inverse operations (x&/) by: me math period 2. benchmark: topic #22: benchmark:ma.7.2.3: apply...
TRANSCRIPT
Inverse Operations (x&/)
By: Me
Math Period 2
Benchmark:
Topic #22:Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction, and multiplication and division, to solve one- step problems.
Definition:
Operations that “undo” each other. Multiplying and dividing are inverse operations and so are addition and subtraction.
Example/ Drawing/ Formula:First you do the inverse of multiplying 3 which is dividing
3. That cancels out. Then I do 6/3, which equals 2. Next, you take the 9x and divide by 9 which now means you are left with x. Now you bring the 2
down and divide 2 and 9 (2/9). Therefore, x= 2/9.
Equation: 9x * 3 = 6 9x * 3 = 6
/3 /3 9x 9x = 2 /9 /9
x = 2/9
Create A Question:
Can you solve this equation?
My Question:
14x / 4 = 7
Solution to question:
x= 2
How did I get 2? Here… look at this
Explanation To Question:
What you have to do is do the inverse of dividing 4 which is multiplying 4. That cancels out. Then you do the same to the other side. 7x4=28. Bring that down(28). Next, 14x/14equals it canceling out. X is left over. So, 28/14=2. Therefore, x=2.
14x / 4 = 7
Credits:
I would like to thank:
Google (for the images)Mr. Imamura (for the math)Kahiki ( for helping me to put the image as the background)Mom( for letting me use the computer)
Thank you for watching!!!