introduction to ac circuits (capacitors and inductors) 2 days ago · ac circuits dr. mohamed refky...
TRANSCRIPT
-
Introduction to AC Circuits
(Capacitors and Inductors)
Dr. Mohamed Refky Amin
Electronics and Electrical Communications Engineering Department (EECE)
Cairo University
http://scholar.cu.edu.eg/refky/
-
OUTLINE
• Previously on ELCN102
• AC Circuits
• Capacitors
• Inductors
• Transient Analysis
RC Circuits
RL Circuits
Dr. Mohamed Refky 2
-
Previously on ELCN102
Dr. Mohamed Refky
DefinitionElectric circuit theorems are always beneficial to help find
voltage and currents in multi loop circuits.
The network theorems include:
• Superposition Theorem
• Thevenin’s Theorem
• Norton’s Theorem
• Maximum Power Transfer Theorem3
-
Previously on ELCN102
Dr. Mohamed Refky
Norton’s TheoremA linear two-terminal circuit can be replaced by equivalent circuit
consisting of a current source 𝐼𝑁 in parallel with a resistor 𝑅𝑁
4
-
Previously on ELCN102
Dr. Mohamed Refky
Steps of Norton’s Theorem1) Identify the load resistance and introduce two nodes 𝑎 and 𝑏
2) Remove the load resistance between node 𝑎 and 𝑏 and set allthe independent sources to zero (voltage sources are SC and
current sources are OC) and calculate the resistance seen
between nodes 𝑎 and 𝑏. This resistance is 𝑅𝑁 of the Nortonequivalent circuit.
3) Replace the load resistance with a short circuit and calculate
the short circuit current between nodes 𝑎 and 𝑏. This currentis 𝐼𝑁 of the Norton equivalent circuit.
5
-
Previously on ELCN102
Dr. Mohamed Refky
Thevenin and Norton equivalent circuits
Thevenin equivalent circuit must be equivalent to Norton
equivalent circuit
𝑅𝑁 = 𝑅𝑡ℎ, 𝑉𝑡ℎ = 𝐼𝑁𝑅𝑁, 𝐼𝑁 =𝑉𝑡ℎ𝑅𝑡ℎ
→ 𝑅𝑡ℎ =𝑉𝑡ℎ𝐼𝑁
6
-
Previously on ELCN102
Dr. Mohamed Refky
Maximum Power Transfer TheoremThe maximum amount of power will be dissipated by a load
resistance (𝑅𝐿 ) when that load resistance is equal to theThevenin/Norton resistance of the network supplying the power.
→ 𝑅𝐿 = 𝑅𝑡ℎ = 𝑅𝑁For maximum power 𝑃𝑅𝐿
7
-
AC Circuits
Dr. Mohamed Refky
DefinitionAn AC circuit is a combination of active elements (Voltage and
current sources) and passive elements (resistors, capacitors and
coils).
Unlike resistance, capacitors and coils can store energy and do
not dissipate it. Thus, capacitors and coils are called storage
elements.8
-
AC Circuits
Dr. Mohamed Refky
DefinitionAn AC circuit is a combination of active elements (Voltage and
current sources) and passive elements (resistors, capacitors and
coils).
The sources are usually sinusoidal voltage or current sources
9
-
Capacitors
Dr. Mohamed Refky
Definition and StructureA capacitor is a passive element designed to store energy in its
electric field.
Capacitors are the most common component beside resistors. It
used in electronics, communication, and computer systems.
A capacitor is an electrical device
constructed of two parallel plates
separated by an insulating material
called the dielectric.
10
-
Capacitors
Dr. Mohamed Refky
Definition and StructureWhen a voltage source is connected to a capacitor, an electric
field is generated in the dielectric and charges are accumulated on
the plates.
𝑄 = 𝐶 × 𝑉
𝐶 =𝑄
𝑉
The amount of charge (𝑄) that a capacitor can store per voltacross the plates, is its capacitance (𝐶).
Coulomb Farad
Volt
11
-
Capacitors
Dr. Mohamed Refky
Definition and Structure
Most capacitors in electronics have capacitance values of micro-
Farad (𝜇𝐹 = 10−6 𝐹) to pico-Farad (𝑝𝐹 = 10−12 𝐹) .
