kuliah dasar sistem kendali 6

Upload: frista-asrori

Post on 26-Feb-2018

238 views

Category:

Documents


1 download

TRANSCRIPT

  • 7/25/2019 kuliah dasar sistem kendali 6

    1/19

    January 20, 2016 1

    Dasar Sistem Kontrol

    06:

    Steady state errors

    DWI ANA RATNA WATI

    Department of Electrical [email protected]

    mailto:[email protected]:[email protected]
  • 7/25/2019 kuliah dasar sistem kendali 6

    2/19

    January 20, 2016 2

    Isi

    definisi steady state errorkonstanta static error

    static errors sistem dengan pengendali

    static errors sistem sero

    static errors sistem dengan pengganggu

  • 7/25/2019 kuliah dasar sistem kendali 6

    3/19

    January 20, 2016 !

    Steady state erroradala" selisi" antara input

    dan output saat

    Definisi steady state error

    t

    Jika se#ua" sistem stabil:

    tmakarespon alamianya mendekati0 saat

  • 7/25/2019 kuliah dasar sistem kendali 6

    4/19

    January 20, 2016 $

    Klasifikasi sistem kontrol

    ( ) ( ) ( )

    ( ) ( ) ( )111

    111)(

    21 ++++

    ++++=

    sTsTsTs

    sTsTsTKsG

    p

    N

    mba

    Sistem kontrol dengan umpan #alik memiliki fungsi ali"loop ter#uka G%s&

    dise#ut sistem tipe N'

  • 7/25/2019 kuliah dasar sistem kendali 6

    5/19

    January 20, 2016 (

    Steady state error

    )(sR )(sC)(sE)(sG

    )(1)(

    )()(

    sGsG

    sRsC

    +

    =

    )()(1

    1

    )(1

    )()()()()()( sR

    sGsG

    sGsRsRsCsRsE

    +

    =

    +

    ==

    )(1

    )(lim)(lim)(lim

    00 sG

    ssRssEtee

    sstss

    +

    ===

  • 7/25/2019 kuliah dasar sistem kendali 6

    6/19

    January 20, 2016 6

    Static position error constant Kp

    Steady)state error untuk input unit!stepadala"

    )0(1

    11

    )(1lim

    )(1

    )(lim

    00 GssG

    s

    sG

    ssRe

    ssss

    +

    =

    +

    =

    +

    =

    Static position error constant Kpdidefinisikan :

    )0()(lim0

    GsGKs

    p ==

    p

    ssK

    e+

    =

    1

    1

  • 7/25/2019 kuliah dasar sistem kendali 6

    7/19

    January 20, 2016 *

    Static position error constant Kp

    +or a type 0 system

    ( ) ( )

    ( )( ) K

    sTsT

    sTsTKK ba

    sp =

    ++

    ++=

    ...11

    ...11lim

    210

    +or a type 1 or "ig"er system

    ( ) ( )

    ( ) ( )

    =

    ++

    ++=

    ...11

    ...11lim

    21

    0

    sTsTs

    sTsTKK

    N

    ba

    sp

    Kess

    +

    =

    1

    1

    0=sse

  • 7/25/2019 kuliah dasar sistem kendali 6

    8/19

    January 20, 2016

    Static elocity error constant Kv

    Steady)state error untuk input unit!rampadala"

    )(

    1lim

    1

    )(1lim

    )(1

    )(lim

    0200 ssGssG

    s

    sG

    ssRe

    sssss

    =

    +

    =

    +

    =

    Static elocity error constant Kdidefinisikan :

    )(lim0

    ssGKs

    v

    =

    v

    ssK

    e 1=

  • 7/25/2019 kuliah dasar sistem kendali 6

    9/19

    January 20, 2016 -

    Static elocity error constant Kv

    .ntuk sistem tipe nol

    ( )( )

    ( ) ( ) 0

    ...11

    ...11lim

    210

    =

    ++

    ++=

    sTsT

    sTsTsKK ba

    sv

    .ntuk sistem tipe satu

    ( )( )

    ( ) ( ) K

    sTsTs

    sTsTKsK ba

    sv =

    ++

    ++=

    ...11

    ...11lim

    210

    =sse

    Kess

    1=

    .ntuk sistem tipe dua dan yang le#i" tinggi

    ( ) ( )

