holomorphic solutions of some functional equations iii
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Holomorphic solutions of some functional equations IIIMiami Suzuki aa Department of Mathematics, Faculty of Informatics , Teikyo Heisei Unisersity , Uruido,Ichihara-shi, 290-0193, JapanPublished online: 29 Mar 2007.
To cite this article: Miami Suzuki (2000) Holomorphic solutions of some functional equations III, Journal of DifferenceEquations and Applications, 6:4, 369-386, DOI: 10.1080/10236190008808236
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Pnnted ir. Malaysta.
Holornorphic Solutions of Some Functional Equations Ill
Department of Mathematics, Faculty of Informatics, Teikyo Heisei University, Otani2289-23, Uruido, Ichihara-shi, Chiba, 290-0193, Japan
(Received I February 1999; In final form 17 June 7999)
We will concern with existence of solution $(x) of a functional equation $(X(x, $ ( I ) ) ) = Y(x, qixj) . where X(x , y) = i x -+ 2 p m n ~ m y z , Y(x, yj = px i Xmtn 2 2 g m ~ x n ' y n ,
i- s - important fioril i h ~ viewpin: of simultaneous systems ~f difTerence ~yuatims. The cases / X / > 1 5: O < / X / / ! have becn treated in a former paper. Hence we will consider here the case j X / = i. Further we wiii consider the cast that X = 1, / p 1 = 1 ( p # 1). The case X = p = 1 will be dealt within another paper.
Keywords: Difference equation; Functional equation; Analytic solution
1980 Mathematzcr Subject Clarrlficatlonr 39A-10. 39B-12. 39B-22
1 INTRODUCTION
We will consider here a simultaneous system of difference equations
x(s + 1 ) = X ( X ( S ) , Y ( S ) ) , Y ( S + 1 ) = Y ( x ( s ) , Y ( s ) ) , ( 1 . 1 )
where
* Tel.: 81-436-74-6139. Fax: 81-436-74-7872. E-mail: [email protected].
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For single difference equation,
it is knmm that there exists en5re sduticn x(s) with
We wish to consider the corresponding problems for system ( 7 .I) . Thus, we will seek a pair of entire solutions !x(s), y(s)) such that
(xis + rj, y(s + r j j - - jO,O) as r ---i -m (P E Rj, (1.3)
uniformly for s E K, where IK is any compact subset of the s-plane. Single difference equations of the first order are studied in some
extent [7], So, it would be worthwhile considering to reduce the system (1.1) to some single first order equation.
S??pp~se there is. a fiincti~n $ (x ) , h~!om~rphic in 1x1 : 6, which satisfies
for a 6 > 0. Let x(s) be a solution of
with x(s i- r) -+ 0 as r -+ -m. Put y(s) = $(x(s)), then (x(s), y(s)), is a solution of (1.1) with (1.3). Hence, solving the system (1.1) is reduced to solving the single Eq. (1.5). Therefore the functional Eq. (1.4) is of significance from the viewpoint of systems of difference equations (1.1).
We proved in [5] that, when I X I # 1, (1.4) admits solution $(x) which is holomorphic at x = 0. In this note, we will consider the case where I X I = 1. D
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Note the following fact: Put
in (1. I) , then we obtain
u is + 1 ) = U(u(s ) , v ( s ) ) , v(s + 1 ) = V(u(s ) , v(s)), (1.6)
with
a"2O - .-,, I \ Q ~ O = - ~ ~ ~ ~ ( / L - A ~ ) , _h
A l l B11 = bpi1 + - X ( 1 a - p ) , Q l l = aq11 +-p(1 b - A), (1-7)
b2 '402 2 B02 Po2 = _Po2 a + c4 (A - p ), Q02 = bgo2 + - b p(1 - p) .
Now we suppose 1 X / = 1 in (1.2). As in [5] , we assume that
Xk # p for any k E N, (1.8)
and
920 # 0.
Note that, under the assumption (1.8), the condition (1.9) may be sup- posed to hold without losing generality, as seen from (1.7). By these assumptions, non-zero formal solution $(x ) to (1.4) is determined uniquely, in the form
whether
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372 M. SUZUKI
Although the formal solution $(x) the form (1.10) gives holo- morphic solution for (1.4) when I X f 1 we will show here that, when X=ei"" with irrational a, there is no holomorphic solution 4(x) of (1.4) for most cases, if (1.1) admits solutions (x(s'),y(s)) with the condition (1.3) ("most cases" means the cases represented by the Siegel condition (I .I 1) below).
THEOREM 1 Suppose, in (1.2), that X = eiN". Further suppose that ct is irrational and satisfies the Siegel condition (1.1 1)
Suppose there exist holomorphic solutions (x(s), y(s)) with the condition (1.3). Then. for (1.41, lhere exists izo solution $(x) which is holomorphic at x = O .
Hence, if (I .4) admits a holomorphic solutions $(XI, then there is no solution, wiih (1.3),jbr (1.1).
When / X 1 = : and (1.4) does not admit the solution, we may exchange the role of x, y if 1 p 1 # 1. In fact, we may consider the equation for unknown 4(x),
instead of (1.4). Note that (1.12) may possess a solution, even if (1.4) does not.
