lec 1 introduction frequencty response
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EE 204
Analog Electronics II
Frequency Response
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EE 204 Analog Electronics II
Frequency Response BJT/MOSFET
Differential amplifiers, Multistage amplifiers
Feedback amplifiers and their configurations, feedback
topologies, loop gain, stability using Bode plot,
frequency compensation
Output stages and power amplifiers, classA amplifiers,
class-B amplifiers, class-AB amplifiers, Biasing, IC
power amplifier, MOS power transistors.
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MOS Field-EffectTransistors (MOSFETs)
Small Signal Equivalent Circuit Models S-domain analysis, Bode plots,
Amplifier Transfer Function and frequency response
Low and High frequency response of common source and commonemitter amplifiers, Millers theorem.
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Bipolar JunctionTransistors (BJTs)
Small Signal Equivalent Circuit Models S-domain analysis, Bodeplots, Amplifier Transfer Function and frequency response
Low and High frequency response of common source andcommon emitter amplifiers, Millers theorem.
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Single-Stage Integrated-Circuit Amplifiers
Frequency Response of Common Gate, Common Base and Cascodeconfiguration.
Frequency Response of Emitter & Source Followers
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Frequency Response of Amplifiers
Input signal to an amplifier is expressed as
the sum of sinusoidal signals.
Characterization of amplifier performance
is known as the amplifierfrequency
Response.
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Frequency Response
The frequency response of a circuit is the variation in its behaviorwith change in signal frequency.
The frequency response of amplifier circuits is considered by usingtheirtransfer functions
Systematic way of obtaining the frequency response is to us Bodeplots
Keep the amplitude of the sinusoidal source constant and vary thefrequency, to obtain the circuits f requency respon se.
The frequency response is regarded as a complete description of
the sinusoidal steady-state behaviorof a circuit as a function offrequency.
Achieve important concepts such as mid-band gain, cutoff frequencyand bandwidth and unity gain-bandwidth Product.
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Define bandwidth, cutof f f requency, and geometr ic centerfrequency, and identify each on a frequency-response curve.
Calculate any two of the following values, given the other two: Geometric centerfrequency, orbandwidth, fL, fH.
Describe the decadeand octavefrequency multipliers.
Compare and contrast the Bode plotwith the frequency-response curve.
Perform a complete low-frequency analysis of a BJT amplifier.
Discuss the concept of gain roll-offand calculate its effect onvoltage gain at a given operating frequency.
Explain why BJT internal capacitances are not considered inlow-frequency analyses.
Objectives : Frequency Response
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Objectives : Frequency Response
Calculate the Miller input and output capacitance values
for a BJT amplifier.
Perform a complete high-frequency analysis of a BJTamplifier.
Compare high-frequency roll-off rates to low-frequencyroll-off rates.
Perform the low-frequency-response analysis of an FETamplifier.
Perform the high-frequency-response analysis of an FETamplifier.
Describe and analyze the frequency response of amultistage amplifier/DA.
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Frequency Response
Centre Frequency
fo = fLfH
fo
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Decible
In communications systems, gain is
measured in bels. Historically, the bel isused to measure the ratio of two levels ofpower or power gain G; that is,
G=Number of bels=log10P2/P1 G=Number of Decibel (dB)=10 log10
P2/P
Alternatively, the gain G can be expressedin terms of voltage or current ratio
GdB=20log10V2/V1
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Bode Plot
Bode plots use a logarithmicscale for the
frequency axis and a linearscale in eachof the separate plots ofmagnitude and
phase.
Bode plots are semilog plots of themagnitude (in decibels) and phase (indegrees) of a transfer function versus
frequency.
B d Pl t U d t E ti t Z
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Bode Plot Used to Estimate Zeros
& Poles
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Measuring of Frequency Response of
a linear Amplifier
Input signal vi=Visint Output Signal vo=Vosin(t+) Signals are characterized by
Amplitude, Frequency and Phase
Transfer Function Magnitude of Amplifier Gain
Ratio of the amplitude of output sinusoid (Vo) to the amplitudeof the input sinusoid (Vi) at the input frequency ()
Gain |T()|= Vo/Vi
Graph of gain magnitude |T()| verses frequency - Bode Plot
Phase Angle
The phase of the amplitude transmission T() at the inputfrequency
Phase Angle
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Amplifier Bandwidth
Constant gain between L& H
Lowergain belowL& above H
Amplifier Bandwidth
Band over which the gain of amplifier is almostconstant to within a certain number of decibel (3 dB).
3 dB frequency is also known as Cornerfrequency orBreak frequency
Designing an amplifier Its bandwidth must coincide with the spectrum of the
signal it is required to amplify otherwise, amplifierwould distort the frequency spectrum with differentcomponents amplified by different amount.
