small car would have to be moving with a much higher velocity, but it can have the same momentum since momentum is mass times velocity.

Page 27: HNRS 227 Lecture #2 Chapters 2 and 3

Question B 15 (p. 66)A 30.0 kilogram shell is fired from a

2,000 kilogram cannon with a velocity of 500 meters per second. What will be the velocity of the cannon?

Page 28: HNRS 227 Lecture #2 Chapters 2 and 3

B #15 page 66

15. Listing the known and unknown quantities:

Shell m = 30.0 kg Cannon m = 2,000 kgShell v = 500 m/s Cannon v = ? m/s

This is a conservation of momentum question, where the shell and cannon can be considered as a system of interacting objects:

Shell momentum = - Cannon momentummv s = - mv c

mv s - mv c = 0

30.0 kg 500 ms

2,000 kg vc 0

15,000 kg ms

2,000 kgvc 0

15,000 kgms

2,000 kgvc

vc 15,000 kg m

s2,000 kg

15,0002,000

kg1

1

kg

ms

7.5 ms

The cannon recoils with a velocity of 7.5 m/s.

Page 29: HNRS 227 Lecture #2 Chapters 2 and 3

Circular MotionCentripetal Force

usually gravity, but can be any force (such as the pull of a string) that forces an object into circular motion

Centrifugal Force a fictitious force, an apparent outward force

felt by an object in circular motionAcceleration in circular motion is a =

v2 / r therefore in circular motion F = mv2 / r

Page 30: HNRS 227 Lecture #2 Chapters 2 and 3

Question B 28 (page 66)What is the maximum speed at which

a 1000 kilogram car can move around a curve with a radius of 30.0 meters if the tires provide a maximum frictional force of 2700 Newtons? (1 Newton is a unit of force needed to accelerate a 1 kilogram mass 1 meter per second per second.)

Page 31: HNRS 227 Lecture #2 Chapters 2 and 3

Question B 28 (page 66)28.

F ma and a v2

r F m v2

r

v rF

m

v rFm

30.0m 2700.0N

1,000.0kg

9.00ms

or 32.4kmhr

Page 32: HNRS 227 Lecture #2 Chapters 2 and 3

Universal Law of GravityNewton’s Universal Law of

Gravitational Attraction every object is attracted to every other

object the force is proportional to masses and

inversely proportional to the distance squared

–F = (G*m*M) / r2

Page 33: HNRS 227 Lecture #2 Chapters 2 and 3

A Problem of Very Little AttractionWhat is the gravitational force

between two 100 kilogram people separated by 1 meter?

Page 34: HNRS 227 Lecture #2 Chapters 2 and 3

Really just a little

Use the formula for the force of gravity:F = G*m*M / r2

where G = 6.67 x 10-11 Nm2/kg2

and m = 100 kgand M = 100 kgand r = 1=======================ThenF = 6.67 x 10-11 Nm2/kg2 *100 kg*100 kg / (1 meter) 2

F = 6.67 x 10-7 N