jms-4 paper -1

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JMS – 4 PAPER – 1 http://www.chemistrycrest.com/ Page 1 PAPER-1 Maximum Marks: 80 Question paper format and Marking scheme : 1. In Section I ( Total Marks: 21), for each question you will be awarded 3 marks if you darken ONLY the bubble corresponding to the correct answer and zero marks if no bubble is darkened. In all other cases, minus one (–1) mark will be awarded. 2. In Section II (Total Marks: 16), for each question you will be awarded 4 marks if you darken ALL the bubble(s) corresponding to the correct answer(s) ONLY and zero marks other wise. There are no negative marks in this section. 3. In Section III (Total Marks: 15), for each question you will be awarded 3 marks if you darken ONLY the bubble corresponding to the correct answer and zero marks if no bubble is darkened. In all other cases, minus one (–1) mark will be awarded. 4. In Section IV (Total Marks: 28), for each question you will be awarded 4 marks if you darken ONLY the bubble corresponding to the correct answer and zero marks otherwise. There are no negative marks in this section.

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Page 1: JMS-4 PAPER -1

JMS – 4 PAPER – 1

http://www.chemistrycrest.com/ Page 1

PAPER-1 Maximum Marks: 80 Question paper format and Marking scheme: 1. In Section I ( Total Marks: 21), for each question you will be awarded 3 marks if you darken ONLY the bubble corresponding to the correct answer and zero marks if no bubble is darkened. In all other cases, minus one (–1) mark will be awarded. 2. In Section II (Total Marks: 16), for each question you will be awarded 4 marks if you darken ALL the bubble(s) corresponding to the correct answer(s) ONLY and zero marks other wise. There are no negative marks in this section. 3. In Section III (Total Marks: 15), for each question you will be awarded 3 marks if you darken ONLY the bubble corresponding to the correct answer and zero marks if no bubble is darkened. In all other cases, minus one (–1) mark will be awarded. 4. In Section IV (Total Marks: 28), for each question you will be awarded 4 marks if you darken ONLY the bubble corresponding to the correct answer and zero marks otherwise. There are no negative marks in this section.

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SECTION – I (Total Marks : 21) (Single Correct Answer Type)

This section contains 7 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct.

1. Correct acidic strength order of the following is

COOH

1

COOH

Cl

2

COOH

3

CH3

COOH

4

OMe

(A) 3 > 2 > 4 > 1 (B) 4 > 2 > 1 > 3 (C) 2 > 3 > 4 > 1 (D) 2 > 1 > 3 > 4 2. Match the following List–I List – II (Sol) (Nature) 1) Starch sol P) Lyophilic 2) Gold sol Q) Lyophobic 3) Sulphur R) Multimolecular 4) Natural Rubber S) Macromolecular T) Negatively charged A) 1 - P,T; 2 - R,T; 3 - Q; 4 - S,T B) 1 - P,S,T; 2 - Q,R,T; 3 - R; 4 - P,T C) 1 - S,T; 2 - Q,T; 3 - R; 4 - P,T

D) 1 - P,Q,T; 2 - S,R,T; 3 - P,S; 4 - P,T 3. Compound (A), 5 10 4C H O is oxidized by 2 2Br H O− to the acid, 5 10 5C H O which readily forms a

lactone. (A) forms a triacetate with 2Ac O and a hydrazone with 2PhNHNH . ‘A’ is oxidized by 4HIO when only one molecule of it is consumed. The structure of ‘A’ is

A)

CHO

(CHOH)3

CH2OH

B)

CHO

( )2CHOH

2CH OH

CO

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C) CHO

C

C

C

2CH OH

H

H OH

OH

O

D)

( )2HOH C CH CH OH CHO− − −

2CH OH

4. To 500 ml of 2 M impure H2SO4 sample, NaOH solution 1 M was slowly added & the following plot was obtained. The percentage purity of H2SO4 sample and slope of the curve respectively are

vol. of NaOH added(L)

1.5

1.0

0.5

)Hof(mol +

A) 50%, B) 75%,

C) 75%, –1 D) none of these

5. IP/EA ratio for bromine is 103

. Its electronegativety is 2.8. Its electron affinity on Mulliken’s scale

in kJ/mol is,

A) 81 B) 93 C) 162 D) 351

6. +

NaOD / D O2

?

