hot water အပိုင္း

2
(၂) ° - COP of electric boiler = 3.75 - () (annual electricity consumption) () (annual cost of electricity) days (Annual hot water output) = 4500 kWh/day x 365 days = 1,642,500 kWh () COP = Energy output/Energy input

Upload: grannypapa

Post on 26-Sep-2015

213 views

Category:

Documents


0 download

DESCRIPTION

Hot_Water

TRANSCRIPT

  • ()

    - COP of electric boiler = 3.75 -

    ( ) (annual electricity consumption) ( ) (annual cost of electricity)

    days (Annual hot water output) = 4500 kWh/day x 365 days = 1,642,500 kWh

    ( )

    COP = Energy output/Energy input

  • (annual electricity consumption) = Annual hot water output / COP = 1,642,500 / 3.75 = 438,000 kWh

    ( ) ( ) ( ) (diesel price) x $5 = $ 2,190,000

    Note : COP = Coefficient of performance