12
-
Capacitors
Dr. Mohamed Refky
Instantaneous Current
𝑄 = 𝐶 × 𝑉
𝑖𝑐 𝑡 =𝑑𝑞 𝑡
𝑑𝑡=𝑑 𝑐 𝑡 × 𝑣𝑐 𝑡
𝑑𝑡
For constant capacitance (𝑐 𝑡 = 𝐶)
𝑞 𝑡 = 𝐶 × 𝑣𝑐 𝑡
𝑖𝑐(𝑡) = 𝐶𝑑𝑣𝑐(𝑡)
𝑑𝑡
13
-
Capacitors
Dr. Mohamed Refky
Instantaneous Power and Energy storedInstantaneous power is given by
𝑞(𝑡) = 𝑣 𝑡 × 𝑖 𝑡
= 𝑣 𝑡 × 𝐶𝑑𝑣(𝑡)
𝑑𝑡
Energy stored in the capacitor is given by
𝑤 = න𝑞 𝑡 𝑑𝑡 = න 𝑣 𝑡 × 𝐶𝑑𝑣(𝑡)
𝑑𝑡𝑑𝑡
= 𝐶න𝑣 𝑡 𝑑𝑣(𝑡) =1
2𝐶𝑣2 𝑡
14
-
Capacitors
Dr. Mohamed Refky
Series and Parallel Combinations
𝑣𝑒𝑞𝑢 = 𝑣1 + 𝑣2 +⋯+ 𝑣𝑁
Series Capacitors
𝑄
𝐶𝑒𝑞=𝑄
𝐶1+𝑄
𝐶2+⋯+
𝑄
𝐶𝑁
𝑄 = 𝐶 × 𝑉
𝑄 −𝑄 𝑄 −𝑄 𝑄 −𝑄
𝑄 −𝑄
15
-
Capacitors
Dr. Mohamed Refky
Series and Parallel Combinations
Series Capacitors
1
𝐶𝑒𝑞=
1
𝐶1+
1
𝐶2+⋯+
1
𝐶𝑁
𝑄 = 𝐶 × 𝑉
16
-
Capacitors
Dr. Mohamed Refky
Series and Parallel Combinations
Parallel Capacitors 𝑄 = 𝐶 × 𝑉
𝑄𝑒𝑞 = 𝑄1 + 𝑄2 +⋯+ 𝑄𝑁
𝐶𝑒𝑞𝑣 = 𝐶1𝑣 + 𝐶2𝑣 + ⋯+ 𝐶𝑁𝑣
17
-
Capacitors
Dr. Mohamed Refky
Series and Parallel Combinations
Parallel Capacitors 𝑄 = 𝐶 × 𝑉
𝐶𝑒𝑞 = 𝐶1 + 𝐶2 +⋯+ 𝐶𝑁
18
-
Capacitors
Dr. Mohamed Refky
Example (1)Find the equivalent capacitance seen between terminals 𝑎 and 𝑏of the circuit shown.
19
-
Inductors
Dr. Mohamed Refky
Definition and StructureAn inductor is a passive element designed to store energy in its
magnetic field.
Inductors are used in power supplies, transformers, radios, TVs,
radars, and electric motors.
An inductor is constructed of a wire
wounded into a coil.
20
-
Inductors
Dr. Mohamed Refky
Definition and StructureWhen the current flowing through an
inductor changes, the magnetic field induces
a voltage in the conductor, according to
Faraday’s law of electromagnetic induction,
to resist this change in the current.
𝑣𝐿 𝑡 = 𝐿𝑑𝑖𝐿 𝑡
𝑑𝑡
𝐿 is the inductance in Henri (𝐻)
21
-
Inductors
Dr. Mohamed Refky
Definition and Structure
Most inductors in electronics have inductance values of mille
Henri (𝑚𝐻 = 10−3 𝐻) to micro- Henri (𝜇𝐻 = 10−6 𝐻) .
