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P1 = n n 1+ 2 q= 3 + 10 E B 30 C F 50 30 30 40 40 A D 2 m 6 m 2 m Jika material yang digunakan struktur tersebut adalah beton bert , hitung dan gambar Bidang Momen, Bidang Gaya Lintang dan Bidang Gaya Normal konstruksi diatas (Selesaikan dengan Metode Slope Deflection dan Metode Cross PORTAL MENGALAMI PERGOYANGAN A METODE SLOPE DEFLECTIONS DIMENSI PENAMPANG Balok BC ; b = 30 cm = 0.3 m h = 50 cm = 0.5 m kolom AB ; b = 30 cm = 0.3 m h = 40 cm = 0.4 m kolom CD ; b = 30 cm = 0.3 m h = 40 cm = 0.4 m INERSIA PENAMPANG Balok BC ; Ix = 1 * b * 12 = 0.083 * 0.3 * 0.5 = 0.003125 h 3 m 4

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SOAL DAN PENYELESAIAANP1 =nn1+2q=3+10EB30CF5030304m4040AD2m6m2mJika material yang digunakan struktur tersebut adalah beton bertulang, hitung dan gambar Bidang Momen, Bidang Gaya Lintang dan Bidang Gaya Normal konstruksi diatas (Selesaikan dengan Metode Slope Deflection dan Metode Cross PORTAL MENGALAMI PERGOYANGANAMETODE SLOPE DEFLECTIONSDIMENSI PENAMPANGBalokBC;b=30cm=0.3mh=50cm=0.5mkolomAB;b=30cm=0.3mh=40cm=0.4mkolom CD;b=30cm=0.3mh=40cm=0.4mINERSIA PENAMPANGBalokBC;Ix=1*b*h312=0.0833333333*0.3*0.53=0.003125m4kolomAB;Ix=1*b*h312=0.0833333333*0.3*0.43=0.00160m4kolomCD;Ix=1*b*h312=0.0833333333*0.3*0.43=0.0016m4PERBANDINGAN INERSIAEbeton=2000000t/m2BalokBC;CB=0.00313m4=6250=1.95EIkolomAB;BA=0.0016m4=3200=1EIkolomCD;DC=0.0016m4=3200=1EIPEMBEBANAN DAN JARAKn=9JARAKLBE;LEB=2mBEBANLBC;LCB=6mq1=3.9t/m'LBA;LAB=4mP1=5.5tLCD;LDC=4mq2=3.9tLCF;LFC=2mMOMEN PRIMERq=3.9t/m'5.5tMFDCMFCBMFCFEB1.95EICFMFBEMFCDMFBA4m1EI1EIMFABMFDCAD2m6m2mJOINT AMFAB=0( Tidak ada beban )JOINT BMFBA=0( Tidak ada beban )MFBE=+P1*LBE=+5.5*2=+11tmMFBC=-1*qCD*LBC212=-0.08*3.9*62=-11.70tmJOINTCMFCD=0( Tidak ada beban )MFCF=Qcf*0.5LCf=7.8*0.52=-7.8tmMFCB=11.7tmjepit dMFDC=0( Tidak ada beban )MOMEN AKHIRq=3.905.5MbCMCBMCFEB1.95EICFMBEMCDMBA41EI1EIMABMDCAD2m6m2mA=0(PELETAKAN JEPIT)D=0(PELETAKAN JEPIT)JEPIT AMAB=MFAB+EI(B-31)LAB=0+1(B-311)44=0.25(B-0.751)=0.25B-0.191JOINT BMBE=11TmMBA=MFAB+EI(2B-31)LAB=0+1(2B-311)44=0.25(2B-0.751)=0.5B-0.191MBC=MFBC+EI(2B+C)LBC=-11.70+1.953125(2B+C)6=-11.70+0.3255208333(2B+C)=-11.70+0.6510416667B+0.33CSYARAT BATAS MB=0MB=MBE+MBA+MBC(11) + (0.5B-0.191) + (-11.7+0.6510416667B+0.3255208333C)-0.70+1.1510416667B+0.3255208333C-0.191=01.15B+0.33C-0.191=0.70PERSAMAAN 1JOINT CMCF=-7.8TmMCD=MFCD+EI(2C-31)LAB=0+1(2C-311)44=0.25(2C-0.751)=0.5C-0.191MCB=MFCB+EI(2C+B)LBC=11.70+1.95(2C+B)6=11.7+0.3255208333(2C+B)=11.7+0.65C+0.33BSYARAT BATAS MC =0MC =MCF+MCD+MCB(-7.8) + (0.5C-0.191) + (11.7+0.6510416667C+0.3255208333B)3.90+1.1510416667C+0.3255208333B-0.191=01.1510416667C+0.33B-0.191=-3.90PERSAMAAN 2JEPIT DMDC=MFDC+EI(C-31)LDC=0+1(C-311)44=0.25(C-0.751)=0.25c-0.191H= 0MAB+MBA+MCD+MDCLABLCDMAB=0.25b-0.191Mcd=0.5c-0.191MBA=0.5b-0.191+MDc=0.25c-0.191+=0.75b-0.3751=0.75c-0.37510.75b-0.3751+0.75c-0.3751=0440.75b+0.75c-0.751=40.1875b+0.19c-0.191=0persamaan 3BC11.15104166670.33-0.19B=0.700.331.1510416667-0.19XC=-3.900.18750.19-0.191=01.0595789427-0.1517775242-0.90780141841.150.33-0.191.0595789427-0.1517775242-0.90780141840.70-0.15177752421.0595789427-0.9078014184X0.331.15-0.19=-0.15177752421.0595789427-0.9078014184X-3.900.90780141840.9078014184-7.14893617020.190.19-0.190.90780141840.9078014184-7.14893617020.001-2.77555756156289E-170B1.33010XC=-4.240011-2.90B=1.33C=-4.241=-2.90JEPIT AMAB=0.25B-0.191=0.251.33-0.19-2.90=0.330.54=0.88TMJOINT BMBA=0.50B-0.191=0.501.33-0.19-2.90=0.67+0.54=1.21MBC=-11.70+0.65B+0.33C=-11.70+0.651.33+0.33-4.24=-11.70+0.87+-1.38=-12.21tmMBE=11tmKONTROL MOMENMBE+MBC+MBA=011+-12.21+1.21=0.00OKJOINT cMcd=0.5C-0.191=0.50-4.24-0.19-2.90=-2.12+0.54=-1.57Mcb=11.7+0.65C+0.33B=11.70+0.65-4.24+0.331.33=11.70+-2.76+0.43=9.37tmMcf=-7.8tmKONTROL MOMENMcf+Mcb+Mcd=0-7.80+9.37+-1.57=0.00OKJEPIT Dmdc=0.25c-0.191=0.25-4.24-0.19-2.90=-1.06+0.54=-0.51tmFREE BODYq=3.90t/m'q=3.90t/m'5.5MBEMbCMCBMCFEBB1.95EICCF11.012.219.377.8RBERBCRCBRCF5.57.8RBARCDBC1.21MBA1.57MCD41EI1EIMAB0.880.51MDCRABARDCD2m6m2mREAKSI PELETAKAN1BENTANG BCRBC=6RBC-MBC+MCD-QBC* 1/2 LBC=06RBC-12.21+9.37-70.2=06RBC-73.04=06RBC6RBC=73.04RBC=12.1728132388RCB=-6RCB-MBC+MCD+QBC* 1/2 LBC=0-6RCB-12.21+9.37+70.2=0-6RCB67.36=0-6RCB-6RCB=-67.36RCB=11.2271867612KONTRLRBC+RCB-QBC=012.17+11.23-23.40=0.00OK2BENTANG ABRAB=-4RAB+MAB+MBA=0-4RAB+0.88+1.21=0-4RAB+2.09=0-4RAB-4RAB=-2.09RAB=0.5223974763RBA=-4RBA+MAB+MBA=0-4RBA+0.88+1.21=0-4RBA+2.09=0-4RBA-4RBA=-2.09RBA=0.52239747633BENTANG CDRDC=-4RDC-MDC-MCD=0-4RDC-0.51-1.57=0-4RDC-2.09=0-4RDC-4RDC=2.09RDC=-0.5223974763RDC=0.5223974763RCD=-4RCD-MABMBA=0-4RCD-0.51-1.57=0-4RCD-2.09=0-4RCD-4RCD=2.09RCD=-0.5223974763RCD=0.5223974763
bidang md nFREE BODYq=3.90t/m'q=3.90t/m'5.5MBEMbCMCBMCFEBB1.95EICCF11.012.219.377.8RBERBCRCBRCF5.5012.1711.237.8RBARCDB0.520.5223974763C1.21MBA1.57MCD41EI1EIMAB0.880.51MDCRABADRDC0.520.522m6m2mGAMBAR BIDANG MGAMABAR LIHAT ANGKA N = 6-9GAMABAR LIHAT ANGKA N = 0-4GAMBAR BIDANG M11.07.87.812.219.379.3711.012.2117.5517.551.211.571.211.570.880.510.880.51GAMBAR BIDANG D12.177.85.50GAMBAR BIDANG D11.2312.170.520.527.85.500.520.5211.230.520.520.520.520.520.5217.6719.0317.6719.03