how do you do? john rutherford, dumfries. or, are you any good doc? inputs qualifications courses...
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![Page 1: How do you do? John Rutherford, Dumfries. Or, are you any good doc? Inputs Qualifications Courses Staffing Equipment Protocols Resuscitation training](https://reader036.vdocuments.net/reader036/viewer/2022083005/56649f165503460f94c2cece/html5/thumbnails/1.jpg)
How do you do?
John Rutherford, Dumfries
![Page 2: How do you do? John Rutherford, Dumfries. Or, are you any good doc? Inputs Qualifications Courses Staffing Equipment Protocols Resuscitation training](https://reader036.vdocuments.net/reader036/viewer/2022083005/56649f165503460f94c2cece/html5/thumbnails/2.jpg)
Or, are you any good doc?
Inputs• Qualifications• Courses• Staffing• Equipment• Protocols• Resuscitation training
Outcomes• Mortality• Complications• Logbooks• Success at techniques• Satisfaction surveys
![Page 3: How do you do? John Rutherford, Dumfries. Or, are you any good doc? Inputs Qualifications Courses Staffing Equipment Protocols Resuscitation training](https://reader036.vdocuments.net/reader036/viewer/2022083005/56649f165503460f94c2cece/html5/thumbnails/3.jpg)
Success at techniques
• You can record a yes/no for some events
• Intubated or unable, caudal inserted or not
• This can give a percentage result
• We cannot be perfect
• How much failure is acceptable?
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Cusum
• Statistical technique
• Move along graph to right each time you do a technique
• Move up if fail
• Move down if succeed
• Upper and lower limits depend on acceptable and unacceptable failure rates
![Page 5: How do you do? John Rutherford, Dumfries. Or, are you any good doc? Inputs Qualifications Courses Staffing Equipment Protocols Resuscitation training](https://reader036.vdocuments.net/reader036/viewer/2022083005/56649f165503460f94c2cece/html5/thumbnails/5.jpg)
The technical bits…
• p0 acceptable failure rate
• p1 unacceptable failure rate
type 1 error type 2 error
• ln, loge
• h0= -b/(P+Q)• H1= -a/(P+Q)
• a = ln[(1-)/]• b = ln[(1- )/ ]
• P = ln[p1/p0]
• Q = ln[(1-p0)/(1-p1)]
• s = Q/(P+Q)
![Page 6: How do you do? John Rutherford, Dumfries. Or, are you any good doc? Inputs Qualifications Courses Staffing Equipment Protocols Resuscitation training](https://reader036.vdocuments.net/reader036/viewer/2022083005/56649f165503460f94c2cece/html5/thumbnails/6.jpg)
a 2.944439 attempts success?b 2.944439 1 yP -0.69315 2 yQ 0.117783 3 yh0 5.117523 lower boundry limit 4 yh1 -5.11752 upper boundry limit 5 ys -0.20471 6 y
7 yalpha 0.05 type 1 error 8 ybeta 0.05 type 2 error 9 yp0 0.2 unacceptable failure rate 10 yp1 0.1 acceptable failure rate 11 y
12 y1-s 1.20471 13 yNoofObs 14 y
21 15 y16 y17 y18 y19 y cusum lower boundry limitupper boundry limitattempts20 y -4.09421 5.117523 -5.11752 2021 y22
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-2
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lower boundry limit upper boundry limit cusum