22
-
Inductors
Dr. Mohamed Refky
Series and Parallel Combinations
𝑣𝑒𝑞𝑢 = 𝑣1 + 𝑣2 +⋯+ 𝑣𝑁
Series Inductors
𝐿𝑒𝑞𝑑𝑖
𝑑𝑡= 𝐿1
𝑑𝑖
𝑑𝑡+ 𝐿2
𝑑𝑖
𝑑𝑡+ ⋯+ 𝐿𝑁
𝑑𝑖
𝑑𝑡 23
-
Inductors
Dr. Mohamed Refky
Series and Parallel Combinations
Series Inductors
𝐿𝑒𝑞 = 𝐿1 + 𝐿2 +⋯+ 𝐿𝑁
24
-
Inductors
Dr. Mohamed Refky
Series and Parallel Combinations
Parallel Inductors
𝑖 = 𝑖1 + 𝑖2 +⋯+ 𝑖𝑁
1
𝐿𝑒𝑞න𝑣 𝑑𝑡 =
1
𝐿1න𝑣 𝑑𝑡 +
1
𝐿2න𝑣 𝑑𝑡 + ⋯+
1
𝐿𝑁න𝑣 𝑑𝑡
𝑣 = 𝐿𝑑𝑖
𝑑𝑡
25
-
Inductors
Dr. Mohamed Refky
Series and Parallel Combinations
Parallel Inductors
1
𝐿𝑒𝑞=
1
𝐿1+
1
𝐿2+⋯+
1
𝐿𝑁
26
-
Inductors
Dr. Mohamed Refky
Example (2)Find the equivalent inductance seen between terminals 𝑎 and 𝑏 ofthe circuit shown.
27
-
Transient Analysis
Dr. Mohamed Refky
DefinitionThe transient response of the circuit is the response when the input
is changed suddenly or a switches status is changed.
𝑣 𝑡 =
𝑣1 𝑡 , 𝑡0 < 𝑡 < 𝑡1𝑣2 𝑡 , 𝑡1 < 𝑡 < 𝑡2
⋮𝑣𝑛 𝑡 , 𝑡𝑛−1 < 𝑡 < 𝑡𝑛
𝑣 𝑡 the same
28
-
Transient Analysis
Dr. Mohamed Refky
DefinitionThe transient response of the circuit is the response when the input
is changed suddenly or a switches status is changed.
𝑣 𝑡 the same
29
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
At 𝑡 = 0−, capacitor is initiallycharged to 𝑉0.
𝑣𝑐 0 = 𝑉0
At 𝑡 = 0, the switch is closed.
Source Free RC Circuits
From the resistor 𝑖 𝑡 =𝑣𝑐 𝑡
𝑅
From the capacitor 𝑖 𝑡 = −𝐶𝑑𝑣𝑐 𝑡
𝑑𝑡
30
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
−𝐶𝑑𝑣𝑐 𝑡
𝑑𝑡=𝑣𝑐 𝑡
𝑅
𝑑𝑣𝑐 𝑡
𝑑𝑡= −
𝑣𝑐 𝑡
𝐶𝑅
Source Free RC Circuits
𝑣𝑐 0 = 𝑉0
This is a first order differential
equation with an initial condition
𝑑
𝑑𝑡𝑎𝑒−𝑏𝑡 = −𝑎𝑏 𝑒−𝑏𝑡
Hint:
31
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑑𝑣𝑐 𝑡
𝑑𝑡= −
𝑣𝑐 𝑡
𝐶𝑅
𝑣𝑐 𝑡 = 𝛼𝑒−𝑡𝑅𝐶
Source Free RC Circuits
𝑣𝑐 0 = 𝛼𝑒0𝑅𝐶 = 𝑉0
Using the initial condition
𝛼 = 𝑉032
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑣𝑐 𝑡 = 𝑉0𝑒−𝑡𝑅𝐶
𝑅𝐶 is called the time constantof the circuit (𝜏)
Source Free RC Circuits
The time constant (𝜏) of a circuit isthe time required for the response
to decay to 1/𝑒 or 36.8% of itsinitial value (a change of 63%).
33
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑣𝑐 𝑡 = 𝑉0𝑒−𝑡𝑅𝐶
Source Free RC Circuits
It takes about 5𝜏 to changethe voltage by 99%. This
period of 5𝜏 is calledtransient time.
