in the name of god the most compassionate, the most...
TRANSCRIPT
Electric Machines I
In The Name of God The Most Compassionate, The Most Merciful
2017 Shiraz University of Technology Dr. A. Rahideh
2
Table of Contents1. Introduction to Electric Machines
2. Electromagnetic Circuits
3. Principle of Electromechanical Energy Conversion
4. Principle of Direct Current (DC) Machines
5. DC Generators
6. DC Motors
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Chapter 5Direct Current (DC) Generators
5.1. Different Types of DC Machines
5.2. Basic Relations
5.3. Armature Reaction
5.4. Operating Characteristics of DC Generators
5.5. Parallel Connection of DC Generators
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Different Types of DC GeneratorsBase on the magnetic field production, DC generators are classified as1. Separately excited DC generators: a separate voltage source
(from the generator terminal) is required for field production.2. Shunt DC generators: field winding is connected in parallel to
the generator terminal (armature winding).3. Series DC generators: field winding is connected in series with
the armature winding.4. Cumulative compound DC generators: both series and parallel
field windings are used and their magnetic fields are added together. It is further divided as long shunt and short shunt.
5. Differential compound DC generators: both series and parallel field windings are used and their magnetic fields are subtracted from each other. It is divided as long shunt and short shunt.2017 Shiraz University of Technology Dr. A. Rahideh
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Specifications of DC GeneratorsDC generators have the following specifications:
1. Nominal terminal voltage
2. Nominal power (nominal terminal current can be obtained from the first two items)
3. Efficiency
4. Nominal rotational velocity
5. Voltage regulation (VR) 100
fl
flnl
VVV
VR
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Prime movers• The mechanical power to a DC generator can be provided by a
prime mover.
• The prime movers can be 1. Steam turbines2. Gas turbines3. Hydro turbines4. Diesel engines5. Electric motors
• In this chapter, it is assumed that the rotational velocity of the generators is constant, unless otherwise mentioned.
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Separately Excited DC GeneratorsThe schematic diagram of the separately excited dc generator:
The simplified schematic diagram:
fV
aI
+
_
tV
fI
+ _
Field winding
Armature circuit
IL
N S +
Ia
Field winding Armature winding
_
+
_
If
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Separately Excited DC GeneratorsThe equivalent circuit of the separately excited dc generator:
ra is the armature winding resistancerf is the field winding resistanceIa is the armature currentIf is the field currentIL is the load currentVt is the generator terminal voltage (load voltage)Vf is the field winding voltageEa is the induced voltage in the armature winding
fV
aI
+
_
tV fI
+ _
LI
aE
ar fr
La II aaat rIEV kEa fff rIV fI
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Armature Induced VoltageInduced voltage in a single loop is expressed as:
is the rotational velocity in rad/s is the magnetic flux of each polep is the number of poles
The induced voltage in the armature winding having N turns and aparallel paths is obtained as:
Z is the total number of conductorsN is the total number of turnsa is the number of parallel paths
plrplr
lrA
lrBlvBE
/22
222
apZE
aZE
aNEa 22
apZk2
kEa
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Shunt DC GeneratorsThe schematic diagram of the shunt dc generator:
The simplified schematic diagram:
IL
N S
Ia
Field winding Armature winding
+
_
If
aI
+
_
tV
fI
LI
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Shunt DC GeneratorsThe equivalent circuit of the shunt dc generator:
aI
+
_
tV
fI
LI aI
+
_
tV
fI LI
aE
ar
fr
fLa III
aaat rIEV kEa
f
tf r
VI
fI
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Voltage-Making of Shunt DC Generators
• Assume a shunt DC generator is rotated using a prime mover under no‐load condition.
• In the starting point (when the rotational speed is still zero) the terminal voltage is zero;
• Therefore, the field current ( If ) is zero and no field can be produced.
• Consequently no emf is induced.• The question is how the terminal voltage can be made?• Residual flux is behind the voltage‐making.• Residual flux produces a small emf.• Small emf causes small terminal voltage.• Small terminal voltage flows small field current.• Small field current increases the flux and so on.
