lambda absorption lecture

10
A Bit More on the Absorption of Light

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Page 1: Lambda Absorption Lecture

A Bit More on the Absorption of Light

Page 2: Lambda Absorption Lecture

How do we associate the energy of a particle in a 1-Dbox with the wavelength of the particle?

velocity nu

velocitynu

Page 3: Lambda Absorption Lecture

http://en.wikipedia.org/wiki/Image:Particle_in_a_box_wavefunctions.png#filea

We require that λ return to zero at the ends of the box

Page 4: Lambda Absorption Lecture

in general where n = 1, 2, 3,…

since

Particle has no potential energy, so the only energy we can associate with the particle is kinetic energy:

We require also that the particle always be moving

Page 5: Lambda Absorption Lecture

Apply to “real world”, i.e., π electrons in a ~linear,conjugated hydrocarbon, e.g. butadiene

CH2=CHCH=CH2

Length of “box” is: 2 × 135 pm + 1 × 154 pm + 2 ×77 pm = 578 pm

How many π electrons?

n = 1

n = 2

n = 3

• •• •

Page 6: Lambda Absorption Lecture

At what λ will absorption occur?

h = 6.626 × 10−34 J s; (J = kg m2/s2); c = 3.0 × 108 m/s; me = 9.1039 × 10−31 kg

How does this estimate compare with the experimentally determined λ? (λmax experimentalis 217 nm).

Page 7: Lambda Absorption Lecture

For more complicated molecules, our simple theoretical model breaks down, as expected. Someof the salient features, however, can be retained, especially in a qualitative sense.

For example, we saw that:

So, the energy gap is inversely proportional to square of the length of the box.

Page 8: Lambda Absorption Lecture

If we equate our expression for the energy gap (∆E)with a modified form of Planck’s relation we can solve for the wavelength necessary to bridge thatenergy gap:

And we see that λ is directly proportional to the square of the length of the box (or the size of theconjugated molecule).

Page 9: Lambda Absorption Lecture

And, all things being equal, a longer, conjugated molecule should absorb at a longer wavelength. Ifthe molecule is long enough, it should absorb at a long enough wavelength that we might even seethe transmitted light with our eyes. Consider themolecule β-carotene.

http://www.chm.bris.ac.uk/motm/carotene/beta-carotene_structure.html

This molecule is a relatively long, conjugated “box”.

Page 10: Lambda Absorption Lecture

Accordingly, β-carotene has a λmax of 455 nm, whichis in the “blue” region of the visible portion of the electromagnetic spectrum, and thus it appears orange to our eyes.

R

O

Y

G

BI

V

700 nm

400 nm

http://en.wikipedia.org/wiki/Visible_spectrum