lecture 2 august 3, 2005 lehninger (4 th edition), chapter 6,

45
Lecture 2 • August 3, 2005 • Lehninger (4 th Edition), Chapter 6,

Post on 20-Dec-2015

224 views

Category:

Documents


0 download

TRANSCRIPT

Page 1: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Lecture 2

• August 3, 2005

• Lehninger (4th Edition), Chapter 6,

Page 2: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

ENZYME KINETICS

LNC Chapter 6

Page 3: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

REACTANTS

SUBSTRATESPRODUCTS

kFirst order reactions: A P

kSecond order reactions: A + B P

A + A P

Page 4: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

1st order: ln[A] = ln[Ao] - kt or [A] = [Ao] exp(-kt)

2nd order: 1/[A] = 1/[Ao] + kt

time

[A]

time

[A]

1

time

ln [A]

Page 5: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

TRANSITION STATE THEORY

A C

B D

A C

B D

A C

B D

A catalyst serves in at least two ways:it binds and aligns the substratesit facilitates the redistribution of electrons (charges)

Page 6: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

k1 k2

E + S ES Products k-1

CHAPTER 6

Enzymes and Enzyme Kinetics

Page 7: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Fig. 6-2

Page 8: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Fig. 6-3

Page 9: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Derivation of Michaelis-Mentenequation

• 1. equilibrium assumption: k-1 >> k2

• 2. steady state assumption: d[ES]/dt = 0

• Note: [E] = [E]total – [ES]

Page 10: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Hmmm..??

Page 11: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

when [S] >> Km

then

v vmax and vmax = k 2 [E] T

k2 x [E]T x [S]v = ------------------------- Km + [S]

Page 12: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

k -1 + k 2 Km =

k 1

Page 13: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

d

Km Kd

when

k -1 >> k 2

Page 14: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Fig. 6-11

Page 15: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Fig. 6-12

Page 16: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

1 Km 1 1 = x +vo v max [S] v max

y = ax + b

Page 17: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Lineweaver-Burk Plot

Double Reciprocal Plotbox. 6-1

Page 18: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

- another definition:

v max

k2 = k cat = ------------ [E] T

TURNOVER NUMBER

Page 19: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,
Page 20: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

molecules of substrate / molecule of enzyme / second

moles of substrate / mole of enzyme / second

Page 21: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Reactions with more than one substrate

(more typical)

Overall reaction:

S1 + S2 P1 + P2

Page 22: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Fig. 6-13

Page 23: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

LNC 6-14 a

Lines intersect: ternary complex is formed in the reaction

Page 24: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

LNC 6-13 b

This case is also referred to as the Ping-Pongor

double displacement mechanism

Page 25: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

LNC 6-14 b

Lines do not intersect: no ternary complex is formed

Page 26: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Enzyme Inhibitors

Page 27: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Fig. 6-15a

Page 28: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Competitive Inhibition

= 1 + [I] / KI

box. 6-2.1

Page 29: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Fig. 6-15b

Page 30: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Uncompetitive Inhibition

’ = 1 + [I] / KI

box. 6-2.2

Page 31: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Fig. 6-15c

Page 32: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Mixed Inhibition

When = ’, then we also speak of noncompetitive inhibition

box 6-2.3

Page 33: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

LNC 6-28

FEEDBACK INHIBITION

Page 34: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

LNC 6-26

Page 35: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

LNC 6-27

ASPARTATE TRANSCARBAMYLASE

Page 36: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

LNC 6-29a

Page 37: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

LNC 6-29b

Page 38: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

LNC 6-29c

Page 39: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Part III

Bioenergetics and MetabolismChapter 13 in LNC

Page 40: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

THE CARBON CYCLE

Page 41: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

urea

THE NITROGEN CYCLE

Page 42: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,
Page 43: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,
Page 44: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

Types of Organic Reactions

1) Group transferGlucose + ATP Glu-6-P + ADPH2O + ATP Pi + ADP

2) Oxidation-reduction reactionsEthanol + NAH+ acetaldehyde + NADH + H+

3) Eliminations, isomerizations, rearrangementsaldose ketose

4) reactions involving making or breaking of C-C bondsFru-1,6, bisphosphate dihydroxyacetone-phosphate

+ glyceraldehyde-3phosphate

Page 45: Lecture 2 August 3, 2005 Lehninger (4 th Edition), Chapter 6,

• End of Lecture 2

• Aug. 3, 2005