aI
+
_
tV
fI
LI
kEa
resa kE
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Series DC GeneratorsThe schematic diagram of the series dc generator:
The simplified schematic diagram:
If
IL
N S
Ia
Field winding Armature winding
+
_
aI
+
_
tV
fI
LI
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Series DC GeneratorsThe equivalent circuit of the series dc generator:
Lfa III
saaat rrIEV
kEa
af II
aI
+
_
tV
fI
LI aI
+
_
tV
fI LI
aE
arsr
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Compound DC GeneratorsShort-shunt
The simplified schematic diagram of the short‐shunt compound dc generator:
aI
+
_
tV fI
LI
Series field Shunt field
Cumulative Differential
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Compound DC GeneratorsShort-shunt
The equivalent circuit of the short‐shunt compound dc generator:
faL III
Lsaaat IrIrEV
kEa
alDifferenti
CumulativeLsfsh IkIk
aI
+
_
tV
fI
LI
aE
ar
fr
sr
f
aaaf r
IrEI
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Compound DC GeneratorsLong-shunt
The simplified schematic diagram of the long‐shunt compound dc generator:
aI
+
_
tV fI
LI
Series field Shunt field
Cumulative Differential
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Compound DC GeneratorsLong-shunt
The equivalent circuit of the long‐shunt compound dc generator:
faL III
saaat rrIEV
kEa
alDifferenti
Cumulativeasfsh IkIk
f
tf r
VI
aI
+
_
tV
fI
LI
aE
ar
fr
sr
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Cumulative vs. Differential Compound DC Generators
• If the direction of the fields produced by the series and shunt field windings are the same, the generator is cumulative;
• Otherwise it is differential.
• Effective magneto‐motive force (MMF) is calculated as
whereThe number of turns of shunt field windingThe number of turns of series field winding
ATD Ampere turn demagnetizing
alDifferenti
CumulativeATDININMMF ssffeffective
fNsN
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Power Flow in DC Generators• In dc generators the input power is mechanical (torque
multiplied by rotational speed)
• In dc generators the output power is electrical (voltage multiplied by current)
aaIEPP lossesmechmech
TPP mechin
LtLelecout IVPPP
Input mechanical power Mechanical losses
elecaa PPPPPIE lossesfieldlossescorelossesbrushlosses armature
Ohmic losses due to armature winding
Brushes losses Ohmic losses due to field windings
Core losses
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DC GeneratorsExample 1: Consider a separately excited DC generator with
a) If the field current is reduced to 2.4 A, but the rotational velocity remains unchanged, calculate the emf ( Ea ).
b) If the field current is reduced to 2.1 A, and the rotational velocity is increased to 1600 rpm, calculate the emf ( Ea ).
c) If at the rotational velocity of 1200 rpm, the emf is 120 V, calculate field current ( If ).
d) If emf is 160 V and field current is 2.2 A, calculate the rotational velocity ( n ).
V151aE rpm1450n A8.2fI
Separately Excited
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DC GeneratorsSolution 1: separately excited DC generator
a) If the field current is reduced to 2.4 A, but the rotational velocity remains unchanged, calculate the emf ( Ea ).
considering the linear core.
V151aE rpm1450n A8.2fI
kEaˆ nIkE fa
11
22
1
2
nIknIk
EE
f
f
a
a 1
2
1
212 n
nII
EEf
faa
V4.12914501450
8.24.21512 aE
2017 Shiraz University of Technology Dr. A. Rahideh
Separately Excited
23
DC GeneratorsSolution 1: separately excited DC generator
b) If the field current is reduced to 2.1 A, and the rotational velocity is increased to 1600 rpm, calculate the emf ( Ea ).
Note that emf is directly proportional with the field current and rotational velocity.
V151aE rpm1450n A8.2fI
1
2
1
212 n
nII
EEf
faa V125
14501600
8.21.21512 aE
2017 Shiraz University of Technology Dr. A. Rahideh
Separately Excited
24
DC GeneratorsSolution 1: separately excited DC generator
c) If at the rotational velocity of 1200 rpm, the emf is 120 V, calculate field current ( If ).
Note that field current is directly proportional with the emf but inversely proportional with the rotational velocity.
V151aE rpm1450n A8.2fI
11
22
1
2
nIknIk
EE
f
f
a
a 2
1
1
212 n
nEEII
a
aff
A7.212001450
1511208.22 fI
2017 Shiraz University of Technology Dr. A. Rahideh
Separately Excited
25
DC GeneratorsSolution 1: separately excited DC generator
d) If emf is 160 V and field current is 2.2 A, calculate the rotational velocity ( n ).
Note that rotational velocity is directly proportional with the emfbut inversely proportional with the field current.
