lecture 35 plane surfaces. spherical mirrors. spherical ceiling mirror spherical make-up or shaving...
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Lecture 35Plane surfaces.
Spherical mirrors.
Spherical ceiling mirror
Spherical make-up or shaving mirror
Image on a plane mirror
All the reflected rays seem to be coming from here!
Virtual image (the rays don’t come from it)
As explained in lecture 33:
How to find the image
• Draw two rays (one of them the normal to the surface, it’s a trivial one)
• Draw reflected rays.
• Extrapolate rays until they intersect.
ss’
s : location of the object
s’: location of the image
Positive in front of mirror
Negative behind mirror
Plane mirror:
s = -s’
Sign conventions
Position of object: s > 0 if object is on the same side of surface as incoming rays
Position of image: s’ > 0 if image is on the same side of surface as outgoing rays
Radius of curvature: R > 0 if center of curvature is on the same side of surface as outgoing rays
Magnification
y
Object’s height
Both y and y ’ can be negative if item is upside down!
Magnificationy
my
If m > 0, image is
upright.
If m < 0, image is inverted.
Example: For a plane mirror, m = +1
y ’
Image’s height
Reverse image
A B
C
A ’B’
C ’
Image on a plane mirror is virtual, upright and reversed.
Front and back are reversed
ACT: Refraction through a plane surface
object
s s’
Where does the spot appear to be?This image is:
A) Virtual
B) RealRays don’t really converge at that point, only their extrapolations.
The sign of s is: A) Positive B) Negative
Both object and incoming rays are left of surface.
The sign of s’ is: A) Positive B) Negative
Image is left of surface. Outgoing rays are right of the surface.
image
Image of an image (2)
Use first image as an object for second mirror. Easier…
Image for mirror 1 / Object for mirror 2
Object for mirror 1Image for mirror 2
1
2
(if you look at mirror 2 first, you get another 2 images; and than there are also the images of the images of the images … see front page of lecture 33 notes)
Spherical mirrors
C = center of curvatureV = vertexR = radius of curvature
Optical axis
C
V
Robject
Concave R > 0
Optical axis
V
Robject
C
Convex R < 0
Concave spherical mirror
s’
sR
C
htan
tan
tan
hshshR
If α is small (paraxial approximation),
2
Thus,2h h h
s s R
1 1 2s s R
Independent of h valid for all rays (with small
α)
Focal distance, focal point
C
If object is very far, incoming rays are all parallel and s ∞
Rays converge at one point called the focal point F
F2R
f
f (focal length)
1 1 2f R
Focal length (spherical mirror)
1 1 1s s f
DEMO: Focal point
Getting the image
If a screen or a photographic plate is placed here, image will form on it
s > 0
s’ > 0Image is real and inverted.
F
1 ray parallel to the axis, reflection goes through F
1 ray to vertex, reflection at equal angle
Magnification (spherical mirror)
ss’
y
y ’
tany ys s
y sm
y s
sm
s
It looks a little odd: image seems to be in front of mirror (and we’re used to plane mirrors, where it’s behind)
DEMOS:
Mirror and bulb
Mirrors and pigs
ACT: Spherical mirror
Object
What do you see if you place your eye at the position shown?
DEMO:As you walk out look at the background with your face close to
the mirror.
Image
A. Smaller, inverted, real image of the arrow
B. Blurred image, hard to recognize
C. Virtual image of the arrowF
In-class example: Closer to the mirror
An object is placed at distance f/2 from this mirror. The image is:
s s’ < 0
F
A) Smaller, real and upright
B) Smaller, virtual and inverted
C) Larger, real and inverted
D) Larger, virtual and upright
E) None of the above
2 1 1
2f
sf s f
0, virtuals f 2s
ms
1 larger
0 upright
m
m
Convex spherical mirror
F
Everything is the almost the same for the convex mirror, except R < 0, so f = R/2 < 0.
Image is virtual, smaller and upright.
DEMO: Convex mirror
Appendix: Refraction through a plane surface (entire calculation)
object image
1 1 2 2sin sinn n
s s’
θ1
θ2
θ1θ2
s s’ 1 2tan tan 0s s s
n1n2
Where does the spot appear to be (for frontal view)?
2
2 21 1 2 1 2 2 2 2
02 22 2 1 2 1 11 22
21
tan sin cos sin 1 sin 1 sin
tan sin cos sin 1 sin1 sin
n nss n nn
n