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  • 7/27/2019 Lecture12(20-3-11)

    1/4

    EE 332

    DEVICES AND CIRCUITS II

    Lecture 12

    Small-Signal Models

    and Single Transistor Amplifier (4)

    (CC Amplifier)

    CC AMPLIFIER (FOLLOWER)/INPUT RESISTANCE

    vx ix

    rb

    RL//RE

    rix

    ie=(+1)ix

    vb

    ve

    : ( 1)

    ( 1)

    x x x L

    x

    b L

    x

    K V L v i r i R

    vr r R

    i

    = + += = + +

    InputResistance

    Withtestsourceapplied:/ /

    C C

    i B bR R r

    Ingeneral,RE>>RL

    RiRB

    rb

    CC AMPLIFIER (FOLLOWER)/OUTPUT RESISTANCE

    vx

    ix

    Rthr i

    vbe

    Ro

    vb

    ve

    RE

    ( 1)

    ,

    ( 1)

    1

    1 1

    x

    x

    th

    x

    x

    th

    x th

    e

    x

    th

    e

    i i i i

    va n d i

    r R

    vi

    r R

    v r Rr

    i

    r Rr

    1

    1

    th

    e

    m

    Rr

    g

    = = + = +

    = + ++= = +

    = ++ +

    Outputresistance:Withtestsourceapplied:

    / /C Co E e

    = + +Usuallyverysmall

    R R rre

    re

    i

    CC AMPLIFIER (FOLLOWER)

    /SMALL SIGNAL MODEL

    Rs

    vS

    C1

    R2

    R1 RC

    RE

    Q1C2

    VCC

    RL

    vo

    R

    s

    vS

    C1

    R2

    R1 RC

    RE

    Q1C2

    VCC

    RL

    vovo

    vs

    RBRC

    RL

    rro

    gmvbe

    vbe

    Rs

    RE

    vo

    vs

    RBRC

    RL

    rro

    gmvbe

    vbe

    Rs

    RE

    54

  • 7/27/2019 Lecture12(20-3-11)

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    CC AMPLIFIER (FOLLOWER)/GAIN

    Problem:FindthegainofCB

    amplifier

    Given:

    , ,0.8 , 0.1 , 1001 :1.5, 100

    B E ON CE sat F

    R A

    v V V V QV V

    = = = = =

    1 2

    1 2

    10 ; 30 ; 5.1 ; 2.2 ;

    1 ; 10 ; 12 ; 10

    C E

    s L CC

    R k R k R k R k

    R k R k V V C C F

    = = = = = = = = =

    Rs

    vS

    C1

    R2

    R1 RC

    RE

    Q1C2

    VCC

    RL

    vo

    CC AMPLIFIER (FOLLOWER)/GAIN

    REQ

    VEQ

    RC

    RE

    Q1

    VCC

    vo

    ANSWER

    ANSWERAssumingBJToperatinginforwardactivemodeTheveninizingLHScircuit

    1

    1 2

    1 2

    3

    ( / / ) 7.5

    EQ CC

    EQ

    RV V V

    R R

    R R R k

    = =+= =

    Solvetheloop,

    ,

    ( 1)

    2.3

    EQ E E BE ON B EQ

    E B

    EQ BE ON

    V I R V I R

    I I

    V V

    10.0( 1) 7.5 101 2.2

    B

    EQ E

    I AR R k k

    = = =+ + +

    = + + = +

    IC

    IE

    IB

    CC AMPLIFIER (FOLLOWER)/GAIN

    REQ

    VEQ

    RC

    RE

    Q1

    VCC

    vo

    ANSWER

    ANSWER

    IC

    IE

    IB

    and

    10.0

    ,

    1 1.01

    B

    C E

    I A

    then

    I mA I m A

    = =SolveRHSloop

    5.1

    2.22

    4.67

    RC C C

    RE E E

    CE CC RC RE

    V R I V

    V R I V

    V V V V V

    = == == =

    SinceVCE=4.67>VCE,sat=0.1V

    TheBJToperatesinForwardActive

    region

    CC AMPLIFIER (FOLLOWER)/GAIN

    Rs

    vS

    C1

    R2

    R1

    RC

    RE

    Q1

    C2

    VCC

    RL

    vo

    ANSWER

    ANSWER

    Step1:DCanalysis DCeffectsonthedashbox 4resistorBJTcircuit

    55

  • 7/27/2019 Lecture12(20-3-11)

