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  • 7/30/2019 Lecture13 Gradually Varied Flow1 2

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    Gradually Varied Flow I+II

    Hydromechanics VVR090

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    Gradually Varied Flow

    Depth of flow varies with longitudinal distance.

    Occurs upstream and downstream control sections.

    Governing equation:

    21

    =

    o fS Sdy

    dx Fr

    (previously Sf= 0 was studied)

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    Derivation of Governing Equation

    Total energy:

    2

    2uH z y

    g= + +

    Differentiating with respect to distance:

    ( )2 / 2= + +

    d u gdH dz dy

    dx dx dx dx

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    =

    =

    f

    o

    dH

    Sdx

    dzSdx

    For a given flow rate:

    ( )2 2 22

    3 3

    / 2d u g Q dA dy Q T dy dyFr

    dx gA dy dx gA dx dx

    = = =

    (slope of energy grade line)

    (bottom slope)

    21

    =

    o fS Sdy

    dx Fr Resulting equation:

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    Definition of Water Surface Slope

    Water surface slope dy/dx is defined with respect tothe channel bottom.

    Hydrostatic pressure distr ibution is assumed

    (streamlines should be reasonably straight and parallel).

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    The head loss for a specific reach is equal to the

    head loss in the reach for a uniform flow having the

    same R and u. Manning equation yields.

    The slope of the channel is small

    No air entrainment

    Fixed velocity distribution

    Resistance coefficient constant in the reach under

    consideration

    2 2

    4 / 3f

    n uS

    R=

    Assumptions made when solving the gradually varied flow

    equation:

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    Classification of Gradually Varied Flow Profiles

    The following condit ions prevail:

    Ify < yN, then Sf > So

    Ify > yN, then Sf < So

    IfFr> 1, then y < yc

    IfFr< 1, then y > yc

    IfSf = So, then y = yN

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    Water surface profi les may be classif ied with respect to:

    the channel slope

    the relationship between y, yN, and yc.

    Profile categories:

    M (mild) 0 < So < Sc

    S (steep) So > Sc > 0

    C (critical) So = Sc

    A (adverse) So < 0

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    Gradually Varied Flow

    Profile Classification I

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    Gradually Varied Flow Profile Classification II

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    Mild Slope (M-Profiles)

    Profile types:

    1: y > yN > yc => So > Sf and Fr< 1

    => dy/dx > 0

    2: yN > y > yc => So < Sf and Fr< 1

    => dy/dx < 0

    3: yN > yC > y => So < Sf and Fr> 1=> dy/dx > 0

    0 < So < Sc

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    Steep Slope (S-Profiles)

    Profile types:

    1: y > yc > yN => So > Sf and Fr< 1

    => dy/dx > 0

    2: yc > y > yN => So > Sf and Fr> 1

    => dy/dx < 0

    3: yc > yN > y => So < Sf and Fr> 1=> dy/dx > 0

    0 < Sc < So

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    Final Form of Water Surface Profile

    1. y , Sf 0, Fr 0, and dy/dx So

    2. y yN, Sf So, and dy/dx 0

    3. y yc, Fr 1, and dy/dx

    21

    =

    o fS Sdy

    dx Fr

    Asymptotic conditions:

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    Transition from Subcrit ical to Supercritical Flow

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    Transition from Supercritical to Subcrit ical Flow

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    Example: Flow into a Channel from a Reservoir

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    Flow Controls

    determine the depth in channel either upstream or

    downstream such points.

    usually feature a change from subcritical to supercrit icalflow

    occur at physical barriers, for example, sluice gates,

    dams, weirs, drop structures, or changes in channelslope

    Locations in the channel where the relationship between the

    water depth and flow rate is known (or controllable).

    Controls:

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    Strategy for Analysis of Open Channel Flow

    1. Start at control points2. Proceed upstream or downstream depending on

    whether subcritical or supercritical flow occurs,

    respectively

    Typical approach in the analysis:

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    Computation of Gradually Varied Flow

    21

    =

    o fS Sdy

    dx Fr Governing equation:

    Solutions must begin at a control section and proceedin the direction in which the control operates.

    Gradually varied flow may approach uniform flow

    asymptotically, but from a practical point of view a

    reasonable definition of convergence is applied.

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    Uniform Channel

    Prismatic channel with constant slope and resistance coefficient.

