ECO-007 No. of Printed Pages : 6

BACHELOR'S DEGREE PROGRAMME

Term-End Examination

June, 2017 08413 ELECTIVE COURSE : COMMERCE

ECO-007 : ELEMENTS OF STATISTICS

Time : 2 hours Maximum Marks : 50

Weightage : 70%

Note : There are three sections and all are compulsory.

SECTION - A

1. Fill in the blanks with appropriate Ovoids given in the brackets : 5x1=5

(a) The census method of investigation is not possible when the universe is in size. (finite/ infinite).

(b) The value of can be located with the help of a histogram. (mean/mode)

(c) It is better to calculate mean deviation about . (mean/median)

(d) In a positively skewed distribution median is greater than . (mean/mode)

(e) The typing errors committed by a typist on a page is an example of variable. (discrete/ continuous)

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2. State whether the statements given below are true or false. 5x1=5

(a) In systematic sampling, a sample composed of every n th item is selected.

(b) Negative values cannot be represented in a histogram.

(c) The sum of deviations' of individual values from their arithmetic mean is always equal to zero.

(d) Mean Deviation cannot be negative.

(e) Co-efficient of variation is always presented in percentage.

SECTION - B

Attempt any two of the following :

3. (a) Construct a histogram for the following data : 10+5=15

Class interval : 2 - 4 4 - 6 6 - 8 8-10 10 - 12 12 - 16

Frequency 5 7 8 18 15 20

(b) Write a note on Pie diagram.

4. (a) The mean of a set of 75 observations was calculated as 80.4. It was discovered later that an item of value 96 was wrongly taken as 26. Determine the correct mean. 6+9=15

(b) Calculate the value of mode from the following data :

Class 0-10 10 - 20 20 - 30 30 - 40 40 - 50 50 - 60 60 - 70 70 - 80 Interval :

Frequency : 8 12 10 20 40 44 48 12

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5. (a) Using the following data, calculate mean deviation about median. 10+5=15

Marks : 20 - 40 40 - 60 60 - 80 80 - 100 100 - 120 120 - 140 Frequency : 6 9 8 10 11 6

(b) Calculate co-efficient of Variation from the following data.

Mean = 85, Variance =16

6. (a) Write a note on historigram. 6+9=15

(b) Explain the method of Karl Pearson's co-efficient of skewness.

SECTION - C

7. Differentiate between any two of the following :

(a) One Dimensional Diagram and Two Dimensional Diagram. 5+5=10

(b) Primary data and Secondary data.

(c) Discrete and Continuous Variables.

(d) Absolute and Relative Variations.

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5. (a) -14-1 gci 7:12tA 3TRITTITT 4 Trrfizrwr Trrai

ra-r-m-C nuilt fiT : 10+5=15

20-40 40-60 60-80 80-100 100-120 120-140

31-1-1, 6 9 8 10 11 6

(b) 311 311NTTut rC kul •TrifT

(co-efficient of Variation) chl

W12i=85, qt.Rill (Variance) =16

6. (a) ow rich fq7 (Historigram) tR -crWteirt ffftf7 I

(b) chic4 ii-lq-1-1**ErrzT7u tfIT

Wlf-A7 I 6+9=15

'WS -17

7. 14-■ 74 1.44 '41 14 3r4T 77771 5+5=10

(a) 7W-rcii-icfici 3-11"(131 7gT rgicv-icficf aTitta

(b) aTtwt 7q1 fgetzm 37.** (c) 7§ifz7 (Discrete) 7 2 TT 3TZgift7 (Continuous)

(d) tiffkT 72.1T 1:114V tql7 (Variations)

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1.4%311.-007

t--II rich 31-1I NT chi 014-1

t-IA I h TRkt.ii

, 2017

41 f-ISh+i : (41 ui \re-i

1111.34. -007 :

T:2 rTrr -

37filTh7 77 3.7'W :50

Tff chi : 70%

: ff-77 C9' 0.5 7Q1T 7:1113 alftaref g I

(gu8 - aT

1. TR T:l.cf gR1 ftwr Tqt

ah~ l I 5x1=5

(a) 3-1-1-41-TT9. t 44 1u1-11 RAT (census method)

1-1-q )c11 z14 T 31TWR

t I (Iffffrid/311:1fiflid)

(b) TT ¶ (value) 317117 r-ci ,1

(histogram) ch t 11(-11 gild f*-74T kichclf t I

( 11-1t71/ 1.1#11 )

TTII74 chl 1 1 1J1-11 a,(-11

3-1-FqT3T T t I ocrib7T/Trrftzr*0

(d) qa-F-TrT. Faqi-i fa--TTai -11{fzrwr

31-N -T ( -Frruip) (e) ZTOIR gRI f-*7# -cr- -ER 'I ZTT

t (variable)

(51.-ft7/31-dftU)

(c )

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4 P.T.O.

2. TM- We "r" . tgc-114 .4

chl-f-TET +irici I 5x1=5

(a) 1.> -wqr-T-P-47 Mrdlt1-1 -4 17—A-T nth .7:1 (=Ha -5rf-d--o

w.1-1 \Aim t1

(b) 1 ch airqu rcii (histogram) 14

TAT 311--d-r9-Fe Whcil

(c) 374 (-1 4-11CR -1:1R-Tfti ce-irchvicf 1=74 -*Ri -cm-ii

#71-r qk4 i I

(d) ITTar t-ichii I

(e) t7177 1juTEW (Co-efficient of Variation) #711

9f717 (percentage) * r -4?1 "arqff f*-TIT

\-1-int I

'urn -w rii-ircifigi -471 64171 .397 itraq I

3. (a) i1+-irciftgo * 3iINT7 TIT 7W 31177 f77

(histogram) : 10+5=15

icy : 2 - 4 4 - 6 6 - 8 8-10 10 - 12 12 - 16

airlt : 5 7 8 18 15 20

(b) 311tgf (Pie diagram) TR "crq re.viurl fFtRI

4. (a) 75 tfTt * * tii-iicRiTt7 (mean)

+1c-ti 80.4 LiRchrrict 717T I 77 TM Tic

771 fW 4m4) A. 96 itc-ti * -4,7 TT 1,7f

26 t71 77111 4 t-14-liot 14117 *f-77 I 6+9=15

(b). 71#0* 31117tRii-P:11Z* (mode)

~ir i 7111*r-77 :

wirt-1-T 0-10 10 - 20 20-30 30-40 40-50 50-60 60-70 70-80

3.1-9f-9 : 8 12 10 20 40 44 48 12

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