if f is a scalar function, then 4-1 gradient of a scalar but grad ; hence an alternative way to...
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If f is a scalar function, then 1 2 3, ,ξ ξ ξ
4-1 gradient of a scalar
But grad ; hence
An alternative way to conclude that is a vector is to note
that is a scalar for all recall that is a vector ,and
invoke the appropriate quotient law.
j( )
ji j i j if f x f x
x x
e
ξ ξ ξ
j jff fx
e
( )ii
ff
ε
ξ
if
j
jf
df d
jd
4 、 tensor calculus
is the convariant component of if
ξthi f
iif
f
ε
jd
4-2 Derivative of a vector ; christoffel` symbol; covariant derivative
Consider the partial derivative of a vector F. with F = ,
we have
write
the contravriant component of the derivative with respect to of the base vector. Note that
i iij j j
iFF
εFε
ξ ξ ξ
j
Fξ
kiij kj
εε
ξ
2 jij j ii
x
εε
ξξ ξ ξ
iFiε
jthk
christoffel system of the second kind
k kij ji
We can now write
( )k iki ij j
iFF
Fε
ξ ξIntroduce the notation
,ij ij
F
εF
ξThis means that ----- called the convariant derivative of --- is definded as the contravariant component of the vector comparing (4-2-1) and (4-2-2) then gives us the formula
,iFj
iFthi j
F
,
ii k ij kjj
FF F
ξ
,( )j jij ij
d d F d
FF ξ ξ ε
ξ
Although is not necessarily a tensor, is one , foriF
j
ξijF,
(4-2-1)
(4-2-2)
A direct calculation of is more instructive; with F= ,we have
Now , whence
The covariant derivative of writing as , is defined as the covariant component of ; hence
jiF ,
kjkiji FgF ,,
iFthi
iFiε
,i( )
kj i
i j kj j j
FF F
F εε ε
ξ ξ ξk ki i
ε ε
( )k
k k l kii ij l ijj j
εεε ε ε ε
kk iijj
εε
,ki
i j k ijj
FF F
And therefore
consequently
And while this be the same as (4-2-3) it shows the explicit addition to needed to provide the covariant derivative of
jF
,Fi j
(4-2-3)
iF
ij
F
Other notations are common for convariant derivatiives; they are, in approximate order of popularity
| ;F F D F Fi j i j j i j i
Although is not a third-order tensor, the superscript can nevertheless be lowered by means of the operation
kij
[ , ]k k ikp ij kp pj j
ig ij p g
ε εε ε
ξ ξand the resultant quantity , denoted by , is the Christoffel symbol of the first kind. The following relations are easily verified
],[ pij
2
[ , ]ji
k kj i k jix x
ij k
εεε ε
ξ ξξ ξ ξ
( ) [ , ] [ , ]ji
i j j ik k k
gij
ik j jk ik
εεε ε ε ε
ξ ξ ξξ
1[ , ] { }
2
g gg jk ijp ikg ij kkp ij j i k
(4-2-4)
1{ }
2
1{[ , ] [ , ] [ , ] [ , ] [ , ] [ , ]}
21
{[ , ] [ , ]}2[ , ]
jkikj i k
ggg ij
kj i ij k ki j ji k jk i ik j
ij k ji k
ij k
[Prove] :
4-3 covariant derivatives of Nth –order Tensors
Let us work out the formula for the covariant derivatives of . write ..ijAk
..ij kk i j
AA ε ε ε
By definition
.. ,
.. ( )
ij kk p i j
ij kk i jp
Ap
A
Aε ε ε
ξ
ε ε εξ
This leads directly to the formula
.... , .. .. ..