V151aE rpm1450n A8.2fI
11
22
1
2
nIknIk
EE
f
f
a
a 2
1
1
212
f
f
a
a
II
EEnn
rpm19552.28.2
15116014502 n
2017 Shiraz University of Technology Dr. A. Rahideh
Separately Excited
26
DC GeneratorsExample 2: Consider a separately excited DC generator with the following values for nominal power, nominal terminal voltage and armature resistance:
a) If the generator supplies the nominal load under the nominal voltage, calculate the emf ( Ea ) and the armature current ( Ia ).
b) If the voltage terminal remains 250 V but the load decreases to 40 kW, calculate the emf ( Ea ).
c) If the load is 40 kW and emf is 255 V, calculate the terminal voltage( Vt ).
d) If the terminal voltage is 253 V and emf is 257 V, calculate load power ( PL ).
kW50nP V250ntV 025.0ar
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Separately Excited
27
DC GeneratorsSolution 2: a separately excited DC generator with
a) If the generator supplies the nominal load under the nominal voltage, calculate the emf ( Ea ) and the armature current ( Ia ).
kW50nP V250ntV 025.0ar
fV
aI
+
_
tV
fI
+ _
LI
aE
arfr
Load
V250 ntt VV
kW50 nL PP
A200250
50000 aL II
V255200025.0250 aata IrVE
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Separately Excited
28
DC GeneratorsSolution 2: a separately excited DC generator with
b) If the voltage terminal remains 250 V but the load decreases to 40 kW, calculate the emf ( Ea ).
kW50nP V250ntV 025.0ar
fV
aI
+
_
tV
fI
+ _
LI
aE
arfr
Load
V250tV
kW40LP
A160250
40000 aL II
V254160025.0250 aata IrVE
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Separately Excited
29
DC GeneratorsSolution 2: a separately excited DC generator with
c) If the load is 40 kW and emf is 255 V, calculate the terminal voltage( Vt ).
kW50nP V250ntV 025.0ar
fV
aI
+
_
tV
fI
+ _
LI
aE
arfr
Load
V255aE
kW40LP
taL V
II 40000
aata IrVE t
t VV 40000025.0255
010002552 tt VV
accepted)(NotV4
(Accepted)V251tV
2017 Shiraz University of Technology Dr. A. Rahideh
Separately Excited
30
DC GeneratorsSolution 2: a separately excited DC generator with
d) If the terminal voltage is 253 V and emf is 257 V, calculate load power ( PL ).
kW50nP V250ntV 025.0ar
fV
aI
+
_
tV
fI
+ _
LI
aE
arfr
Load
V257aE
V253tV
a
taaL r
VEII aata IrVE
W40480160253 LtL IVPA160025.0
253257
LI
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Separately Excited
31
DC GeneratorsExample 3: Consider a series DC generator with the following values for nominal power, nominal terminal voltage and series field resistance:
a) If the armature current is the nominal current and the terminal voltage is also nominal and emf is 137 V, calculate the armature resistance ( ra ).
b) If the terminal voltage is nominal but the load is 75% of nominal load, calculate the emf ( Ea ).
c) If the load is 8 kW and emf is 136 V, calculate the terminal voltage ( Vt ).
kW10nP V125ntV 05.0sr
Series
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DC GeneratorsSolution 3: a series DC generator
a) If the armature current is the nominal current and the terminal voltage is also nominal and emf is 137 V, calculate the armature resistance ( ra ).
kW10nP V125ntV 05.0sr
aI
+
_
tV
fILI
aE
arsr
Load
A80125
10000
nt
nna V
PI
15.080
125137
a
tasa I
VErr
1.015.0 sa rr
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Series
33
DC GeneratorsSolution 3: a series DC generator
b) If the terminal voltage is nominal but the load is 75% of nominal load, calculate the emf ( Ea ).
kW10nP V125ntV 05.0sr
aI
+
_
tV
fILI
aE
arsr
Load
A60125
1000075.0
t
La V
PI
saata rrIVE
V13405.01.060125 aE
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Series
34
DC GeneratorsSolution 3: a series DC generator
c) If the load is 8 kW and emf is 136 V, calculate the terminal voltage ( Vt ).
kW10nP V125ntV 05.0sr
aI
+
_
tV
fILI
aE
arsr
Load
tt
La VV
PI 8000
saata rrIVE
15.08000136 t
t VV
012001362 tt VV
accepted)(NotV5.9
(Accepted)V5.126tV
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Series
35
DC GeneratorsExample 4: Consider a shunt DC generator with the following values for nominal power, nominal terminal voltage armature resistance and field resistance:
An electrical load under nominal voltage is connected to the generator and emf is 267 V. Calculate the load power and the efficiency of the machine.
kW30nP V250ntV 12.0ar 40fr
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Series
36
DC GeneratorsSolution 4: Consider a shunt DC generator with
kW30nP V250ntV 12.0ar
Shunt
40fr
V250 ntt VV V267aE
aI
+
_
tV
fI
LI
aE
ar
fr
Load
A7.14112.0
250267
a
taa r
VEI
A25.640250
f
tf r
VI
A45.135 faL III
?LP ?