𝑣𝑐 𝑡 Change
𝜏 0.3678𝑉0 63%
2𝜏 0.1353𝑉0 86%
3𝜏 0.0497𝑉0 95%
4𝜏 0.0183𝑉0 98%
5𝜏 0.0067𝑉0 99%
34
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑣𝑅 𝑡 = 𝑣𝑐 𝑡 = 𝑉0𝑒−𝑡𝑅𝐶
𝑖 𝑡 =𝑉0𝑅𝑒−𝑡𝑅𝐶
Power dissipated in the resistor
Source Free RC Circuits
𝑝 𝑡 = 𝑣𝑅 𝑡 × 𝑖 𝑡 =𝑉02
𝑅𝑒−2𝑡𝑅𝐶
35
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
Energy dissipated by the resistor
Source Free RC Circuits
𝑝 𝑡 = 𝑣𝑅 𝑡 × 𝑖 𝑡 =𝑉02
𝑅𝑒−2𝑡𝑅𝐶
𝑤 𝑡 = න0
𝑡
𝑝 𝑡 𝑑𝑡
=𝑉02
𝑅න0
𝑡
𝑒−2𝑡𝑅𝐶 𝑑𝑡 =
𝑉02
𝑅
−𝑅𝐶
2𝑒−2𝑡𝑅𝐶
0
𝑡
=𝑉02𝐶
21 − 𝑒
−2𝑡𝑅𝐶
36
-
Transient Analysis
Dr. Mohamed Refky
Example (3)For the circuit shown, 𝑣𝐶(0) = 15 𝑉. 𝑅1 = 5𝑘Ω, 𝑅2 = 8𝑘Ω,𝑅3 = 12𝑘Ω, 𝐶 = 100𝜇𝐹. Find 𝑣𝐶 𝑡 , 𝑣𝑥 𝑡 , and 𝑖𝑥 𝑡 for 𝑡> 0.
37
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
The step response is the
response of the circuit due to
a sudden change of voltage
or current source.
𝑖𝑅 𝑡 =𝐸 − 𝑣𝑐 𝑡
𝑅
𝑖𝐶 𝑡 = 𝐶𝑑𝑣𝑐 𝑡
𝑑𝑡
Step response of an RC circuits
38
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑖𝐶 𝑡 = 𝑖𝑅 𝑡
𝐶𝑑𝑣𝑐 𝑡
𝑑𝑡=𝐸 − 𝑣𝑐 𝑡
𝑅
−𝐶𝑑 𝐸 − 𝑣𝑐 𝑡
𝑑𝑡=𝐸 − 𝑣𝑐 𝑡
𝑅
𝑑 𝐸 − 𝑣𝑐 𝑡
𝑑𝑡= −
𝐸 − 𝑣𝑐 𝑡
𝑅𝐶
Step response of an RC circuits
39
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑑 𝐸 − 𝑣𝑐 𝑡
𝑑𝑡= −
𝐸 − 𝑣𝑐 𝑡
𝑅𝐶
𝑣𝑐 0 = 𝑉0
𝐸 − 𝑣𝑐 𝑡 = 𝛼𝑒−𝑡𝑅𝐶
𝐸 − 𝑉0 = 𝛼𝑒−0𝑅𝐶
Step response of an RC circuits
→ 𝛼 = 𝐸 − 𝑉0
40
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝐸 − 𝑣𝑐 𝑡 = 𝐸 − 𝑉0 𝑒−𝑡𝑅𝐶
𝑣𝑐 𝑡 = 𝐸 − 𝐸 − 𝑉0 𝑒−𝑡𝑅𝐶
If 𝑉0 = 0
𝑣𝑐 𝑡 = 𝐸 − 𝐸𝑒−𝑡𝑅𝐶
= 𝐸 1 − 𝐸 𝑒−𝑡𝑅𝐶
Step response of an RC circuits
41
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝐸 − 𝑣𝑐 𝑡 = 𝐸 − 𝑉0 𝑒−𝑡𝑅𝐶
𝑣𝑐 𝑡 = 𝐸 − 𝐸 − 𝑉0 𝑒−𝑡𝑅𝐶
If 𝑉0 = 0
𝑣𝑐 𝑡 = 𝐸 − 𝐸𝑒−𝑡𝑅𝐶
= 𝐸 1 − 𝐸 𝑒−𝑡𝑅𝐶
Step response of an RC circuits
42
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑣𝑐 𝑡 = 𝐸 − 𝐸 − 𝑉0 𝑒−𝑡𝑅𝐶
𝑖 𝑡 = 𝐶𝑑𝑣𝑐 𝑡
𝑑𝑡=𝐸 − 𝑣𝑐 𝑡
𝑅
=𝐸 − 𝑉0𝑅
𝑒−𝑡𝑅𝐶
Step response of an RC circuits
43
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
Steady state response of a circuit is the behavior of the circuit a
long time after an external excitation is applied.