    Apply energy equation over a small distance Dx:

    2

    2o f

    d uy S S

    dx g

    + =

    Express the equation in difference form:

    ( )2

    2o f

    uy S S x

    g

    + =

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    Over the short distance Dx assume that Manningsequation is suitable to describe the frictional losses (S

    f

    ):

    2 2

    4 / 3f

    n uS

    R

    =

    The equation to be solved may be written:

    ( )

    ( )

    2

    2 2 4 / 3

    / 2

    /o mean

    y u gx

    S n u R

    + =

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    Dx i

    Reach i

    x

    y i y i+1

    ( ) ( )

    ( )

    2 2

    1

    2 2 4 / 3

    1/ 2

    / 2 / 2

    /

    i ii

    o i

    y u g y u gx

    S n u R

    +

    +

    + + =

    All quantities known at i. Assume yi+1

    and computeDx i (u i+1 given by the continuity equation).

    u i

    u i+1

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    Example 6.1

    A trapezoidal channel with b = 6.1 m, n = 0.025, z = 2, and So =

    0.001 carries a discharge of 28 m3/s. If this channel terminates in

    a free overfall, determine the gradually varied flow profile by the

    step method.

    b = 6.1 m

    2

    1yN

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    Solution:

    Compute normal water depth.

    ( )

    ( )

    2 / 3

    2

    2

    1

    2 1

    2 1

    o

    N N

    N

    N N

    N

    Q AR S n

    A b zy y

    P b y z

    b zy yR

    b y z

    =

    = += + +

    +

    = + +

    yN = 1.91 m

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    Compute crit ical water depth:

    ( )

    1/

    2

    c c c

    c c c

    c

    u QFr

    gD A gA T

    A b zy y

    T b zy

    = = =

    = +

    = +

    yc = 1.14 m

    yN > y > yc

    Mild slope (yN > yc)M2 profile

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    Table for step calculation:

    y A P R u u2

    /2g Sf Sfav Dx S (Dx)1.14 9.55 11.20 0.85 2.93 0.438 0.00670.0058 3 3

    1.24 10.64 11.64 0.91 2.63 0.353 0.0049

    0.0044 9.3 12.3

    1.32 11.54 12.00 0.96 2.43 0.300 0.0039

    and so on( ) ( )2 2

    1

    , 1/ 2

    / 2 / 2i i

    i

    o f i

    y u g y u gx

    S S

    +

    +

    + + =

    ( ), 1/ 2 , 1 ,1

    2f i f i f i

    S S S+ += +

    2 2

    4 / 3f

    n uS

    R=

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    Other Solution Methods

    Problem with the step method is that the water depths isobtained at arbitrary locations (i.e., the water depth is not

    calculated at fixed x-locations).

    By direct integration of the governing equation this problemcan be circumvented.

    Different approaches for direct integration:semi-analytic

    trial-and-error

    finite difference

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    Semi-Analytic Approach

    Find solution in terms of closed-form functions (integrals).

    Employ suitable approximations to these functions or

    some look-up tables.

    Approach OK for channels with constant properties.

    (for more information, see French)

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    Trial-and-Error Approach

    Well-suited for computations in non-prismatic channels.

    Channel properties (e.g., resistance coefficient and

    shape) are a function of longitudinal distance.

    Depth is obtained at specific x-locations.

    Apply energy equation between two stations locatedD

    xapart (z is the elevation of the water surface):

    2

    2 2

    1 2

    1 2

    2

    2 2

    f e

    f e

    uz S x hg

    u uz z S x h

    g g

    + =

    + = + + +

    he: eddy losses

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    Equation is solved by trial-and-error (from 2 to 1):

    1.Assume y1 u1 (continuity equation)2. Compute S

    f

    (and he

    , if needed)

    3. Compute y1 from governing equation. If this value agrees

    with the assumed y1, the solution has been found.

    Otherwise continue calculations.

    Estimate of frictional losses:

    ( )1 212

    f f fS S S= +

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    Example 6.4

    A trapezoidal channel with b = 20 ft, n = 0.025, z = 2, and So =

    0.001 carries a discharge of 1000 ft3/s. If this channel terminates

    in a free overfall and there are no eddy losses, determine the

    gradually varied flow profile by the trial-and-error step method.

    b = 20 ft

    2

    1yN

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    Solution Table

    Stn. z y A u u2/2g H1 R Sf Sfav Dx hf H2

    0 103.74 3.74 103 9.71 1.46 105.20 2.81 0.00670 105.20

    116 104.62 4.50 130 7.69 0.92 105.54 3.24 0.00347 0.00509 116 0.590 105.79

    105.02 4.90 146 6.85 0.73 105.75 3.48 0.00251 0.00461 116 0.535 105.73

    355 105.56 5.20 158 6.33 0.62 106.18 3.65 0.00201 0.00226 239 0.540 106.27

    105.93 5.32 173 5.78 0.52 106.45 3.85 0.00156 0.00204 239 0.724 106.47

    745 106.34 5.60 175 5.71 0.51 106.85 3.89 0.00150 0.00153 490 1.14 107.59

    106.96 6.21 201 4.98 0.385 107.34 4.21 0.00103 0.00130 490 0.97 107.42

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    Finite Difference Approach

    Suitable for application on a computer (small length stepsDx might be needed).Can be applied for completely arbitrary channel

    configurations and properties.