W5.3386245.135250 LtL IVP
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DC GeneratorsSolution 4: Consider a shunt DC generator with
Neglecting the mechanical losses,the input power is calculated as
kW30nP V250ntV 12.0ar 40fr
V250 ntt VV V267aE
aI
+
_
tV
fI
LI
aE
ar
fr
Load
?LP ?
W5.33862 Lout PP
W9.378337.141267 aain IEP
%5.899.37833
33862.5100% in
out
PP
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Shunt
38
DC GeneratorsExample 5: Consider a cumulative long‐shunt compound DC generator with the following values for nominal power, nominal terminal voltage series field resistance and shunt field resistance:
At the nominal condition (load power and terminal voltage are nominal), the input power to the generator is 103.5 kW. Calculate the armature resistance.
kW100nP V600ntV 02.0sr
Cumulative compound
200fr
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DC GeneratorsSolution 5: Consider a cumulative long‐shunt compound DC generator with
kW100nP V600ntV 02.0sr 200fr
kW100 nL PP V600 ntt VV kW5.103inP ?ar
aI
+
_
tV
fI
LI
aE
ar
fr
sr
Load
A7.166600
100000
t
LL V
PI
A3200600
f
tf r
VI
A7.169 fLa III
2017 Shiraz University of Technology Dr. A. Rahideh
Cumulative compound
40
DC GeneratorsSolution 5: Consider a cumulative long‐shunt compound DC generator with
kW100nP V600ntV 02.0sr 200fr
kW100 nL PP V600 ntt VV kW5.103inP ?ar
aI
+
_
tV
fI
LI
aE
ar
fr
sr
Load
A7.166LI A3fI A7.169aI
aain IEP V6107.169
103500
a
ina I
PE
059.07.169600610
a
tasa I
VErr
039.0059.0 sa rr
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Cumulative compound
41
Armature Reaction (AR)• The influence of the magnetic field due to armature current on
the main field due to field winding current is called armature reaction.
• Assume there is no current in the armature winding (no‐load condition), therefore the field is only produced by the field winding current.
If
N S Bf
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Armature Reaction (AR)• Now assume armature winding carrying currents, therefore the
field due to armature current interferes with that due to field winding current.
If
Bf Ba
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Armature Reaction (AR)
N S Ba
Bf
Ba Bf
Bf + Ba
Neutral axis
New neutral
axis
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Armature Reaction (AR)There are two armature reactions:1. Latitudinal armature reaction:
It means the neutral axis displacement. The displacement in the generating mode is in the direction of motion and in the motoring mode is in the opposite direction of motion.
2. Longitudinal armature reaction: The flux density under one edge of each pole increases and under the other edge decreases. The increase may saturate one edge of the pole and this effect is known as longitudinal AR or armature reaction demagnetization.
N S Ba
Bf
Ba Bf
Bf + Ba
Neutral axis
New neutral
axis
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Methods to Improve Commutation1. Brushes displacement
(load dependent)
2. Increase in the brush connection resistance (higher ohmic loss)
3. Using inter‐poles (higher cost)
4. Using compensating windings (higher cost)
Field
windingArmature winding
Rotor
Stator
Inter-pole
Commutator
Compensating winding
Pole-shoe
Brush
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Compensating Windings• Compensating windings reduce the
armature reaction.
• The armature current flows in the compensating windings.
• Ampere‐turn of compensating windings in each pole is expressed as:
(1)Where Zcw is the number of compensating conductors, Ia is the armature current.
Inter-pole
Compensating winding
acw
cw IZAT2
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Compensating Windings• The ampere‐turn of armature
windings under each pole is expressed as:
(2)
Where Z is the total armature conductors, a is the number of parallel paths and p is the number of poles.
Inter-pole
Compensating winding
aa MMFATpitchPolearcPole
aI
pZAT a
a 2pitchPolearcPole
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Compensating Windings• To minimize the armature reaction,
the ampere‐turn of compensating windings should be equal to that of armature windings but in opposite direction.
