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Irwin, Basic Engineering Circuit Analysis, 9/E 1

Chapter 6: Energy Storage Elements: The Capacitor and the Inductor Problem 6.1

6.1

Ch06.indd 1Ch06.indd 1 12/23/08 1:33:17 PM12/23/08 1:33:17 PM



6.2




6.3




6.4




6.5

Figure P6.5

P6.5.




6.6

Figure P6.6

P6.6.




6.7

Figure P6.7

P6.7.




6.8

Figure P6.8

P6.8.




6.11

Figure P6.11

P6.11.




6.12

Figure P6.12

P6.12.




6.15

Figure P6.15

P6.15a P6.15b.




6.16

Figure P6.16

P6.16,




6.18




6.20




6.22



-





6.24

Figure P6.24

P6.24.



t





6.25

Figure P6.25

P6.25.




6.26

Figure P6.26

P6.26.




6.29

Figure P6.29

P6.29.




6.31

Figure P6.31

P6.31.




6.32

Figure P6.32

The waveform for the current in the 2-H inductor shown in Fig. P6.32a is given in Fig. P6.32b. Determine the

following quantities (a) the energy stored in the inductor at t = 1.5 ms, (b) the energy stored in the inductor

at t = 7.5 ms, (c) vL(t) = 1.5 ms, (d) v

L(t) at t = 6.25 ms, and (e) v

L(t) at t = 2.75 ms.

Ch06.indd 54Ch06.indd 54 12/24/08 9:07:34 AM12/24/08 9:07:34 AM



6.33




6.36

Figure P6.36

6.36




6.37

Figure P6.37

P6.37a

P6.37b,



/





6.38

Figure P6.38

P6.38



c





6.41




6.42




6.44




6.45




6.46




6.49

Figure P6.49

P6.49.




6.50

Figure P6.50

P6.50




6.51

Figure P6.51

P6.51




P6.52




6.53

Figure P6.53

P6.53.




6.54

Figure P6.54

P6.54.




6.58

Figure P6.58

6.58.




6.60

Figure P6.60

P6.60.




6.61

Figure P6.61

P6.61




6.65

Figure P6.65

P6.65




6.66




6.67

Figure P6.67

P6.67,




6.68

Figure P6.68

P6.68




For the network in the Fig. P6.69 below, vS1 (t) = 80 cos 324t V and

vS2 (t) = 40 cos 324t V. Find v

o(t).

Ch06.indd 115Ch06.indd 115 12/24/08 9:07:34 AM12/24/08 9:07:34 AM



6.72

Figure P6.72

P6.72



3




SOLUTION:

The correct answer is a.Yes. The capacitors should be connected as shown.

F�2 F�4

F�6

eqC

FCeq ��

366

)6(6�

��

Chapter 6: Energy Storage Elements: The Capacitor and the Inductor Problem 6FE-1



SOLUTION:

The correct answer is c.

�� dttitq )()(

��

��

��

��

stCstCt

tCtq

��

1,6

10,6

0,0

)(

Ctqtv )(

)( �

��

��

��

�

�stV

stVtxtV

tv�

�1,6

10,106

0,0

)( 6

)(2

1)( 2 tvCtw �

��

��

��

�

�stJ

stJtxtJ

tw��

�1,18

10,1018

0,0

)( 26




SOLUTION:

The correct answer is b.

The voltage across the unknown capacitor Cx is (using KVL):

xV�� 824

VVx 16�vCq �

The capacitors are connected in series and the charge is the same.

Cq �� 480)8(60 ��

FvqCx ��

3016

480��




SOLUTION:

mH6

eqLmH12

mH3

mH3 mH9

mH2

The correct answer is d. � mmmmmmLeq 2]36]12)93[([ ��

� mmmmmLeq 2]36]12)12[([ ��

� mmmmLeq 2]366[ ��

mmmLeq 2]33[ ��

mmLeq 25.1 ��

mHLeq 5.3�




SOLUTION:

The correct answer is a.

dttdiLtv )(

)( �

tttt teeetedttdi 2222 402020)2(20)( ��

� �tt teemtv 22 402010)( ��

��

�

��

�� 0,4.02.0

0,0)(

22 tVteetV

tv tt



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