    ( ) ( ) =

    ++

    ++=

    ...11

    ...11lim

    210 sTsTs

    sTsTKsK

    N

    ba

    sv

    0=sse

  • 7/25/2019 kuliah dasar sistem kendali 6

    10/19

    January 20, 2016 10

    Static acceleration error constant Ka

    Steady)state error untuk input unit!parabolicadala"

    )(1lim1

    )(1lim

    )(1)(lim

    20300 sGsssGs

    sGssRe

    sssss

    =

    +

    =

    +

    =

    Static acceleration error constant Kadidefinisikan :

    )(lim 20

    sGsKs

    a

    =

    a

    ssK

    e 1=

    2)(

    2ttr =

  • 7/25/2019 kuliah dasar sistem kendali 6

    11/19

    January 20, 2016 11

    Static acceleration error constant Ka

    .ntuk sistem tipe nol

    ( ) ( )( ) ( )

    0...11

    ...11lim

    21

    2

    0=

    ++

    ++=

    sTsT

    sTsTKsK ba

    sa

    .ntuk sistem tipe dua

    ( )( )

    ( )( ) K

    sTsTs

    sTsTKsK ba

    sa =

    ++

    ++=

    ...11

    ...11lim

    21

    2

    2

    0

    =sse

    Kess

    1=

    .ntuk sistem tipe tiga dan yang le#i" tinggi

    ( ) ( )

    ( )( ) =

    ++

    ++=

    ...11

    ...11lim

    21

    2

    0 sTsTs

    sTsTKsK

    N

    ba

    sa

    0=sse

    ( ) ( )

    ( )( ) 0...11

    ...11

    lim 21

    2

    0=

    ++

    ++=

    sTsTs

    sTsTKs

    K

    ba

    sa =sse

    .ntuk sistem tipe satu

  • 7/25/2019 kuliah dasar sistem kendali 6

    12/19

    January 20, 2016 12

    Steady)state error dalam #entuk gain

    step input ramp input acc' input

    type 0system

    type 1system

    type 2system

    2)(

    2ttr =1)( =tr ttr =)(

    K+1

    1

    K

    1

    K1

    0

    0 0

  • 7/25/2019 kuliah dasar sistem kendali 6

    13/19

    January 20, 2016 1!

    Sistem kendali proporsional

    )(sR )(sC)(sE

    1

    1

    +TsK

    /entukan steady)state errors sistem ini

  • 7/25/2019 kuliah dasar sistem kendali 6

    14/19

    January 20, 2016 1$

    Sistem kontrol integral

    )(sR )(sC)(sE

    1

    1

    +TssK

    /entukan steady)state errors sistem ini

  • 7/25/2019 kuliah dasar sistem kendali 6

    15/19

    January 20, 2016 1(

    Steady)state error sistem sero

    )(sR )(sCK

    s

    1)(sE

    BJs +1

    /entukan steady)state errors system #erikut

    J

    Kn=JK

    B

    2=

  • 7/25/2019 kuliah dasar sistem kendali 6

    16/19

    January 20, 2016 16

    Steady)state error sistem sero

    dengan kontrol proportional deriatif

    )(sR )(sC

    s

    1)(sE

    BJs +

    1

    /entukan steady)state errors sistem #erikut

    J

    Kpn=

    p

    d

    JK

    KB

    2

    +=

    sKK dp+

  • 7/25/2019 kuliah dasar sistem kendali 6

    17/19

    January 20, 2016 1*

    espon pengendali proporsional

    ter"adap gangguan torsi

    )(sR )(sCpK s

    1)(sE

    BJs +1

    )(sD

    /entukan steady)state error yang dise#a#kan ole" gangguan torsi#erupa step dengan magnitudo Td

    T

  • 7/25/2019 kuliah dasar sistem kendali 6

    18/19

    January 20, 2016 1

    espon pengendali proporsionalintegral

    ter"adap gangguan torsi

    )(sR )(sC

    s

    1)(sE

    BJs +1

    )(sD

    /entukan steady)state error yang dise#a#kan ole" gangguan torsi#erupa step dengan magnitudo Td

    T

    +

    sTK

    i

    p

    11

  • 7/25/2019 kuliah dasar sistem kendali 6

    19/19

    January 20, 2016 1-

    Sistem Sero dengan elocity feed#ack

    )(sR )(sCK

    s

    1

    hK

    )(sE

    BJs +1

    )(sD

    /entukan error ketika input referensi dan input pengganggu muncul

    di dalam sistem #erikut'

    tentukan nilai steady)state error ketika sistem memiliki input

    referensi unit)ramp and input pengganggu step dengan magnitud d'