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    CC AMPLIFIER (FOLLOWER)/GAIN

    ANSWER

    ANSWER Step2:SmallSignalParameters:1

    4025

    100 2.540

    104.67105

    1

    C

    m

    T

    m

    A CE

    o

    C

    I mAg mS

    V mV

    r kg mS

    V V Vr k

    I mA

    = = == = =

    += = =

    CC AMPLIFIER (FOLLOWER)/GAIN

    ANSWER

    ANSWER

    vo

    vs

    RBRC

    RL

    rro

    gmvbe

    vbe

    Rs

    RE

    ( 1) [ / / ]

    [ ( 1) [ / / ]]

    ( 1) [ / / ]

    [ ( 1) [ / / ]]

    ( 1) [ / / ]

    ( 1) [ / / ]

    101 1803

    CC o

    v

    b

    o b E L

    b b b b E L

    CC o b E L

    v

    b b E L

    E L

    E L

    vA

    v

    v i R R

    v i r i r R R

    v i R R A

    v i r R R

    R R

    r R R

    == + = = + +

    + = = + + + = + +

    0.9862.5 101 1803k

    = =

    CC AMPLIFIER (FOLLOWER)/GAIN

    ANSWER

    ANSWER

    vo

    vs

    RBRC

    RL

    rro

    gmvbe

    vbe

    Rs

    RE

    (1 )[ / / ] 173

    / / 173 / /7.5 7.2

    7.2

    7.2 1

    CC o o b

    vss b s

    i

    b s

    i s

    b E L

    i b B

    b

    s

    v v vA

    v v v

    Rv v

    R R

    r r R R k

    0.986 0.878 0.866CBvs

    R r R k k k

    v k

    v k k

    = = = +

    A

    = + + = = = = = +

    Q

    = =

    CC AMPLIFIER (FOLLOWER)/GAIN

    ANSWER

    ANSWER

    Rs

    vS

    C1

    R2

    R1 RC

    RE

    Q1C2

    VCC

    RL

    vovo

    vs

    RBRC

    RL

    rro

    gmvbe

    vbe

    Rs

    RE

    vo

    vs

    RBRC

    RL

    rro

    gmvbe

    vbe

    Rs

    RE

    +

    56

  • 7/27/2019 Lecture12(20-3-11)

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    CC AMPLIFIER (FOLLOWER)/GAIN

    ANSWERANSWER

    vo

    vs

    RBRC

    RL

    rro

    gmvbe

    vbe

    Rs

    RE

    ( )( 1)( )

    0.710

    = =

    = +

    + +

    =

    CC o b e o

    i

    i i b e

    B E

    B b E L

    i i i iA

    i i i i

    R R

    R r R R

    ,

    7.20.986 0.710

    10

    i L v i

    i

    i v

    L

    Use

    A R A R

    RA A

    R

    k

    k

    = == =

    End of Lecture 12

    CC AMPLIFIER (FOLLOWER)/GAIN

    ANSWERANSWER

    vo

    vs

    RBRC

    RL

    rro

    gmvbe

    vbe

    Rs

    RE

    ( 1)

    ( 1)

    [ ( 1) ]

    o L

    b L

    L

    v i R

    and

    v ir i R

    i r R

    = += + += + +

    ( 1)

    [ ( 1) ]

    11

    CC o L

    vt

    b L

    CC m LL

    vt

    m LL

    m

    v RA

    v r Rg RR

    Ag R

    Rg

    + = = + + = ++

    AsgmRL>>1Voltagefollowerorbufferamp

    TerminalVoltagegain:

    RE//RLRL sinceRL