(1)
(2)
Inter-pole
Compensating winding
aI
pZAT a
a 2pitchPolearcPole
acw
cw IZAT2
acw ATAT pa
ZZcw pitchPolearcPole
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Compensating WindingsExample: Consider a DC machine with 14 poles, 400 V, 2000 kW, having lap winding and 1100 conductors. Pole arc per pole pitch ratio is 0.7. Calculate the number of compensating conductors in each pole to have a uniform air‐gap flux density under each pole.
paZZcw pitchPole
arcPole
14p 14aLap winding
1100Z
41414
11007.0
cwZ
2017 Shiraz University of Technology Dr. A. Rahideh
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Inter-polesExample: Consider a DC generator with 6 inter‐poles, 600 V, 600 kW, having lap winding and 696 conductors. Calculate the number of turns of each inter‐pole if the MMF of inter‐poles is 1.25 times higher than that of armature.
The current of inter‐poles is the same as armature current (Ia).
aMMFMMF 25.1poleinter
6p 6aLap winding
696Z
12662
69625.1poleinter
NaI
pZIN a
a 225.1poleinter
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Operating Characteristics of DC Generators
1. No‐load Characteristics (Magnetic Characteristics): No load terminal voltage vs. field currentGenerator speed is kept constant.
2. Full‐load Characteristics: Full‐load terminal voltage vs. field currentGenerator speed and load current are kept constant.
3. External Characteristics: Terminal voltage vs. load currentGenerator speed and field current are kept constant.
4. Armature‐reaction CharacteristicsField current vs. load currentGenerator speed and terminal voltage are kept constant.
fa IE
ft IV
Lt IV
Lf II
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Operating Characteristics of Separately Excited DC Generators
The following circuit is used to obtain the characteristics of a separately excited DC generator:
fV
La II S1
_
tV
fI
+
_
Variable load
V
A+
S2
A
fR
2017 Shiraz University of Technology Dr. A. Rahideh
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Operating Characteristics of Separately Excited DC Generators
1. No‐load Characteristics (Magnetic Characteristics): No load terminal voltage vs. field current
fa IE
)A(fI
(V)aE
Procedure: • Switches S1 and S2 are both open.• Generator is rotated at the nominal
speed.• Due to the residual flux, a small voltage
appears on the terminal.• Rf is set to its maximum value and S2 is
closed.• Rf is gradually and monotonically
decreased and the terminal voltage and field current are recorded.
fV
La II S1
_
tV
fI
+
_
Variable load
V
A+
S2
A
fR
ctenr
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Operating Characteristics of Separately Excited DC Generators
2. Full‐load Characteristics: Full‐load terminal voltage vs. field current
ft IV
Procedure: • Switches S1 and S2 are both open.• Generator is rotated at the nominal speed.• Load resistance is set to its minimum (zero)
and Rf is set to its maximum value.• Switches S1 and S2 are closed.• Load resistance is increased and Rf is
gradually decreased so that the load current always remains at nominal value.
• The terminal voltage and field current are recorded.
fV
La II S1
_
tV
fI
+
_
Variable load
V
A+
S2
A
fR
ctenr
)A(fI
(V)tV
cteIL
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Operating Characteristics of Separately Excited DC Generators
3. External Characteristics: Terminal voltage vs. load current
Lt IV
Procedure: • Switches S1 and S2 are both open.• Generator is rotated at the nominal speed.• S2 is closed and Rf is set so that to have
nominal terminal voltage.• Load resistance is set to its maximum value
and S1 is closed.• Load resistance is decreased and field current
is kept unchanged.• The terminal voltage and load current are
recorded.
fV
La II S1
_
tV
fI
+
_
Variable load
V
A+
S2
A
fR
ctenr cteI f
(A)LI
(V)tV
Ohmic drop AR drop
2017 Shiraz University of Technology Dr. A. Rahideh
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Operating Characteristics of Separately Excited DC Generators
4. Armature‐reaction CharacteristicsField current vs. load current
Lf II
Procedure: • Switches S1 and S2 are both open.• Generator is rotated at the nominal speed.• S2 is closed and Rf is set so that to have
nominal terminal voltage.• Load resistance is set to its maximum value
and S1 is closed.• Load resistance is decreased and field current
is increased to keep the terminal voltage unchanged (always nominal value).
• The load current and field current are recorded.
fV
La II S1
_
tV
fI
+
_
Variable load
V
A+
S2
A
fR
ctenr cteVt
(A)LI
(A)fI
2017 Shiraz University of Technology Dr. A. Rahideh
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Operating Characteristics of Shunt DC Generators
The following circuit is used to obtain the characteristics of a shunt DC generator:
LIS1
_
tVfI Variable
load V
A+
S2 A
fR
aI
2017 Shiraz University of Technology Dr. A. Rahideh
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Starting of Shunt DC Generators• Shunt DC generators use the
terminal voltage to excite the field circuit.