It remains to consider the case that / X / = / p 1 = I . In connection with Theorem 1, we suppose X = e'(~'~)", p, q E Z.
Writing
we get by (1.4)
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HOLOMOP2HIC SOLUTIONS 173
Hence we can reduce the problem to the case X = I by considering x ~ ~ ( x , y) and ~ ~ ~ / v (A, .s) <A* A~.b,.~!, V/W ,,) V(V A k---,.y,l. ,A
We will deal in this note with the case X = I # p. The case X = p = 1 is considered in [6].
Wher! X = !, (1.4) does m t admit holomoqhic solution $!x)
in general. We consider the following example with 1 p # 1, for simplicity.
we obtain a, > 0 (n 2 2), and
and
Hence the formal power series is not convergent.
Therefore we seek a solution of (1.4) which is holomorphic, not at x = 0 but in an angular domain (1.13) below, and is asymptotically expanded to the formai solution (1.10) there. Put, for some K > 0 and S > O ,
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Now we state our results. First note that, if
in (1 3, then by (1.7) we can take a: b such that
So we may suppose that
THEOREM 2 Suppose X = 1 and 1 p 1 = 1 , p f 1 in (1 2). Further suppose that (1.15). Then we can determine a formal solution to (1.4) in the form of Eq. (1.10):
fci~ f i ; ~ ; ~ L 0 < K 5 ~ 1 2 , EX are 6 > 0 aid 6 d i i t i c i ~ $(XI .4) such that @jx) is holornorphic in D(n, 6) and is expanded asymptotically in the same domain as
From the viewpoint of difference equations, by Theorem 2, it remains to seek solutions x(s) for (1.5) such that x(s) E D(n, 6) for s
large.
2 PROOF OF THEOREM 1
Suppose that there exists a function $(x ) satisfying (1.4). Put
g ( x ) = X(x , $ ( x ) ) = Xx + C pm.xM($(x))", 1x1 < 6. m+n>2
Since X satisfies the condition (1.1 I), by [3] the equation
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HCLOMOLDM!C SOLUTIONS
admits a solution
We can choose numbers p > 0 and T > 0 SO that 8 ( z ) : O(z) is univalent in is/ < p and { 1x1 < r j c O({ / z i < p j ) . Let <x(sj,y(sj) be a soimion of (I. i j which satisfies ( l .3 ) . Let qo be a iiumbei a such that
Then, for any s E L(qO; a), there is a z, Iz 1 < p, such that
x(s)=@(z) , Z = Q - ' [ ~ ( s ) ] .
Put
Thus
and
X(S) = Q(7r(s)XS).
By (2.1) and @2), T(S) is bounded from above and below. Hence if s = E + iqO, < -+ -00, then I z I = I ~ ( s ) 1 . 1 e-a"70 1 is also bounded from above and below. Hence Q(.rr(s)Xs) cannot tend to 0 as Re[s] -+ m, which contradicts (1.3).
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376 M. SUZUKI
3 PROOF OF THEOREM 2
We can obtain a formal solution to (1.4) in the form (].lo), since A"= 1 fp.
Put
Since f(0, 0,O) = 0, f,(O, 0,O) = -p # 0, we obtain by the implicit function theorem that there is a function H(x, u) such that
which is ~o!oI?IoT"~~' Y--" i~ a C!OSP~ domain ] Y I 5 c i , f 2 5 EZ fer seine EI, i2 > 0. The raiige of H(x, u) contains a disc ly 5 E,. Put E = min(q, E Z , E ~ ) . Let +(x) satisfy (1.4): +(X(x, $(x))) = Y(x, $(x)), on a domain contained in 1x1 < E . If I$(x)I < r there, we obtain by (3.1) that
Conversely, if $(x) satisfies (3.2), it also satisfies (1.4). Hence it suffices to seek solutions $(x) of (3.2). We may suppose E > 0 is so small that there is a constant Go > 0 such that, noting that, JpJ = 1,
for 1x1 I E, J u J I E .
Let n (0 < n < 7r12) and N ( N E N) such that
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be fixed. Let g N ( x ) = be the truncation of the formal ~01utio11 jl . lOj . There is a constant GN siich that, for / x I < E ,
For a 5 > 0, consider D(K, 5) in (1.13). Take K > 0 and put
3 = 3 ( N , K, 6)
= ( @ ( x ) ; $ ( x ) 1s hoiomorphic and satisfies
I+(.)/ i ~ 1 x 1 " in D ( K , &)I, (3.5)
in which Kis determined by (3.10) below, if N is chosen. Take 5 < 1 so small that
We will show that, if K is fixed by @.If ) and 6 is determined sufficiently small as shown below, T [$I E 3.
Put v = X(x, gN(x ) + +(x)) = ~ ( 1 +pZOx + . . .) for a Q(x) E F , where by (3.61,
Then for x E D (K, 4,
Futher, if 6 is sufficiently small, we have 1 x 112 < I vl < I x 1 by the assumption pzO < 0 (Fig. 1).