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Evaluating the Frequency Response of Amplifier
Analyze the amplifier equivalent circuit model
(Small Signal Model) taking into account allreactive components.
Represent all reactive components by their
reactancein complex frequency variables sC to 1/sC
Perform analysis to obtain the transfer function
T(s) = V0(s)/Vi(s)
Subsequently replaces into j to determine
the network transfer function T (j)
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Amplifier Transfer Function
Amplifier Types
Direct Coupled
Capacitively Coupled
Difference Gain of the ac amplifierfalls offat low and high
frequencies
Amplifier gain is constant over a wide range offrequencies, called Mid-band All capacitance (coupling, bypass and transistor
internal capacitance) are neglected
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Frequency Response dc & ac
Amplifier
DIRECT COUPLED Amplifier CAPACITIVELY Amplifier
M i d 3 D G h
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Magnitude 3-D Graph
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Single Time constant (STC) Network
STC is the network that can be reduced toone reactive component and one resistor
Time constant of an STC network (RC)is = CR
Categories High Pass
Low-Pass
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Classification of STC circuit
Low Pass (type)
High Pass (type)
Rules for finding the type of STC circuitTime at Replace Circuit
BLP if
Circuit is
HP if
= 0 C by o.cL by s.c
Outputinfinite
Output iszero
= C by s.c
L by o.c
Output is
zero
Output is
finite
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Low Frequency Response
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M it d f STC t k Hi h t
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Magnitude of STC networks High-pass type.
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High-Pass Filter
Zero of the Transfer Function
Vo(s)/Vi(s) = 0
Pole of the Transfer Function
Vo(s)/Vi(s) =
1
11
1
1||
sCR
R
sCR
2121
212121 ||
110
RRCRR
RRCsRsCRRR
p
1
2121
1
1212
110
1||
sCR
RsCRRR
sCR
RR
sCRR
11
1
0 CRssCR z
p
z
i
o
s
sk
sCRR
R
sV
sV
1||)(
)(
12
2
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High-Pass Filter
Zero of the Transfer Function
Vo(s)/Vi(s) = 0
Pole of the Transfer Function
Vo(s)/Vi(s) =
2121
2121
||
110||1
RRC
RR
RRC
sRsCR p
1
1
101
CRssCR z
2121
12
1
1
2
2
12
2 1
1
1||
)(
)(
RsCRRR
sCRR
sCR
R
R
R
sCRR
R
sV
sV
i
o
21
1
21
2
2121
12
||1
11
)(
)(
RRsC
sCR
RR
R
RsCRRR
sCRR
sV
sV
i
o
21
1
21
2
||1
1
)(
)(
RRsC
sCR
RR
R
sV
sV
i
o
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Procedure
First reduce the excitation to zero Voltage independent replaced by a short
circuit
Current source replaced by a open circuit
Grab hold the two terminals of thereactive component
Find the equivalent resistance Req seenby the reactive component
Time constant = CReq or L/Req
Rapid Evaluation
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High Frequency Response
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STC --- Low-Pass Filter
Zero of the Transfer Function
Vo(s)/Vi(s) = 0
Pole of the Transfer Function
Vo(s)/Vi(s) =
Network poles or natural modes,are independent of the excitation
zssCR 11
RC
ssCR p1
01
Magnitude response of STC networks of the low-pass type
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Magnitude response of STC networks of the low-pass type.
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Low-Pass Filter
121
2
1
1
1||
1||
)(
)(
p
Z
i
o
s
s
k
sCRR
sCR
sV
sV
Zero of the Transfer Function
Vo(s)/Vi(s) = 0
Pole of the Transfer Function
Vo(s)/Vi(s) =
2
22
10
1||
sCR
R
sCR
2121
212121
||
110
RRC
RR
RR
C
sRsCRRR p
2
2121
2
2121
110
1||
sCR
RsCRRR
sCR
RR
sCRR
zssCR
11
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Low-Pass Filter
p
i
o
i
o
i
o
sRR
R
sV
sV
RRsCRRR
RR
RRRsCRRR
RsVsV
sCRR
R
sCRR
sCRR
sCR
sV
sV
1
1
)(
)(
)||(11
1
1
)()(
1
1
1||
1||
)(
)(
21
2
2121
2
21
21
2121
2
2
21
2
2
21
2
)RC(R
1
1
1
)RC(R
1
CR
1
,0@
0@cctshortasactsCapacitoras
0@
2121
2
)(
)(
21eq
p
)(p
z
)(z
21
2
)(
)(
RRR
s
s
kV
V
for CFind RVFind
VFind
RRR
kV
V
CapacitorcctopenBykFind
p
z
si
so
eqsi
so
si
so
121
2
11
1||
1||
)()(
pi
o
sk
sCRRsC
R
sVsV
Low Pass Filter
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Low-Pass Filter
p
z
i
o
s
s
k
RRsC
sCR
RR
R
sCRR
sCR
sV
sVsT
1
1
)(1
1
1
1
)(
)()(
21
2
21
2
21
2
Find k k = Vo(s)/Vi(s) while C is short circuited
Z while Vo(s)=0 s = - 1/CR2
pwhile V
i(s)=0 s = - 1/C(R
1+R
2)
Frequency Response
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Frequency Response
Rad/sec
0 10 100 1k 10k 100k 1M 10M .. 100G
1000G
XC1
100k 10K 1K 100 10 1 0.1 ..
