Compute the mean and standard deviation Number of cases 9To find the mean, add all of the observations and divide by 9Mean 1.022222Squared deviations(1.2-(1.022222))^2 = (0.177778)^2 = 0.031605(0.8-(1.022222))^2 = (-0.222222)^2 = 0.049383(0.6-(1.022222))^2 = (-0.422222)^2 = 0.178272(1.1-(1.022222))^2 = (0.077778)^2 = 0.006049(1.2-(1.022222))^2 = (0.177778)^2 = 0.031605(0.9-(1.022222))^2 = (-0.122222)^2 = 0.014938(1.5-(1.022222))^2 = (0.477778)^2 = 0.228272(0.9-(1.022222))^2 = (-0.122222)^2 = 0.014938(1-(1.022222))^2 = (-0.022222)^2 = 0.000494Add the squared deviations and divide by 8

Variance = 0.555556 / 8Variance 0.069444Standard deviation = sqrt(variance) = 0.263523

Mean 1.0222Standard deviation =0.2635

H0: μ = 1.1Ha: μ ≠ 1.1Sample mean = 1.0222Standard deviation = 0.2635Standard error of mean = s / √ nStandard error of mean = 0.2635 / √ 9SE = 0.2635/3Standard error of mean 0.0878t = (xbar- μ ) / SEt = (1.0222-1.1) / 0.0878t = -0.8858

From the t-table (assuming a significance level of 5%) with 8 degrees of freedom, the critical value of |t| is 2.306.Calculated |t| = 0.8858Since calculated t < critical t, do not reject the null hypothesis.The mean weight is not different from 1.1.

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