ijij rj j iji ir rkk p k rp k rp r pkp
AA A A A
4-4 divergence of a vector A useful formula for
will be developed for general coordinate systems. We have
But, by determinant theory
Hence
And therefore
,( )
i pi iii ip
FF divF F F
p
[ , ]
1 [ - ]
2
1
2
i isip
ps ipis isi s
is isp
g ip s
g ggg
gg
ξ ξξ
ξ is isp p
gggg
ξ ξ
( )1 1
2
ggiip p pg g
ξ ξ
1( )ii
F F gg
ξ
4-5 Riemann-Christoffel Tensor
Since the order of differentiation in repeated partial differentiation of Cartesian tensor is irrelevant, it follows that the indices in repeated covariant differentiation of general tensors in Euclidean 3-D may also be interchanged at will. Thus, identities like
jiij ,, and
jikijk ff ,, Eq (4-5-1) is easily verified directly, since
2
, ,p
ij p ijji
ξ ξ
(4-5-1)
However, the assertion of (4-5-1) in Euclidean 3-D leads to some nontrivial information. By direct calculation it can be shown that
ppkijjikijk fRff .,,
.
p pkjp p pr rkiR
kij ri kj rj kii j
ξ ξWith help of (4-2-4) it can be shown that , the Riemann-christoffel tensor, is given by
Rpkij
2 2 221
[ ] [ ]2
r m r mpkij rm pj ki pi kj
g g ggpj pi kjkiR gk i p j j pk i
ξ ξ ξ ξ ξ ξ ξ ξ
But since the left-hand side of vanishes for all vectors , it follows that kf
0pkijR
Although (4-5-2) represents 81equations, most of them are either identities or redundant, since . Only six distinct nontrivial conditions are specified by (4-5-2), and they may be written as
(4-5-2)
031312331232312311223 RRRRRRpkij
pkij pkji kpij ijpkR R R R
(4-5-3)
[Note]
, ,( )
p pkj p pr rki
k ij k ji rj kj rj ki pi jf f f
ξ ξ[prove]
2
,,
,
,
( ) ( ) ( )
( ) ( ) ( )
k i p pk ij kj pi iji
pp p rk kki p kj kp r ij kpi i i r
pp p prk kk ji kj p kj pj r ji kpi j j p
pp pp pk ki
k ij p ki kjj j ji
ff f
ff ff f f
ff ff f f f
f fff f
ξ
ξ ξ ξ ξ
ξ ξ ξ ξ
ξξ ξ ξ ξ
2,
,
, ,
(
pjk
p p pr kkj pi r ij ij kpi p
pk j p pp p p p prk
k ji kj ki kj pj r ji ji krj i i ji
p pjk kjp pr r
k ij k ji kj pi r p jk pj r pj i
p pkj p rki
ri kj rji j
ff f
f fff f f
f f f f f f
ξ
ξ ξξ ξ ξ
ξξ
ξ ξ)p r
ki pf
Since is antisymmetrical in i and j as well as in p and k, no information is lost if (4-5-2) is multiplied by . Consequently , a set of six equations equivalent to (4-5-3) is given neatly by
pkijRspk tijε ε
0stSWhere is the symmetrical, second-order tensor stS
1
4spk tijst
pkijS R ε ε
The tensor is related simply to the Ricci tensor ijS
pij ij ij pR S g S
.p
ij ijpR R
So that (4-5-3) is also equivalent to the assertion 0ijR
The familiar divergence theorem relating integrals over a volume V and its boundary surface S can obvious be written in tensor notation as
Where Ni is the unit outward normal vector to S . Similar stokes , theorem
for integrals over a surface S and its boundary line C is just
Where tk is the unit tangent vector to C , and the usual handedness rules apply for direction of Ni and ti
,i if dv f N dsi i
v s
,ijk kf N ds f t dsck j i k
s ε
4-6 Integral Relations
GTRgR 82
1
ij ijR R
ijij
R g R
i i
k lx xi i
jk j jk jl
kijklR
1,
2j jkkk j
g ggjk
x xx
2 jiij
ds g dx dx
,iig jk
jk
廣義相對論
, ,i
j kl j lk jkl iA A R A jikl ijkl
R R
0i i ijkl klj ljkR R R
,i
iji j j
AA A
x
,
ii i
jj jA
A Ax
PgUUPT
ijkl klijR R
klijR
12
1
!4
321111
2
1 22
nnN
nnnnnnnn
0ijklR
ijlk ijklR R