Thus, if x E D(n, S), then we have v E D(n, 6) and $(X(x, gN(x) + $(x))) is well defined. Hence we can define the following map T : $ € F + T[$]as
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FIGURE 1
with v! = X(x, gN(x) + d(x)), that is?
with v2 = x(x, gN(x)j . Since gw(n) is the truncated formal solution, we get
for a constant K1, which is determined if N is fixed. We fix K so large that
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HOLOMOPuDR!C SOLUTIONS
Since, if 6, > 0 is small, we have for ! u ( , 1x1, 1 ~ 3 1 5 S1,
We take F so that
then we get for x E D(n, 6):
Further (noting that I p I = 1)
and, for u=gN(v1) + t+(vl) by (3.3)
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380 M. SUZUKI
hence
Thus we have, for 1 u: I = IgN(vl) 1,
Let S be taken so that
(GN+ K)S < 1 . (3.12)
Then, by (3.4) when Go < 1, we have
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and when Go > I , we have
Tkzs we hsve, fcr either csse?
and we have that T[I$] E F. i is obviousiy continuous and F is convex. Further F is d nuniid
f'amdy By Schauder's fixed point tineorem in [2,4]. we know the existence of a fixed pomts $fx) E F for the map T. That IS, we have, if we write w(xj = gN(x ) + qj(xj,
Next we will show that the fixed point 4 is unique for each N. In fact, suppose there would be q5j(x) E 3, j= 1,2 such that, writing vj = vj(x) = X(x, gN(xj + (Pi(x)), j = 1,2 , then
vi - v2 = (41 ( x ) - ~ Z ( X ) ) ( P I I X + higher terms)
= FI ( x ) (dl ( x ) - d2 ( x ) ) ,
g d v ~ ) - gN(v2)
= (41 ( x ) - 42(x))(2pll . a2x2 + higher terms), (3.14)
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M. SUZUKI
we get
Put Dl = D(rc/2,6'), (6' = (1 + sin(n12))-'6) and C= {(I I € - X I =
1x1 sin(rc12)) for x E Dl . Then C c D(K, 6) and by Cauchy integral [I] we see that
So that
Thus if N > 3,
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we obtain by (3.14)-(3.16) for x E D1\O:
for sufficiently small x. Since v l (x ) E D ( K , 6) for x E D ( K , S), we have
where v Y 1 ( x ) = V I ( V ~ ( X ) ) , v ~ ( x ) = X . Hence
Since Ih(x)l = j p+q l lx+0(x2)1 L 1 - lqllI 1x1 + 10(x2)I, we have I h(x) I 1 1 - blx 1 , with 3 = ] qll I $ 1 . for sufficiently smali x, Thus by (3.17) we get
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384 M. SUZUKI
Hence from (3.19) and (3.20) we get
Fwther, we have
if we take N so iarge that - dl - b > I and jx j is sufficiently smali, we get
since Ivf+'(x)l 5 I v ; ( x ) I 5 1x1 by (3.7). k Put p ( t ) = t ( l -d2t) , r ~ = r = 1x1, and rk=p ( r )=p(rk- ] ) for k > 1 .
By induction we have Iv,k(x) 1 5 rk-1. Since rk < rk-], we have some constani c (2 0) such that rk-+ c (as k -+ CO). And we see that c = c(1 - dzc). By d2 # 0, we have c = 0, i.e.,
rm = p m ( r ) -+ 0 (as m -+ 00).
Thus by (3.19)
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Thus
and c;il jx) = d2(x) if J X 1 is small. Hence we have the ilniqueness of the fixed point far the map T : & i (x) = C $ ~ ( X ) f ~ r x E D ( I E , ~ ) f a a 5xed N. We denote it by 4'"?(xj.
Let N' > N. Consider the families 3(N1), F (N) with constants IC(N1), S(N'); IC(N), S(N), respectively. Put 6=min(6(N1), 6(N)). Put $(x) = c$[~'](x) + ~N'(X) - g ,~(x) , then
where w = g,+) + $lN'](x), hence by the uniqueness we have
Therefore $IN1(x) =g&) + q5[N1(~) does not depend on N, which we denote by $(x). Obviously +(x) is a solution of (11.4) and
for large N, which shows that $(x) is asymptotically expanded in Db, 4.
Hence the proof is completed.
References
[I] L.V. Ahlfors, Complex Analysis (Third edition), McGraw-Hill Kogakusha, Ltd., Tokyo, Japan, 1979.
121 T. Kimura, Ordinary Differential Equation, Kyouritu shuppan Press, 1974. [3] C.L. Siegel, Iteration of analytic functions, Ann. Math. 43 (19421, 607-612.
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386 M. SUZUKI
D.R. Smart, Fixed Point Theorems, Cambridge tTniv. Piess, 1971. M . Suzuki, Holomorphic solutions of some functional equations, Nihonkai Marhr- matical Journal 5 (1994); 109- 1 14.
161 M. Suzuki, Holomorphic solutions of some functional equations 11, SEAMS Bull. Math. (to appear).
[q N. Yanagihara, Meromorphic solutions of some difference equations, Funkcial. Eqv. 23 (1980), 309-326.
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