k c and equilibrium problems (4 types). additional key terms ice table solve 4 types of problems...
TRANSCRIPT
![Page 1: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/1.jpg)
Kc and Equilibrium Problems
(4 types)
![Page 2: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/2.jpg)
Additional KEY TermsICE table
• Solve 4 types of problems involving equilibrium constants.
![Page 3: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/3.jpg)
1. Plug and solve
*Always make sure the equation is balanced, FIRST*
![Page 4: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/4.jpg)
At 225°C, a 2.0 L container holds 0.040 moles of N2, 0.15 moles of H2 and 0.50 moles of NH3. If the system is at equilibrium, calculate KC.
1. Change all into concentrations - mol/L
2. Write the equilibrium law for the reaction
N2(g) + 3 H2(g) 2 NH3(g)
0.040 mol N2
2.0 L= 0.020 M N2
= 0.075 M H2
= 0.25 M NH3
![Page 5: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/5.jpg)
3. Substitute the concentrations and calculate K.(Note: no units for K)
![Page 6: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/6.jpg)
The equilibrium concentrations of N2 and NO are 1.40 mol/L and 5.20 mol/L respectively. Calculate the KC.
According to Eq stoichiometry – the same amount of O2 will be produced as N2.
2 NO(g) N2(g) + O2(g)
1.40 M5.20 M 1.40 M
Kc =
[N2][O2] [NO]2
Kc =
[1.40][1.40] [5.20]2
= 0.0725
![Page 8: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/8.jpg)
At 210°C, the Kc is 64.0 The equilibrium concentrations of N2 and O2 are 0.40 mol/L and 0.60 mol/L, respectively. Calculate the equilibrium concentration of NO.
1. Write out the Eq Law.
2. Rearrange for [NO].
N2(g) + O2(g) 2 NO(g)
![Page 9: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/9.jpg)
3. Substitute concentrations then solve.
![Page 10: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/10.jpg)
At 10.0°C, the Kc is 215.0 The equilibrium concentrations of SO2 is 9.40 mol/L. Calculate the [S] and [O2] at equilibrium.
SO2(g) S(g) + O2(g)
Values should be the same amount for S and O2 – assign the unknown “x”
x M9.40 M x M
Kc =
[S][O2] [SO2]
= Kc [S][O2] [SO2]
![Page 11: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/11.jpg)
[x][x] = 215 [9.40]
= Kc [S][O2] [SO2]
[x]2 = 2021√ √x = 45.0 M
[S]eq and [O2] eq = 45.0 M
![Page 12: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/12.jpg)
3. Simple I.C.E. Tables
![Page 13: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/13.jpg)
1.00 M of hydrogen and 1.00 M of fluorine are allowed to react at 150.0°C. At equilibrium, the [HF] is 1.32 M. Calculate KC.
H2(g) + F2(g) 2 HF(g)
[Eqlbm] 1.320.340.34
[Initial] 1.00 M 1.00 M 0
[Change] - 0.66 - 0.66 + 1.32
Tip #1 – the changes in concentration match the stoichiometry of the reaction.
1 1
![Page 14: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/14.jpg)
[Eq] 1.320.340.34
H2(g) + F2(g) 2 HF(g)
![Page 15: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/15.jpg)
Initially 2.0 mol of SO2, 1.0 mol of O2 are mixed in a 3.0 L reaction container. At equilibrium, 0.20 mol of O2 are found to remain. Calculate the Kc.
2 SO3 (g) 2 SO2 (g) + O2 (g)
[E] 0.15 0.0670.52
[I] 0 0.67 mol/L 0.33 mol/L
[C] - 0.52+ 0.52 - 0.26
Tip #2 – make sure the +/- reflect the appropriate side being made or used up
![Page 16: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/16.jpg)
Kc = 0.00557 Kc = 5.6 x 10-3
[E] 0.15 0.0670.52
Kc =
[SO2]2[O2] [SO3]2
2 SO3 (g) 2 SO2 (g) + O2 (g)
Kc =
[0.15]2[0.067] [0.52]2
Tip #3 – Write Eq Law for equation as written.
![Page 17: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/17.jpg)
4. HARD I.C.E. Tables
![Page 18: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/18.jpg)
[E] 6.0 - x 2x6.0 - x
6.0 moles of N2 and O2 gases are placed in a 1.0 L container, what are all the concentrations at equilibrium? The Kc is 6.76.
N2(g) + O2(g) 2 NO(g)
[I] 6.0 mol/L 0 6.0 mol/L
[C] - x - x + 2x
Tip #4 – use x values to match the stoichiometry changes of the reaction.
1 1
![Page 19: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/19.jpg)
Get rid of the square by taking the square root of both sides.
Substitute known values.
![Page 20: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/20.jpg)
Isolate, and solve for x.
[I]
[C]
[E]
6.0 mol/L 0 6.0 mol/L
- 3.4 - 3.4 2(3.4)
6.82.6 2.66.0 - x 2x6.0 - x
- x - x + 2x
![Page 21: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/21.jpg)
H2 (g) + I2 (g) 2 HI (g)
2.0 moles of HI were placed in a 1.0 L flask at 430ºC. (Kc = 54.3) Calculate the equilibrium concentrations.
[I]
[C]
[E]
0 0 2.0
+ x + x - 2x
2.0 - 2x+ x+ x
Kc = [HI]2
[H2][I2]
![Page 22: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/22.jpg)
54.3 = [2.0 - 2x]2
[+ x][+ x]
Kc = [HI]2
[H2][I2]
7.37 = 2.0 – 2x x
7.37 x = 2.0 – 2x
√ √
7.37 x + 2x = 2.0
9.37 x = 2.0
x = 0.21
[I]
[C]
[E]
0 0 2.0
+ x + x - 2x
2.0 - 2x+ x+ x
0.21 0.21 - 0.42
1.580.210.21
![Page 23: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/23.jpg)
The Kc for the reaction 5.3 x 10 -2 at 0ºC. Initially, 2.5 mol each particle was injected into a 1 L reaction vessel. Find the Eq concentrations.
2.5 + x 2.5 + x 2.5 - 2x
-2x+ x+ x2.5 mol/L 2.5 mol/L2.5 mol/L
[E]
[C]
[I]
H2 (g) + Cl2 (g) 2 HCl (g)
Tip #5 – use the Kc value to predict the changes in the reaction.
![Page 24: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/24.jpg)
5.3 x 10 -2 = [2.5 - 2x]2
[2.5 + x][2.5 + x]
Kc = [HCl]2
[H2][Cl2]
√5.3 x 10 -2 = [2.5 - 2x]2
[2.5+x]2 √
√
0.23 = 2.5 – 2x 2.5+ x
![Page 25: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/25.jpg)
x = 0.86 mol/L x = 1.92
2.23
0.58 + 0.23x = 2.5 - 2x
2.5 mol/L 2.5 mol/L2.5 mol/L
[E]
[C]
[I]
+ 0.86 + 0.86 2(0.86)
0.8 mol/L3.4 mol/L3.4 mol/L
2.23 x = 1.92
![Page 26: K c and Equilibrium Problems (4 types). Additional KEY Terms ICE table Solve 4 types of problems involving equilibrium constants](https://reader038.vdocuments.net/reader038/viewer/2022103015/551aae28550346b2288b4892/html5/thumbnails/26.jpg)
Additional KEY TermsICE table
CAN YOU / HAVE YOU?
• Solve 4 types of problems involving equilibrium constants.