honors topics. recall that some equations have more than one variable. you often need to solve for...
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![Page 1: Honors Topics. Recall that some equations have more than one variable. You often need to solve for just one of them. We will now look at some more complex](https://reader036.vdocuments.net/reader036/viewer/2022062422/56649e695503460f94b66136/html5/thumbnails/1.jpg)
Honors Topics
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Recall that some equations have more than one variable. You often need to solve for just one of them. We will now look at some more complex “literal equations” for which you must FACTOR or SIMPLIFY to solve for one variable.
EXAMPLE 1: Factor EXAMPLE 2: Simplify Solve for a. Solve a-2(b+x)=3a-4(x-b) for
x.*Factor *Distribute a-2b-2x=3a-4x+4b *Solve -2x = 2a +6b*Divide x = -a – 3b
2ax ay z ( ) 2
2
a x y z
za
x y
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Solve for the given variable by simplifying and/or factoring.
EXAMPLE 3: EXAMPLE 4:
Solve for k. Solve for x.
3( )
3 3
3 3
( 3 ) 3
3
3
ax c bx d
ax c bx d
ax bx c d
x a b c d
c dx
a b
3ax c
bx d
5 3 4 1x k kx k
5 3 2
(5 ) 3 2
3 2
5
x kx k
x k k
kx
k
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Recall that there are different forms for writing the equation of a line. Two forms that we studied are standard form Ax + By = C and slope-intercept form y = mx + b.
Point-slope form is used given the slope, m, of a line and a given point on the line.
1 1( )y y m x x 1 1( , )x y
Slope
Point
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Write an equation for each line.
EXAMPLE 1: EXAMPLE 2: Slope and contains Perpendicular to x – 4y = 8 point (-7, 8) through point (½, -½) slope of line
perpendicular to given line is m = -4
Use m= -4 , point (½,-½)
3
2
38 ( 7)
23
8 723 21
82 2
3 5
2 2
y x
y x
y x
y x
4 8
12
4
y x
y x
1 142 21 4 22
34 2
y x
y x
y x
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Let’s recall that the absolute value of a number is its distance from 0.
|17| = 17 |0| = 0 |-6| = 6
|positive| = same |zero| = same |negative| =opposite
The absolute value of a number that is greater than or equal to zero is equal to the same number
|positive or 0| = same
The absolute value of a number that is less than zero is equal to the opposite number
|negative| = opposite
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Simplify each absolute value expression.|x| if x < 0= -x
|xy| if x<0 and y<0 =xy
|x-y| if x<0 and y>0=-(x-y)=-x+y
Since x is negative, when it comes out of the absolute value sign, it is the opposite of the x value. |negative| = opposite
Since both x and y are negative, the product is positive. When it comes out of the absolute value sign, it is same value. |positive| = same
Since x is negative and y is positive, the difference (neg-pos) is negative. When it comes out of the absolute value sign, it is opposite value. |negative| = opposite