lecture12(20-3-11)
TRANSCRIPT
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7/27/2019 Lecture12(20-3-11)
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EE 332
DEVICES AND CIRCUITS II
Lecture 12
Small-Signal Models
and Single Transistor Amplifier (4)
(CC Amplifier)
CC AMPLIFIER (FOLLOWER)/INPUT RESISTANCE
vx ix
rb
RL//RE
rix
ie=(+1)ix
vb
ve
: ( 1)
( 1)
x x x L
x
b L
x
K V L v i r i R
vr r R
i
= + += = + +
InputResistance
Withtestsourceapplied:/ /
C C
i B bR R r
Ingeneral,RE>>RL
RiRB
rb
CC AMPLIFIER (FOLLOWER)/OUTPUT RESISTANCE
vx
ix
Rthr i
vbe
Ro
vb
ve
RE
( 1)
,
( 1)
1
1 1
x
x
th
x
x
th
x th
e
x
th
e
i i i i
va n d i
r R
vi
r R
v r Rr
i
r Rr
1
1
th
e
m
Rr
g
= = + = +
= + ++= = +
= ++ +
Outputresistance:Withtestsourceapplied:
/ /C Co E e
= + +Usuallyverysmall
R R rre
re
i
CC AMPLIFIER (FOLLOWER)
/SMALL SIGNAL MODEL
Rs
vS
C1
R2
R1 RC
RE
Q1C2
VCC
RL
vo
R
s
vS
C1
R2
R1 RC
RE
Q1C2
VCC
RL
vovo
vs
RBRC
RL
rro
gmvbe
vbe
Rs
RE
vo
vs
RBRC
RL
rro
gmvbe
vbe
Rs
RE
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CC AMPLIFIER (FOLLOWER)/GAIN
Problem:FindthegainofCB
amplifier
Given:
, ,0.8 , 0.1 , 1001 :1.5, 100
B E ON CE sat F
R A
v V V V QV V
= = = = =
1 2
1 2
10 ; 30 ; 5.1 ; 2.2 ;
1 ; 10 ; 12 ; 10
C E
s L CC
R k R k R k R k
R k R k V V C C F
= = = = = = = = =
Rs
vS
C1
R2
R1 RC
RE
Q1C2
VCC
RL
vo
CC AMPLIFIER (FOLLOWER)/GAIN
REQ
VEQ
RC
RE
Q1
VCC
vo
ANSWER
ANSWERAssumingBJToperatinginforwardactivemodeTheveninizingLHScircuit
1
1 2
1 2
3
( / / ) 7.5
EQ CC
EQ
RV V V
R R
R R R k
= =+= =
Solvetheloop,
,
( 1)
2.3
EQ E E BE ON B EQ
E B
EQ BE ON
V I R V I R
I I
V V
10.0( 1) 7.5 101 2.2
B
EQ E
I AR R k k
= = =+ + +
= + + = +
IC
IE
IB
CC AMPLIFIER (FOLLOWER)/GAIN
REQ
VEQ
RC
RE
Q1
VCC
vo
ANSWER
ANSWER
IC
IE
IB
and
10.0
,
1 1.01
B
C E
I A
then
I mA I m A
= =SolveRHSloop
5.1
2.22
4.67
RC C C
RE E E
CE CC RC RE
V R I V
V R I V
V V V V V
= == == =
SinceVCE=4.67>VCE,sat=0.1V
TheBJToperatesinForwardActive
region
CC AMPLIFIER (FOLLOWER)/GAIN
Rs
vS
C1
R2
R1
RC
RE
Q1
C2
VCC
RL
vo
ANSWER
ANSWER
Step1:DCanalysis DCeffectsonthedashbox 4resistorBJTcircuit
55
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CC AMPLIFIER (FOLLOWER)/GAIN
ANSWER
ANSWER Step2:SmallSignalParameters:1
4025
100 2.540
104.67105
1
C
m
T
m
A CE
o
C
I mAg mS
V mV
r kg mS
V V Vr k
I mA
= = == = =
+= = =
CC AMPLIFIER (FOLLOWER)/GAIN
ANSWER
ANSWER
vo
vs
RBRC
RL
rro
gmvbe
vbe
Rs
RE
( 1) [ / / ]
[ ( 1) [ / / ]]
( 1) [ / / ]
[ ( 1) [ / / ]]
( 1) [ / / ]
( 1) [ / / ]
101 1803
CC o
v
b
o b E L
b b b b E L
CC o b E L
v
b b E L
E L
E L
vA
v
v i R R
v i r i r R R
v i R R A
v i r R R
R R
r R R
== + = = + +
+ = = + + + = + +
0.9862.5 101 1803k
= =
CC AMPLIFIER (FOLLOWER)/GAIN
ANSWER
ANSWER
vo
vs
RBRC
RL
rro
gmvbe
vbe
Rs
RE
(1 )[ / / ] 173
/ / 173 / /7.5 7.2
7.2
7.2 1
CC o o b
vss b s
i
b s
i s
b E L
i b B
b
s
v v vA
v v v
Rv v
R R
r r R R k
0.986 0.878 0.866CBvs
R r R k k k
v k
v k k
= = = +
A
= + + = = = = = +
Q
= =
CC AMPLIFIER (FOLLOWER)/GAIN
ANSWER
ANSWER
Rs
vS
C1
R2
R1 RC
RE
Q1C2
VCC
RL
vovo
vs
RBRC
RL
rro
gmvbe
vbe
Rs
RE
vo
vs
RBRC
RL
rro
gmvbe
vbe
Rs
RE
+
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CC AMPLIFIER (FOLLOWER)/GAIN
ANSWERANSWER
vo
vs
RBRC
RL
rro
gmvbe
vbe
Rs
RE
( )( 1)( )
0.710
= =
= +
+ +
=
CC o b e o
i
i i b e
B E
B b E L
i i i iA
i i i i
R R
R r R R
,
7.20.986 0.710
10
i L v i
i
i v
L
Use
A R A R
RA A
R
k
k
= == =
End of Lecture 12
CC AMPLIFIER (FOLLOWER)/GAIN
ANSWERANSWER
vo
vs
RBRC
RL
rro
gmvbe
vbe
Rs
RE
( 1)
( 1)
[ ( 1) ]
o L
b L
L
v i R
and
v ir i R
i r R
= += + += + +
( 1)
[ ( 1) ]
11
CC o L
vt
b L
CC m LL
vt
m LL
m
v RA
v r Rg RR
Ag R
Rg
+ = = + + = ++
AsgmRL>>1Voltagefollowerorbufferamp
TerminalVoltagegain:
RE//RLRL sinceRL