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Page 1: konicaminolta C364-20150217144926 · 2019. 3. 13. · 26 Q) cos @ cos 201 mg @ ma e (5 e 5 sin sin 291 mgp mag —%1— (3) tan tan 261 (3) mgg 6) map OM57 (092—1517)

Page 2: konicaminolta C364-20150217144926 · 2019. 3. 13. · 26 Q) cos @ cos 201 mg @ ma e (5 e 5 sin sin 291 mgp mag —%1— (3) tan tan 261 (3) mgg 6) map OM57 (092—1517)

Page 3: konicaminolta C364-20150217144926 · 2019. 3. 13. · 26 Q) cos @ cos 201 mg @ ma e (5 e 5 sin sin 291 mgp mag —%1— (3) tan tan 261 (3) mgg 6) map OM57 (092—1517)

Page 4: konicaminolta C364-20150217144926 · 2019. 3. 13. · 26 Q) cos @ cos 201 mg @ ma e (5 e 5 sin sin 291 mgp mag —%1— (3) tan tan 261 (3) mgg 6) map OM57 (092—1517)

Page 5: konicaminolta C364-20150217144926 · 2019. 3. 13. · 26 Q) cos @ cos 201 mg @ ma e (5 e 5 sin sin 291 mgp mag —%1— (3) tan tan 261 (3) mgg 6) map OM57 (092—1517)

Page 6: konicaminolta C364-20150217144926 · 2019. 3. 13. · 26 Q) cos @ cos 201 mg @ ma e (5 e 5 sin sin 291 mgp mag —%1— (3) tan tan 261 (3) mgg 6) map OM57 (092—1517)

Page 7: konicaminolta C364-20150217144926 · 2019. 3. 13. · 26 Q) cos @ cos 201 mg @ ma e (5 e 5 sin sin 291 mgp mag —%1— (3) tan tan 261 (3) mgg 6) map OM57 (092—1517)

Page 8: konicaminolta C364-20150217144926 · 2019. 3. 13. · 26 Q) cos @ cos 201 mg @ ma e (5 e 5 sin sin 291 mgp mag —%1— (3) tan tan 261 (3) mgg 6) map OM57 (092—1517)

Page 9: konicaminolta C364-20150217144926 · 2019. 3. 13. · 26 Q) cos @ cos 201 mg @ ma e (5 e 5 sin sin 291 mgp mag —%1— (3) tan tan 261 (3) mgg 6) map OM57 (092—1517)

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ecare.kundanvidyamandir.comecare.kundanvidyamandir.com/main/Download.aspx?Doc=Asgn... · 16. Evaluate : sin(500 + 9) — cos(400 — 9) + tan 10 tan 100 tan 200 tan 700 tan 800 tan

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INVERSE TRIGONOMETRIC FUNCTIONS...INVERSE TRIGONOMETRIC FUNCTIONS 23 Therefore, tan(cos–1x) = 1–cos θ 21– tanθ = . cosθ x x = Hence 2 –1 8 1– 8 17 15 tan cos = 17 8 8

· 2 cot 4x 2 tan x + sec x x2 cos 2x 1 + sin x cos x tan 4 3x cos 2x f'(x) = (x + cos x)2 — + COS — (it) — 2 — + COS 2. 8. 11. 14. 20. 1 — sin — cos 3x y — —cosec

5. 9. 11. 13. cos(A + B) = cos A cos B — A sin B sm(A + B) = sin A cos B + cos A sm B sm 2A = 2 Sin A cos A tan A + tan B tan(A + B) = 1 — tan A tan B 2 tan A tan 24 = I —

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CHAPTER 5 Analytic Trigonometry · Section 5.1 Using Fundamental Identities 383 32. sec csc csc cot 1 cos 31. sin tan x x 1 sin sin cos sec x 33. 1 cos sin cos sin 1 sec sin tan 1

Chapter 5 Analytic Trigonometrywhsweber.weebly.com/uploads/8/5/6/5/8565256/chapter_5.pdf1. cos ¨=1 sec ¨, sec ¨=1 cos ¨, and tan ¨=sin ¨ cos ¨ 2. sin ¨=1 csc ¨ and tan ¨=1

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Document12 - Weeblynshsdolan.weebly.com/.../614_chptr_10_answers_review.pdf · 2019. 10. 9. · 1 + tan 1700 tan 500 Simplify the given expression. b. sin cos — 12 — cos 700 9

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Page 1 Page 2 - · PDF fileLLWEIDE'S FORMULA a + b cos sin Y cos sin Sin — 9 cos = sec B = cot B 1 + tan tan eCalc.com The Best Online Calculator Unit Converter

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€¦ · Web viewcos 2 (90° + θ) cos -θ + sin 90° - θ cos θ = 1 cos θ - 1 (6) (3) Bepaal die algemene oplossing van: tan x sin x + cos x tan x = 0 (7) (4) Beskou die volgende

Teachingbd · 2018-03-14 · 3.76 (Ans.) 3 tan200 - tan' 200 I -3 = tan 600 A = + + y cos a cos COs J I — tan a, = I + tan 16 cosA cos 2A cos 4A cos 7A = I a, + = cos2p = cos2p

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