XC2
1014 1013 1012 1011 1010 1G 100M .. 10K 1KVout 0 0.9 4.5 8.0 9.0 9.0 9.0 9.0 9.0 8.0 4.7
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Frequency Response
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T B d Pl t D i ti
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True Bode Plot Deviations
f/f0(/0)Magnitud
e error
dB
Phase
error
degrees
0.1 0.04 + 5.7
0.5 1 - 4.0
1 3 0
2 1 + 4.0
10 0.04 - 5.7
Magnitude response
|A| =20 log
Phase Response
=
Magnitude response|A| =20 log
Phase Response
=
High Pass
Low Pass
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Notations
Voltage & Current are function of
Frequency
Symbols used are uppercase letter with
lowercase subscripts ( Vgs , Ib)
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Internal Capacitance
BJT
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BJT Internal Capacitances
Effect ofcapacitances was neglected
Actual BJT exhibit charge storagephenomena that limit speed and frequency
of its operation
Frequency dependence are amplifier gain
and the time delays for BJT being used asa switch or logic inverter.
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Cross-section of an npn BJT.
Small Signal Model
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Small Signal Model
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High Frequency Hybrid Model
C = EBJ Capacitance Range
a few Pico-Farads to a few tens of Pico-Farads
C = CBJ Capacitance
Range
a Fraction of Pico-Farad a few Pico Farads
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rx Resistance of silicon material of the
base region between the Base terminal
and a fictitious internal base terminal
Value of is a few hundred ohms.
rx
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Internal Capacitance - Included
The gain of every MOSFET amplifierfalls
offat some high frequency
Exhibit finite nonzero propagation delay
Capacitance
Gate capacitance COX
Gate electrode
forms a parallel plate capacitance with the
channel, with the silicon oxide layer as
dielectric
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I l C i MOSFET
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Internal Capacitance : MOSFET
Four terminal capacitance G,D,S,B
Cgs, Cgd, Cgb, Csb, Cdb
MOSFET Internal Capacitances
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MOSFET Internal Capacitances
High Frequency Model
High-frequency equivalent circuit model for the MOSFET.
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Normally Body is connected with the Source
Cdb is added to the load capacitance
Common-Source amplifier
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Common-Source amplifier
Cgs = 4.0pF
Cgd = 1.0pFCds = 1.0pF
Frequency Response @10 Rad/sec
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Frequency Response @10 Rad/sec
ForLow Frequency analysis
Internal Capacitors are open cicuited
Low-frequency response of a CS amplifier
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q y p p
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Frequency Response @10 G Rad/sec
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Frequency Response @10 G Rad/sec
ForHigh Frequency analysis
External Capacitors are short cicuited
Normalized high-frequency response of the
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g q y p
amplifier
Capacitively coupled common-source amplifier
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p y p p
Frequency Response : CE with RE
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Frequency Response : CE with RE
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25 ohm
/gm40 ohm
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Frequency Response : CE
Avoid External Capacitors :CE
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Avoid External Capacitors :CE
Cc1 Blocking / Coupling CapacitorBlocks DC at node B from effecting the signal source cct.
Use constant current source or two power supplies Biasing TechniqueDC components in signal source
The circuit should be in-sensitive to DC components ------Responds to differential signal input
Cc2 Blocking / Coupling CapacitorBlocks DC at node C from effecting the load
Output should have NO DC Components
By-pass capacitorKeeps Emitter at signal ground
Ensure that emitter remains at signal ground
Direct Coupled Amplifier : DA
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Direct Coupled Amplifier : DA
Amplifiers being studied are intended for fabrication using IC
technology
Don't employ Coupling/By-pass capacitors
IC cascade amplifier are directly coupled. Thus do not utilizelarge coupling capacitor
Gain remains constant at its mid-band valueAM down tozero frequency
No gain reduction at low frequency.
Gain falls off at high frequency due to internal capacitance