Theoretically, the steady state period starts at 𝑡 = ∞. However,practically, it starts at 𝑡 = 5𝜏.
In steady state, we deal with DC analysis.
Steady State Response
In DC, the capacitor is consider
open circuit (𝑖𝑐 = 0) and the coil isconsider short circuit (𝑣𝐿 = 0). 𝑣𝐿 𝑡 = 𝐿
𝑑𝑖𝐿 𝑡
𝑑𝑡
𝑖𝑐(𝑡) = 𝐶𝑑𝑣𝑐(𝑡)
𝑑𝑡
44
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
At steady state,
𝑣𝑐 ∞ = 𝐸
𝑖 ∞ = 0
Steady State Response
𝑣𝑐 𝑡 = 𝐸 − 𝐸 − 𝑉0 𝑒−𝑡𝑅𝐶
𝑡=∞𝑣𝑐 ∞ = 𝐸
𝑖 𝑡 =𝐸 − 𝑉0𝑅
𝑒−𝑡𝑅𝐶
𝑡=∞𝑖 ∞ = 0
45
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
Transient response of a circuit is the circuit’s temporary response
that will die out with time. The transient period starts at 𝑡 = 0and ends at 𝑡 = 5𝜏
Generally, For a first order RC circuit
𝑉𝑖 and 𝑉𝑓 are the initial and final capacitor voltages, respectively.
𝜏 = 𝑅𝑒𝑞𝐶, 𝑅𝑒𝑞 is the resistance seen between the capacitor nodes
while all sources are switched off.
Transient response
𝑣𝑐 𝑡 = 𝑉𝑓 − 𝑉𝑓 − 𝑉𝑖 𝑒−𝑡𝜏
46
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑣𝑐 𝑡 = 𝑉𝑓 − 𝑉𝑓 − 𝑉𝑖 𝑒−𝑡𝜏
𝑉𝑖 = 𝑣𝑐 0 = 𝑉0
𝑉𝑓 = 𝑣𝑐 ∞ = 0
𝑣𝑐 𝑡 = 0 − 0 − 𝑉0 𝑒−𝑡𝑅𝐶
= 𝑉0𝑒−𝑡𝑅𝐶
Source Free RC Circuits
𝜏 = 𝑅𝐶
47
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
Steady State Response
𝑣𝑐 𝑡 = 𝑉𝑓 − 𝑉𝑓 − 𝑉𝑖 𝑒−𝑡𝜏
𝑉𝑖 = 𝑣𝑐 0 = 𝑉0
𝑉𝑓 = 𝑣𝑐 ∞ = 𝐸
𝑣𝑐 𝑡 = 𝐸 − 𝐸 − 𝑉0 𝑒−𝑡𝑅𝐶
𝜏 = 𝑅𝐶
48
-
Transient Analysis
Dr. Mohamed Refky
Example (4)For the shown circuit, switch has been in position 𝑎 for a longtime. At 𝑡 = 0, the switch moves to 𝑏. Determine 𝑣𝑐(𝑡) for 𝑡 > 0and calculate its value at 𝑡 = 1, 4, and 20𝑚𝑠.
49
-
Transient Analysis
Dr. Mohamed Refky
Example (5)For the shown circuit, switch has been open for a long time and is
closed at 𝑡 = 0. Calculate 𝑣𝑐(𝑡) at 𝑡 = 0.5 and 4𝑚𝑠.
