intro to cs – honors i basic sorting georgios portokalidis [email protected]

11
Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS [email protected]

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Page 1: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU

Intro to CS – Honors IBasic SortingGEORGIOS PORTOKALIDIS

[email protected]

Page 2: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU

Sorting Arranging a collection of items into a particular order

If we are talking about integers◦ a[0] ≤ a[1] ≤ a[2] ≤ ... ≤ a[a.length - 1]

The simplest algorithm in pseudocode

for (index = 0; index < a.length; index++)

Place the (index + 1)th smallest element in a[index]

Can you expand this algorithm? What considerations should you take into account?

Page 3: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU

Selection Sort Some requirements

◦ We want the algorithm to use only this one array a◦ There are other algorithms we could use, if we could use more memory

How can we move array elements under these conditions?

We will swap elements

All sorting algorithms that swap elements are called interchange sorting algorithm

Page 4: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU

Find the smallest element and move it to its rightful place

Can you write an algorithm in pseudocode to implement this?

Page 5: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU

Pseudocode for SelectionSortfor (index = 0; index <a.length − 1; index++){

// Place the correct value in a[index]:indexOfNextSmallest = the index of the smallest value among

a[index], a[index+1],..., a[a.length - 1]

Interchange the values of a[index] and a[indexOfNextSmallest].//Assertion: a[0] <= a[1] <= ... <= a[index] and these//are the smallest of the original array elements.//The remaining positions contain the rest of the//original array elements.

}

Page 6: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU

/**Precondition: i and j are valid indices for the array a.Postcondition: Values of a[i] and a[j] have been interchanged.*/private static void interchange(int i, int j, int[] a){

int temp = a[i];a[i] = a[j];a[j] = temp; //original value of a[i]

}

private static int getIndexOfSmallest(int startIndex, int[] a){

int min = a[startIndex];int indexOfMin = startIndex;for (int index = startIndex + 1; index < a.length;

index++){

if (a[index] < min){

min = a[index];indexOfMin = index;//min is smallest of a[startIndex]

through a[index]}

}return indexOfMin;

}

public static void selectionSort(int[] anArray){

for (int index = 0; index < anArray.length − 1; index++){ // Place the correct value in anArray[index]

int indexOfNextSmallest = getIndexOfSmallest(index, anArray);

interchange(index, indexOfNextSmallest, anArray);}

}

Page 7: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU

Selection Sort in Action

Page 8: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU

Why Use Selection Sort It is simple!

Not very efficient

Simple implies it is easier to implement and less prone to errors

Page 9: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU

Complexity What is the worst-case scenario?

What is the maximum number of comparisons that selection sort may require?

For example to swap the first element you require (n – 1) comparisons

(n − 1) + (n − 2) + ... + 2 + 1 = n(n − 1) / 2 ≈ n2 ◦ Arithmetic progression

This is indicated as O(n2)

Page 10: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU

Searching Arrays What is the simplest way to look for an item in an array?

You can sequentially check each item

However, sorted arrays enable other algorithms◦ Example: binary search

Page 11: Intro to CS – Honors I Basic Sorting GEORGIOS PORTOKALIDIS GPORTOKA@STEVENS.EDU