jordan's solution

1
1 ( ) 1 1 1 1 ( ()) 1 1 11 2 (1 )( ) 1 1 x x x x x x x x So 1 1 (( ) 1) ( ) 11 2 1 1 ( ( ())) 1 1 2 1 2 3 2 (( )2)( ) 1 1 x x x x fx x x x x 2 x So 3 2 x And from original problem, 1 x

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Page 1: Jordan's solution

1( )1 1 11( ( ))

1 1 1 1 2(1 ) ( )1 1

xx x

f f xx x x

x

So

1 1(( ) 1) ( ) 1 1 21 1( ( ( )))1 1 2 1 2 3 2(( ) 2) ( )1 1

xx xxf f f x

x x xx

2x

So 3

2x

And from original problem, 1x