50
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑣𝐿 𝑡 = 𝐿𝑑𝑖𝐿 𝑡
𝑑𝑡
𝑣𝑅 𝑡 = 𝑅𝑖𝐿 𝑡
𝑣𝐿 𝑡 = −𝑣𝑅 𝑡
𝐿𝑑𝑖𝐿 𝑡
𝑑𝑡= −𝑅𝑖𝐿 𝑡
𝑑𝑖𝐿 𝑡
𝑑𝑡= −
𝑅
𝐿𝑖𝐿 𝑡
Source Free RL Circuits
51
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑑𝑖𝐿 𝑡
𝑑𝑡= −
𝑅
𝐿𝑖𝐿 𝑡
𝑖𝐿 0 = 𝐼0
𝑖𝐿 𝑡 = 𝐼0𝑒−𝑡𝜏, 𝜏 =
𝐿
𝑅
Generally,
Source Free RL Circuits
𝑖𝐿 𝑡 = 𝐼𝑓 − 𝐼𝑓 − 𝐼𝑖 𝑒−𝑡𝜏, 𝜏 =
𝐿
𝑅52
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑖𝐿 𝑡 = 𝐼𝑓 − 𝐼𝑓 − 𝐼𝑖 𝑒−𝑡𝜏, 𝜏 =
𝐿
𝑅
𝐼𝑖 = 𝑖𝐿 0 = 𝐼0
𝐼𝑓 = 0
Then
𝑖𝐿 𝑡 = 0 − 0 − 𝐼0 𝑒−𝑡𝜏
= 𝐼0𝑒−𝑡𝜏
Source Free RL Circuits
𝜏 =𝐿
𝑅
53
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
𝑖𝐿 𝑡 = 𝐼0𝑒−𝑡𝜏
𝑣𝑅 𝑡 = 𝑖𝐿 𝑡 × 𝑅
= 𝐼0𝑅𝑒−𝑡𝜏
Power dissipated in the resistor
Source Free RL Circuits
𝑝 𝑡 = 𝑣𝑅 𝑡 × 𝑖𝐿 𝑡 = 𝐼02𝑅𝑒
−2𝑡𝜏
54
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
Source Free RL Circuits
Energy dissipated by the resistor
𝑝 𝑡 = 𝑣𝑅 𝑡 × 𝑖𝐿 𝑡 = 𝐼02𝑅𝑒
−2𝑡𝜏
𝑤 𝑡 = න0
𝑡
𝑝 𝑡 𝑑𝑡
= 𝐼02𝑅න
0
𝑡
𝑒−2𝑡𝜏 𝑑𝑡 = 𝐼0
2𝑅−𝐿
2𝑅𝑒−2𝑡𝜏
0
𝑡
=𝐼02𝐿
21 − 𝑒
−2𝑡𝜏
55
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
Source Free RC Circuits
𝑖𝐿 𝑡 = 𝐼𝑓 − 𝐼𝑓 − 𝐼𝑖 𝑒−𝑡𝜏
𝐼𝑖 = 𝑖𝐿 0 = 𝐼0
𝑖𝐿 𝑡 =𝐸
𝑅−
𝐸
𝑅− 𝐼0 𝑒
−𝑡𝜏
𝜏 =𝐿
𝑅𝐼𝑓 =
𝐸
𝑅
→ 𝑖𝐿 𝑡 =𝐸
𝑅1 − 𝑒−
𝑡𝜏
56
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
Source Free RC Circuits
𝑖𝐿 𝑡 = 𝐼𝑓 − 𝐼𝑓 − 𝐼𝑖 𝑒−𝑡𝜏
𝐼𝑖 = 𝑖𝐿 0 = 𝐼0
𝑖𝐿 𝑡 =𝐸
𝑅−
𝐸
𝑅− 𝐼0 𝑒
−𝑡𝜏
𝜏 =𝐿
𝑅𝐼𝑓 =
𝐸
𝑅
→ 𝑖𝐿 𝑡 =𝐸
𝑅1 − 𝑒−
𝑡𝜏
57
-
Transient Analysis
Dr. Mohamed Refky
Time Domain Analysis 1st Order Systems
Source Free RC Circuits
𝑖𝐿 𝑡 =𝐸
𝑅1 − 𝑒−
𝑡𝜏
𝑣𝑅 𝑡 = 𝑅 × 𝑖𝐿 𝑡
= 𝐸 1 − 𝑒−𝑡𝜏
𝑣𝐿 𝑡 = 𝐿𝑑𝑖𝐿 𝑡
𝑑𝑡= 𝐸 − 𝑣𝑅 𝑡
= 𝐸𝑒−𝑡𝜏
58
-
Transient Analysis
Dr. Mohamed Refky
Example (6)For the shown circuit, switch has been closed for a long time and
is opened at 𝑡 = 0. Calculate 𝑖𝐿(𝑡) for 𝑡 > 0.
59
-
Transient Analysis
Dr. Mohamed Refky
Example (7)For the shown circuit, switch has been opened for a long time and
is closed at 𝑡 = 0. find 𝑖𝑅, 𝑣𝑜, and 𝑖𝐿 for all time.
60
-
Transient Analysis
Dr. Mohamed Refky
Example (8)For the shown circuit, switch has been closed for a long time and
is opened at 𝑡 = 0. find 𝑖𝐿(𝑡) for 𝑡 > 0.
61