introduction to c-13 nmr

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nucleus is present in only 1.08% natural abundance. Therefore, tion of a spectrum usually takes much longer than in 1 H NMR. netogyric ratio of the 13 C nucleus is about 1/4 that of the 1 H nucleu re, the resonance frequency in 13 C NMR is much lower than in 1 H NMR. for 13 C as opposed to 300 MHz for 1 H in a 7.04 Tesla field). e lower frequencies, the excess population of nuclei in the lower s ced, which, in turn, reduces the sensitivity of NMR detection. 1 H NMR, the area of a peak is not proportional to the number of giving rise to the signal. Therefore, integrations are usually no ique carbon in a molecule gives rise to a 13 C NMR signal. Therefore e are fewer signals in the spectrum than carbon atoms in the compou ecule must possess symmetry. nning a spectrum, the protons are usually decoupled from their resp to give a singlet for each carbon atom. This is called a proton-d m. Introduction to C-13 NMR

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Introduction to C-13 NMR. The 13 C nucleus is present in only 1.08% natural abundance. Therefore, acquisition of a spectrum usually takes much longer than in 1 H NMR. The magnetogyric ratio of the 13 C nucleus is about 1/4 that of the 1 H nucleus. - PowerPoint PPT Presentation

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Page 1: Introduction to C-13 NMR

• The 13C nucleus is present in only 1.08% natural abundance. Therefore, acquisition of a spectrum usually takes much longer than in 1H NMR. • The magnetogyric ratio of the 13C nucleus is about 1/4 that of the 1H nucleus. Therefore, the resonance frequency in 13C NMR is much lower than in 1H NMR. (75 MHz for 13C as opposed to 300 MHz for 1H in a 7.04 Tesla field). • At these lower frequencies, the excess population of nuclei in the lower spin state is reduced, which, in turn, reduces the sensitivity of NMR detection.

• Unlike 1H NMR, the area of a peak is not proportional to the number of carbons giving rise to the signal. Therefore, integrations are usually not done.

• Each unique carbon in a molecule gives rise to a 13C NMR signal. Therefore, if there are fewer signals in the spectrum than carbon atoms in the compound, the molecule must possess symmetry.

• When running a spectrum, the protons are usually decoupled from their respective carbons to give a singlet for each carbon atom. This is called a proton-decoupled spectrum.

Introduction to C-13 NMR

Page 2: Introduction to C-13 NMR

http://www.chemistry.ccsu.edu/glagovich/teaching/316/nmr/images/fig15.gif

Carbon-13 Chemical Shift Table

CC triple bonds

Page 3: Introduction to C-13 NMR

Alkane: 2-methylpentane

Page 4: Introduction to C-13 NMR

Alcohol: 2-hexanol

OH

Page 5: Introduction to C-13 NMR

Br

Alkyl Halide: 3-bromopentane

Page 6: Introduction to C-13 NMR

Alkene: 1-hexene

Page 7: Introduction to C-13 NMR

Aromatic Ring: eugenol

HO

O

Page 8: Introduction to C-13 NMR

Carboxylic Acid: pentanoic acid

CO2H

Page 9: Introduction to C-13 NMR

Ester: ethyl valerate

O

O

Page 10: Introduction to C-13 NMR

Amide: pentanamide

O

NH2

Page 11: Introduction to C-13 NMR

Ketone: 3-methyl-2-pentanone

O

Page 12: Introduction to C-13 NMR

Aldehyde: 2-methylpentanal

O

H

Page 13: Introduction to C-13 NMR

Symmetry in C-13 NMREach unique carbon in a molecule gives rise to a 13C NMR signal. Therefore,if there are fewer signals in the spectrum than carbon atoms in the compound,the molecule must possess symmetry. Examples:

CH2CH3CH3CH2 OH

Page 14: Introduction to C-13 NMR

Enantiotopic vs Diastereotopic CH3’s

*

O

O

CH3

enantiotopic

*

*

* *

diastereotopic

OH

Page 15: Introduction to C-13 NMR

Determine the number of signals in the proton-decoupledC-13 NMR spectrum of each of the following compounds:

H3C

CH3

O

CH3

OH

CH3

NH

OCH3OCCH3

O

HO

OH

H3C CH3

CH3

Page 16: Introduction to C-13 NMR

ppm Carbon #139.07 1 131.62 2 124.07 3 123.71 4 59.16 5 39.64 6 26.51 7 25.66 8 17.66 9 16.24 10

8

9

Carbon-13 NMR Spectrum of Geraniol

Page 17: Introduction to C-13 NMR

T1 and NOE Effects in C-13 NMRBecause of unequal T1 and NOE effects, peaks heights vary widely in C-13 NMR.This is why C-13 spectra are normally not integrated.

Carbon T1 (sec) NOE

CH3 16 0.61

1 89 0.56

2 24 1.6

3 24 1.7

4 17 1.6

CH31

2

34

1

2

3

4

CH3

Page 18: Introduction to C-13 NMR

Carbon-13 Proton-Coupled Patterns

http://www.chemistry.ccsu.edu/glagovich/teaching/316/nmr/13ccoupled.html

Page 19: Introduction to C-13 NMR

Carbon-13 Proton-Coupled Spectrum of Ethyl Phenylacetate

Typical coupling constants for 13C-1H one-bond couplings are between 100 to 250 Hz.

http://www.chemistry.ccsu.edu/glagovich/teaching/316/nmr/13ccoupled.html

O

O

Difficult to interpret

C=O

Page 20: Introduction to C-13 NMR

DEPT Spectra

normal C-13 spectrum

DEPT-45

DEPT-90

DEPT-135

C

CH CH2 CH3

Quaternary carbons (C) do not show up in DEPT.

Page 21: Introduction to C-13 NMR

O

O

Simulated DEPT Spectra of Ethyl Phenylacetate

Normal C-13 spectrum

DEPT-45

DEPT-90

DEPT-135O

O

Page 22: Introduction to C-13 NMR

DEPT Spectra of Codeine

Page 23: Introduction to C-13 NMR

Predict the normal C-13, DEPT-90, and DEPT-135 spectra of ipsenol, whose structure appears below.

Page 24: Introduction to C-13 NMR

www.lasalle.edu/~price/DEPT%20and%20COSY%20Spectra.ppt

DEPT Spectra of Ipsenol

Normal C-13 spectrum

CDCl3

DEPT-135

DEPT-90

Page 25: Introduction to C-13 NMR

Determine the number and appearance of the signals in the DEPT-45, DEPT 90, and DEPT 135 NMR spectrum of each of the following compounds:

H3C

CH3

O

CH3

OH

CH3

NH

OCH3OCCH3

O

HO

OH

H3C CH3

CH3