lecture 4: bjt small signal analysis
TRANSCRIPT
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ECE 334: Electronic Circuits
Lecture 4:
BJT Small Signal Analysis
Faculty of EngineeringFaculty of EngineeringFaculty of EngineeringFaculty of Engineering
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Example: Graphical Analysis
Input circuit
B-E voltage loop
VBB = IBRB +VBE
IB = (VBB - VBE)/RB
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Graphical construction of IB and VBE
IB = (VBB - VBE)/RB
If VBE = 0, IB = VBB/RB
If IB = 0, VBE = VBB
VBB/RB
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Load Line
Output circuit
C-E voltage loop
VCC = ICRC +VCE
IC = (VCC - VCE)/RC
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Graphical Construction of IC and VCE
VCC/RC
IC = (VCC - VCE)/RC
If VCE = 0, IC = VCC/RC
If IC = 0, VCE = VCC
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Graphical Analysis
Input
signal Output
signal
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•Load-line A results in bias point QA which is too close to VCC and thus limits the
positive swing of vCE.
•Load-line B results in an operating point too close to the saturation region, thus
limiting the negative swing of vCE.
Bias Point Location Effects
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A Practical BJT Amplifier using
Coupling and Bypass Capacitors
• AC coupling through capacitors is
used to inject an ac input signal and
extract the ac output signal without
disturbing the DC Q-point
• Capacitors provide negligible
impedance at frequencies of interest
and provide open circuits at dc.
In a practical amplifier design, C1 and
C3 are large coupling capacitors or dc
blocking capacitors, their reactance (XC
= |ZC| = 1/ωC) at signal frequency is
negligible. They are effective open
circuits for the circuit when DC bias is
considered.
C2 is a bypass capacitor. It provides a
low impedance path for ac current from
emitter to ground. It effectively
removes RE (required for good Q-point
stability) from the circuit when ac
signals are considered.
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DC and AC Analysis -- Application of
Superposition• DC analysis:
– Find the DC equivalent circuit by replacing all capacitors by open circuits and inductors (if any) by short circuits.
– Find the DC Q-point from the equivalent circuit by using the appropriate large-signal transistor model.
• AC analysis:
– Find the AC equivalent circuit by replacing all capacitors by short circuits, inductors (if any) by open circuits, dc voltage sources by ground connections and dc current sources by open circuits.
– Replace the transistor by its small-signal model (to be developed).
– Use this equivalent circuit to analyze the AC characteristics of the amplifier.
– Combine the results of dc and ac analysis (superposition) to yield the total voltages and currents in the circuit.
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DC Equivalent for the BJT Amplifier
• All capacitors in the original amplifier circuit are replaced by open
circuits, disconnecting vI, RI, and R3 from the circuit and leaving RE
intact. The the transistor Q will be replaced by its DC model.
DC Equivalent Circuit
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AC Equivalent for the BJT Amplifier
• The coupling and bypass capacitors are replaced by short circuits. The DC
voltage supplies are replaced with short circuits, which in this case connect
to ground.
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AC Equivalent for the BJT Amplifier
(contd.)
RB
= R1
R2
=10kΩ 30kΩ
R = RC
R3
= 4.3kΩ100kΩ
• By combining parallel resistors into equivalent RB and R, the equivalent AC
circuit above is constructed. Here, the transistor will be replaced by its
equivalent small-signal AC model (to be developed).
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Hybrid-Pi Small-Signal AC Model for
the BJT
• The hybrid-pi small-signal
model is the intrinsic low-
frequency representation of the
BJT.
• The small-signal parameters are
controlled by the Q-point and
are independent of the geometry
of the BJT.
Transconductance:
gm =IC
VT
≅ 40IC
Input resistance:
rπ =β
oV
T
IC
=β
o
gm
Output resistance:
ro=V
A+V
CE
IC
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Equivalent Forms of the Small-signal
Model for the BJT
• The voltage-controlled current source gmvbe can be transformed into a current-controlled current source,
• The basic relationship ic=βib is useful in both dc and ac analysis when the BJT is biased in the forward-active region.
vbe
= ib
rπ = ib
βo
gm
∴gmvbe
= gmibrπ =βoi
b
ic = gmvbe
+vce
ro
≅ gmvbe
=βoib
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Examples
• On the Board
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