lecture two 2010 pharmacy collage first...
TRANSCRIPT
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Lecture one- Pharmacy collage first Year
Analytical Chemistry
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Such as the amount of Active compounds in pharmaceutical formulations or biological samples.
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There are also different methods such as separation methods for example chromatographic separation methods.
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Molar mass(M) or Molecular weight(M.Wt)
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Molarity(M)= (mass / M.Wt) x (1000/Volume(ml))…. For solids
Molarity(M)= (Sp.grafity x w/w% x 1000) / M.Wt(g/mole).. For liquids
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1dL(diciliter) = 100mL
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= (V)
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Equivalent= is the mass of material providing Avogadro's number of reacting units.
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Formality (F) is the No of formula weight of a solute dissolved in 1 L solution.
F= number of formula weight /L or F= mili formula weight/ml Example : Exactly 5.00 g NaCl are dissolved in 100ml distilled water .calculate the formality of this solution?
No of formula weight= weight(gm) / gram F.Wt F.wt=5.00/58.44= 0.0856
Formality = 0.0856 /(100×0.001) = 0.856 gf.wt /L
Formality(F) is numerically the same as Molarity(M) . F is used for ionic salts that do not exist as molecules in the solid or in the solution. Formality = Molarity numerically F is used for total analytical concentration . M is used for equilibrium concentration.
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Molality(m) = mole of solute/1000g solvent
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The calculations of this type involved: 1- Convert the mass of compound to equivalent moles. 2- multiply by stoichiometric factor. 3- reconversion the data in mole to the metric units.
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Thanks