• At starting situation there is a small terminal voltage due to residual flux which slightly excites the field circuit.
• The small voltage causes a small field current.
• The small field current in addition to residual flux increase the terminal voltage.
• It continues to reach to the normal operating point.
)A(fI
(V)aE cR fR
cf RR
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Starting of Shunt DC GeneratorsA shunt DC generator may not make voltage due to one of the following reasons:1. Lack of residual flux. The shunt
generator should be started in separately excited mode.
2. The flux due to the field circuit is in opposite to the residual flux.
3. The field resistance is greater than critical resistance (Rc).
)A(fI
(V)aE cR fR
cf RR
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Operating Characteristics of Shunt DC Generators
1. No‐load Characteristics (Magnetic Characteristics): No load terminal voltage vs. field current
fa IE
)A(fI
(V)aE
Procedure: • Switches S1 and S2 are both open.• Generator is rotated at the nominal
speed.• Due to the residual flux, a small voltage
appears on the terminal.• Rf is set to its maximum value and S2 is
closed.• Rf is gradually and monotonically
decreased and the terminal voltage and field current are recorded. ctenr
LIS1
_
tVfI Variable
load V
A+
S2 A
fR
aISimilar to separately excited
2017 Shiraz University of Technology Dr. A. Rahideh
61
Operating Characteristics of Shunt DC Generators
2. Full‐load Characteristics: Full‐load terminal voltage vs. field current
ft IV
Procedure: • Since Vt and If are, respectively, the
voltage and current of the field resistance, this characteristics is a line with slope of Rf .
ctenr cteIL
)A(fI
(V)tV
LIS1
_
tVfI Variable
load V
A+
S2 A
fR
aI
2017 Shiraz University of Technology Dr. A. Rahideh
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Operating Characteristics of Separately Excited DC Generators
3. External Characteristics: Terminal voltage vs. load current
Lt IV
Procedure: • Switches S1 and S2 are both open.• Generator is rotated at the nominal speed.• S2 is closed and Rf is set so that to have
nominal terminal voltage.• Load resistance is set to its maximum value
and S1 is closed.• Load resistance is gradually decreased. Field
current cannot be kept constant.• The terminal voltage and load current are
recorded. ctenr
LIS1
_
tVfI Variable
load V
A+
S2 A
fR
aI
(A)LI
(V)tV
B
scI
2017 Shiraz University of Technology Dr. A. Rahideh
63
Operating Characteristics of Shunt DC Generators
4. Armature‐reaction CharacteristicsField current vs. load current
Lf II
• The generator is connected as separately excited and this characteristics is obtained.
fV
La II S1
_
tV
fI
+
_
Variable load
V
A+
S2
A
fR
ctenr cteVt
(A)LI
(A)fI
2017 Shiraz University of Technology Dr. A. Rahideh
64
Operating Characteristics of Series DC Generators
The following circuit is used to obtain the characteristics of a series DC generator:
• No‐load characteristics is undefined for this generator because at no‐load the field current is zero.
• Armature reaction characteristics is meaningless here because.
LIS1
_
tV
fI
Variable load
V
A+ aI
Lf II 2017 Shiraz University of Technology Dr. A. Rahideh
65
Operating Characteristics of Series DC Generators
Full‐load and external Characteristics: Full‐load terminal voltage vs. field or load current
ft IV
Since load and field currents are identical full‐load and external characteristics are the same.
ctenr
Lf II
LIS1
_
tV
fI
Variable load
V
A+ aI
Lt IV
)A(fL II
(V)tV
2017 Shiraz University of Technology Dr. A. Rahideh
66
Operating Characteristics of Compound DC Generators
1. Cumulative compoundi. Over Compound: series field MMF is significantly greater
than shunt field MMF.
ii. Flat compound: series and shunt MMFs are so that the terminal voltage at full‐load is the same as the terminal voltage at no‐load.
iii. Under compound: series field MMF is lower than shunt field MMF.
2. Differential compound
2017 Shiraz University of Technology Dr. A. Rahideh
67
Operating Characteristics of Compound DC Generators
(A)LI
(V)tV
Flat compound
Over compound
LnI
Under compound Separately excited
Shunt Differential compound
2017 Shiraz University of Technology Dr. A. Rahideh