home elevator general data 20100705161018

8/3/2019 Home Elevator General Data 20100705161018

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Home Elevator

General Data


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HOME ELEVATOR

INSTALLATION DATA

Roping 1:1 / 2:1

Pulley (mm) 100

Speed (m/s) 0,15

Rope diameter (mm) 4

N of ropes 3

Rope weight/m (kg) 0,069Height no comp. chain (m) 9

Total rope weight(kg) 1,9

Braking torque (Nm) 55,1

Shaft efficiency(%) 80

Diverted pulley efficiency (%) 100

N of diverted pulleys 0

Nom. torque inst. (Nm) 64,9

Mec. Power(kW) 0,4

Model

MECHANICAL DATA

Nom. torque motor (Nm) 200

Max. torque motor(Nm) 280

Duty cycle (%) 50

Starts/hour 180

Static load (kg) 2000

Nominal speed (rpm) 60

Max. speed (rpm) 225Machine weight (Kg) 78

ELECTRICAL DATA

Nominal consuption (A) 2,5Max. Consumption (A) 10,8

Rated Voltage (V) 165

Nominal power(kW) 1,4

Herzs 6

Brake voltage (Vdc) 210Poles 12

ge75-100-225Home Elevator

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CALCULATION OF THE NUMBER OF THE ROPES

1. INTRODUCTION

The objective of this project is to calculate the number of traction ropes that are

required for the motor Home Elevator. This motor is designed using the machinery

directive U.N.E.-58-120 regulation (cranes and lifting devices), instead of the EN-81

regulation (Safety rules for the construction and installation of lifts).

2. CALCULATIONS

CLASSIFICATION TYPE

To make the rope calculation, first of all we have to classify the machine and see at

which group belongs to. These classification types are defined in the FEM 9.511

regulation Mechanisms Classification. To find the group, first we have to define thefollowing factors.

a- Duty Load.

b- Average operating time per working day.

a- Duty load

The duty load is evaluated in base on 4 types of service conditions, with the following

characteristics:

A. Light

Maximum Load: occasionally

Moderate Load: regularly

Light Load: Small

B. Medium

Maximum Load: frequently

Moderate Load: Regularly

Light Load: Medium

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C. Heavy

Maximum Load: Frequently

Medium Load: Regularly

Light Load: Big

D. Very heavy

Maximum Load: Regularly

Light Load: Very big

Taking into account the service conditions of the home elevator it is considered as

a Heavy duty machine.

b- Average operating time per working day

At it is exposed in the FEM 9.511 regulation, the average working time (t) is

calculated as follows:

60*

***2

V

TNHt=

Where:

H= Average lifting height

N= Number of cycles per hour (a cycle is a movement of up and down travel)

T= working (h) time

V= elevation speed (m/min)

In the home elevator case is considered an installation with the data:

H= 12m

N= 16hours/24cycles=0,67

T=16 h

V= 0.15m/s = 9m/min

So, the average operating time (t) is = 0.47

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CLASSIFICATION TYPE

We know that the Duty Load is Heavy and the average operating time =0.47, so,

from the following table we deduce the classification type of the Home Elevator

Average operating time(hours per day)

Duty Load0.5 1 2 4 8 16

LIGTH M31Bm M41Am M52m M63m

MEDIUMM31Bm

M41Am

M52m

M63m

M74m

HEAVYM31Bm

M41Am

M52m

M63m

M74m

VERY HEAVYM41Am

M52m

M63m

M74m

As per the table, the machine is in the group M4 1Am

ROPE TENSION

The rope tension is going to be calculated for an installation with these specifications:

Load (Q): 375 kg

Car Weight (P): 450kg

Roping: 2:1

Counterweight Balance: 50%

(Tmax) = (P+Q)/2=412,5 kg. Applying a safety factor of 1.25, 515,63 kg or

5058,28 N.

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MINIMUM DIAMETER ROPE CALCULATION

The calculation of the rope diameter is based on the UNE 58-120-91 regulation and it

says: SCd =

Where:

d: minimum rope diameter (mm)

C: rope selection factor [ N

mm

]S: Maximum tension of the rope [N]

As we know per the FEM 9.511 regulation, the Home Elevator is classified in the M4

1Am Group and from the table 1 of the UNE 58-120-91 regulation we know that the

value of C for an elevation mechanism M.4 type is = 0,095N

mm.

Knowing the value of C and once we calculate the maximum tension (Tmax=14347,2 N),

replacing the values in the equation we obtain that the minimum diameter rope is:

28,058.5095,0=d

dmin= 6,76 mm drope= 4 mm

smin= 35,85 mm2 srope= 12,57 mm

2

In the case that we use 4mm2 ropes, the number of ropes that are needed:

57,12

85,35=n

n = 2,85

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MINIMUM BREAKING LOAD CALCULATION

The minimum breaking load calculation it is done with the following calculation as it is

exposed in the UNE 58-120-91 regulation:

pZSF =0

Where:

S: Minimum tension of the rope [N]

Zp: Minimum ratio of practical use.

To calculate the maximum tension in this section, the maximum tension calculated

before is going to be divided by the number of ropes, so:

kNNS 69,109,686.13

5.058,28===

The value of Zp it is specified in the Table 1 of the UNE 58-120-91 regulation, that says

that for a determined elevating mechanism of the group M4 1 Am, the Zp is 4.0.

So, resolving the following equation we obtain that the minimum breaking load it has to

be bigger than:

0,469,10 =F

F0 6,74kN

The real minimum braking load of 4 mm rope cable is: 12,6kN

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MINIMUM PULLEY DIAMETER CALCULATION

To calculate the size of the pulley we use the Table 2 of the UNE58-120-91/1. As per

the table the pulley diameter must be 18 times bigger than the cable diameter.

4X18=72mm

home elevator general data 20100705161018

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