    A range of numerical approaches are available to solve the

    governing equations based on finite differences.

    The equation is written in difference form and solved in terms

    ofy:

    ( )

    2

    2 o fu

    y S S xg

    + =

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    Examples of Gradually Varied Flow

    Flow in channel between two reservoirs (lakes):

    1. Steep slope, low downstream water level

    2. Steep slope, high downstream water level

    3. Mild slope, long channel

    4. Mild slope, short channel

    5. Sluice gate located in the channel

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    Steep Slope, Low Downstream Water Level

    Critical section at inflow to channel. Normal water depth

    occurs some distance downstream in the channel with Fr> 1(yN < ycr). A hydraulic jump develops before water is

    discharged to the downstream lake.

    Q in the channel depends on H1 and critical section.

    Critical

    section Hydraulic

    jump

    Lake

    Lake

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    Steep Slope, High Downstream Water Level

    Downstream water level is high enough to cause dammingeffects to the upstream lake. No critical section occurs in the

    inflow section. y > ycr > yN in the channel.

    Q depends on H1 and H2.

    No critical section

    Fr < 1 in the channel,

    although it is steep

    LakeLake

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    Mild Slope, Long Channel

    Mild slope and long channel implies that normal water depth

    occurs with yN > ycr. Normal water depth is also attained in

    the inflow section to the channel. Non-uniform flow develops

    in the downstream part of the channel before discharge tothe lake.

    Q depends on H1 and yN in the inflow section.

    LakeLake

    uniform flow non-uniform flow

    Normal water depth

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    Mild Slope, Short Channel

    A short channel implies that normal water depth will not

    occur and y > yN > ycr. Non-uniform flow develops in the

    entire channel because of the downstream effects of the

    lake.

    Q depends on H1 and H2.

    Lake Lake

    Non-uniform flow

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    Sluice Gate Located in the Channel

    Sluice gate cause damming upstream affecting inflow

    from lake. Discharge from sluice gate depends on

    upstream water surface elevation over gate opening.

    Supercrit ical flow occurs downstream the gate,

    followed by a hydraulic jump before the downstream

    lake is encountered.

    Q depends on H1 and sluice gate properties.

    Jump

    Sluice gate (Q a

    function ofy)Lake

    Lake

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    Calculation Procedure for Some Gradually

    Varied Flows

    1. Flow from a reservoir to a long, steeply sloping channel

    2. Flow from a reservoir to a long, mildly sloping channel

    3. Flow from a reservoir to a short, mildly sloping channel

    where a downstream water level affects the flow in the

    channel

    4. Flow from a reservoir to a short, steeply sloping channel

    where a downstream water level affects the flow in the

    channel

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    Lake

    Flow from a Reservoir to a Long, Steeply

    Sloping channel

    Critical section occurs in inflow section. Employ energy

    equation from lake surface to inflow section.

    2

    12

    1

    crcr

    cr

    cr

    uH y

    g

    uFrgy

    = +

    = =

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    Flow from a Reservoir to a Long, Mildly

    Sloping Channel

    uniform flow non-uniform flow

    Lake

    Lake

    Normal depth occurs in inflow section. Employ energy equation

    from lake surface to inf low section.

    2

    1

    2 / 3 1/ 2

    2

    1

    NN

    N N o

    uH y

    g

    u R Sn

    = +

    =

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    Flow from Reservoir to Short, Mildly Sloping Channel;

    Downstream Water Level Affects Flow in Channel

    Downstream lake water level affects inflow from upstream

    lake. Non-uniform flow prevails. Q depends on H1 and H2.

    Assume Q = Q1. Do a step calculation from downstreamlake water level to inflow section. Employ energy equation

    from inflow section to upstrem lake water level. H1 is

    regarded as unknown. Calculate for a new flow Q2 which

    gives a new upstream lake water level.

    Lake Lake

    non-uniform flow

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    Make a plot ofH1 as a function ofQ.

    Determine the correct Q based on the actual upstream lake

    water level H1.

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    Flow from Reservoir to Short, Steeply Sloping Channel;

    Downstream Water Level Affects Flow in Channel

    LakeLake

    Non-uniform flow Hydraulic

    Jump

    Non-uniform

    flow

    Critical section at inflow to channel. Make a step calculation

    from upstream lake and downstream lake. The hydraulic jump

    occur where the jump equation is satisfied.

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    Hydraulic jump is assumed to have negligible spatial

    extension.

    ( )

    ( )

    22

    1

    1

    212

    2

    1

    1 8 12

    1 1 8 12

    y

    Fry

    y Fry

    = +

    = +