(A) (B)

(C) (D)

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7. Match the following Column–I Column – II A) Wurtzite structure P) Anions occupy F.C.C lattice B)Zinc Blende Structure Q) Closest packed structure C)Antifluorite structure R) Anions occupy HCP lattice

D)Rocksalt structure S) Cations occupy half/alternate tetrahedral voids A) A-R,S; B-P, R,S; C-S; D-P, B) A-Q,R,S; B-P,Q,S; C-P,Q; D-P,Q C) A-Q, B-P; C-S; D-R D) A-P,Q,S; B-R,; C-S; D-P,

SECTION – II (Total Marks : 16) (Multiple Correct Answers Type)

This section contains 4 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONE OR MORE may be correct. 8. Which of the following statements are true. A) The ratio of the velocity of electron in first three Bohr orbits of hydrogen atom is 2:3:6 respectively B) The ratio of magnitude of Total Energy:Kinetic Energy:Potential Energy for any orbit is 1:1:2 C) The wavelength of a green light is 500 nm, then its frequency is 6 x 1014 Hz

D) The ratio of de-broglie wavelength of a ‘H’ atom, ‘He’ atom and CH4 molecule moving with equal kinetic energy is 4:2:1

9. Among the following orbital interactions, those which represents hyper conjuction interaction.

A) B)

C) D)

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10. Which of the following is true about the complex [PtCl2(NH3)(OH2)] ; [Atomic no. of Pt = 78] (i) It will have two geometrical isomeric forms, cis and trans (ii) The hybridisation state of Pt(II) is sp3 (iii) It is a square planar complex (iv) It is a diamagnetic complex (v) It can show hydrate isomerism (vi) It is a tetrahedral complex (A) (i), (iii) (B) (ii),(v) (C) (ii),(vi) (D)(i v)

11. The polarimeter readings in an experiment to measure the rate of inversion of cane sugar (1st order reaction) were as follows

time (min) : 0 30 ∞ angle (degree) : 30 20 – 15

Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84 (A) The half life of the reaction is 82.7 min

(B) The solution is optically inactive at 131 min. (C) The equimolar mixture of the products is dextrorotatory

(D) The angle would be 7.5° at half time

SECTION-III (Total Marls : 15) (Paragraph Type)

This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on the other paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct.

Paragraph for Question Nos. 12 to 13

A chemist opened a cupboard to find four bottles containing water solutions, each of which had

lost its label. Bottles 1, 2, 3 contained colourless solutions, while bottle 4 contained a blue solution. The labels from the bottles were lying scattered in the floor of the cupboard. They were :

Copper (II) sulphate, Hydrochloric acid Lead nitrate, Sodium carbonate By mixing samples of the contents of the bottles, in pairs, the chemist made the following

observations. Bottle 1 + Bottle 2 White precipitate Bottle 1 + Bottle 3 White precipitate Bottle 1 + Bottle 4 White precipitate Bottle 2 + Bottle 3 Colourless gas evolved Bottle 2 + Bottle 4 No visible reaction Bottle 3 + Bottle 4 Blue precipitate 12. Bottle 3 contains (A) copper (II) sulphate (B) hydrochloric acid (C) lead nitrate (D) sodium carbonate

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13. When bottle 1 is mixed with bottle 4, white precipitate is observed, which is (A) PbSO4 (B) PbCO3

(C) PbCl2 (D) Pb(NO3)2.

Paragraph for Question Nos. 14 to 16

A is a hydrocarbon with molecular formula C6H10. It reacts with Br2 to give B. With Zn/ethanol B gives A and with alcoholic KOH, B gives C. C, A differ from each other with respect to sites of unsaturation.

14. Compound A maybe (A) (B)

CH3

CH3

(C) (D) CH = CH CH CH CH =CH

2 2 2 2− − −

CH2

15. Which of the following gives a dialdehyde on ozonolysis? (A) only A (B) A and B (C) Only C (D) A and C 16. Which of the following reactions cannot generate either A or B or C? (A) (B)

OH

+H∆

CH2

+H∆

→OH

(C)

PBr

2→

OH

OH (D)

+H∆

OH

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SECTION-IV (Total Marks : 28) (Integer Answer Type)

This section contains 7 questions. The answer to each of the questions is a single digit integer, ranging from 0 to 9. The bubble corresponding to the correct is to be darkened in the ORS.

17. (No of P–O–P bonds in P4O6) + (No of B–O–B bonds in borax) – (No of S–O–S bonds in γγγγ form of SO3) is

18. The total number of optically active alkynes having molecular formula C3FClBrI is

19. Among the following diazonium salts, those less reactive than (I) towards coupling reaction are

20. No of metals that can be extracted by carbon reduction method is Na, Al, Mg, Sn, Fe, Pb, Zn, Ca 21. 3000 ml sample of H2O2 has 5.6 volume strength. If this sample liberates 5.6 litre of O2 at 1 atm

& 273 K, then molarity of resultant H2O2 solutio is 1/x . x is (Assuming no change in volume of H2O2 solution)

22.

Bleaching powder reacts with iodide ion according to the following unbalnced equation OCI – + I– + H+

→ I2 + Cl– + H2O A 0.6 g sample of bleaching powder requires 35.24 mL of 0.1084 M Na2S2O3 to titrate the liberated iodine. The percentage of Cl in the sample is nearly z. Sum of the digits of ‘z’

23. The number of tripeptides formed by three different amino acids are