jawaban tugas1-142
DESCRIPTION
Tugas jaringan komputer lanjutTRANSCRIPT
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Tugas 3
Jaringan Komputer Lanjutkelompok 4
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Jawab soal 1
Host A = 62 hostnetID awal = 192.168.30.0/28netmask = 255.255.255.192/26netID = 192.168.30.0/26Broadcast = 192.168.30.63/26RIP = 192.168.30.1 - 192.168.30.62
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Host C1 = 25 hostnetID awal = 192.168.30.64/27netmask = 255.255.255.224netID = 192.168.30.64Broadcast = 192.168.30.95RIP = 192.168.30.65 - 192.168.30.94
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Host C2 = 25 hostnetID awal = 192.168.30.96/27netmask = 255.255.255.224netID = 192.168.30.96Broadcast = 192.168.30.127RIP = 192.168.30.97 - 192.168.30.126
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Host B1 = 14 hostnetID awal = 192.168.30.128/28netmask = 255.255.255.240netID = 192.168.30.128Broadcast = 192.168.30.143RIP = 192.168.30.129 - 192.168.30.142
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Host B2 = 14 hostnetID awal = 192.168.30.144/28netmask = 255.255.255.240netID = 192.168.30.144Broadcast = 192.168.30.159RIP = 192.168.30.145 - 192.168.30.158
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Host D1 = 2 hostnetID awal = 192.168.30.160/30netmask = 255.255.255.252netID = 192.168.30.160Broadcast = 192.168.30.163RIP = 192.168.30.161 - 192.168.30.162
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Host D2 = 2 hostnetID awal = 192.168.30.164/30netmask = 255.255.255.252netID = 192.168.30.164Broadcast = 192.168.30.167RIP = 192.168.30.165 - 192.168.30.166
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Host D3 = 2 hostnetID awal = 192.168.30.168/30netmask = 255.255.255.252netID = 192.168.30.168Broadcast = 192.168.30.171RIP = 192.168.30.169 - 192.168.30.170
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Host D4 = 2 hostnetID awal = 192.168.30.172/30netmask = 255.255.255.252netID = 192.168.30.172Broadcast = 192.168.30.175RIP = 192.168.30.173 - 192.168.30.174
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Jawab soal 2
Jaringan CJumlah Host =50
Jaringan EJumlah Host =25
R1
R2
R3
IP awal yang diberikan adalah 10.252.1.0
10.252.1.0/26
10.252.1.100/30 10.252.1.96/30
10.252.1.64/27
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Jaringan C dengan 50 HostNetmask = 255.255.255.192Net id = 10.252.1.0Broadcast = 10.252.1.63Range IP = 1-62
Jaringan E dengan 25 HostNetmask = 255.255.255.224Net id = 10.252.1.64Broadcast = 10.252.1.95Range IP = 65-94
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Jaringan R1 - R2 2 HostNetmask = 255.255.255.252Net id = 10.252.1.100Broadcast = 10.252.1.103Range IP = 101 - 102
Jaringan R2 - R3 2 HostNetmask = 255.255.255.252Net id = 10.252.1.96Broadcast = 10.252.1.99Range IP = 97 - 98
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Jawab soal 3
Router A
Router CRouter B
Router D Router E
Router F Router G
Subnet X1 Subnet X2
Subnet X3Host =25
Subnet X4Host=10
Subnet X5Host=12
Subnet X6Host=9
INTERNET
IP Awal : 202.134.0.0
202.134.0.0/27 202.134.0.32/28 202.134.0.48/28 202.134.0.64/28
202.134.0.80/30 202.134.0.84/30 202.134.0.88/30 202.134.0.92/30
202.134.0.96/30 202.134.0.100/30
202.134.0.104/30 202.134.0.108/30
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Jawab soal 4
Router A
INTERNET
Router C Router BRouter D
Router E
Router F Router G
Subnet A IP Total =16
IP Total =16
IP Total =16
IP Total =32
Subnet C Subnet D
Subnet E Subnet F
IP Total =8
IP Total =4
IP Awal : 200.192.2.0
200.192.2.96/29
200.192.2.104/29
200.192.2.112/29
200.192.2.48/28 200.192.2.64/28
200.192.2.116/30
200.192.2.80/29 200.192.2.88/29
200.192.2.0/27 200.192.2.32/28
Subnet B IP Total =8
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Jawab soal 5
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• LaboratoriumNetmask = 255.255.0.240 net id = 10.192.1.0/28broadcast = 10.192.1.15Range ip = 1-14
• AdministrasiNetmask = 255.0.0.248 net id = 10.192.2.0/29broadcast = 10.192.2.7Range ip = 1-6
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• Teknik ElektroNetmask = 255.255.0.240 net id = 10.192.3.0/28broadcast = 10.192.3.15Range ip = 1-14
• Teknik InformatikaNetmask = 255.255.0.240 net id = 10.192.4.0/28broadcast = 10.192.4.15Range ip = 1-14