lesson 21: curve sketching ii (section 10 version)
TRANSCRIPT
. . . . . .
Section4.4CurveSketchingII
V63.0121, CalculusI
April1, 2009
Announcements
I
. . . . . .
GraphingChecklist
Tographafunction f, followthisplan:
0. Findwhen f ispositive, negative, zero, notdefined.
1. Find f′ andformitssignchart. Concludeinformationaboutincreasing/decreasingandlocalmax/min.
2. Find f′′ andformitssignchart. Concludeconcaveup/concavedownandinflection.
3. Puttogetherabigcharttoassemblemonotonicityandconcavitydata
4. Graph!
. . . . . .
Outline
MoreExamplesPointsofnondifferentiabilityHorizontalasymptotesVerticalasymptotesTrigonometricandpolynomialtogether
. . . . . .
ExampleGraph f(x) = x +
√|x|
I Thisfunctionlooksstrangebecauseoftheabsolutevalue.Butwheneverwebecomenervous, wecanjusttakecases.
I First, lookat f byitself. Wecantellthat f(0) = 0 andthatf(x) > 0 if x ispositive. Aretherenegativenumberswhicharezeroesfor f? Yes, if x = −1 thenx +
√|x| = −1 +
√1 = 0. Nootherzerosexist.
. . . . . .
ExampleGraph f(x) = x +
√|x|
I Thisfunctionlooksstrangebecauseoftheabsolutevalue.Butwheneverwebecomenervous, wecanjusttakecases.
I First, lookat f byitself. Wecantellthat f(0) = 0 andthatf(x) > 0 if x ispositive. Aretherenegativenumberswhicharezeroesfor f? Yes, if x = −1 thenx +
√|x| = −1 +
√1 = 0. Nootherzerosexist.
. . . . . .
Asymptoticbehavior
I Asymptotically, it’sclearthat limx→∞
f(x) = ∞, becauseboth
termstendto ∞.I Whatabout x → −∞? Thisisnowindeterminateoftheform
−∞ + ∞. Toresolveit, firstlet y = −x tomakeitlookmorefamiliar:
limx→−∞
(x +
√−x
)= lim
y→∞(−y +
√y) = lim
y→∞(√y− y)
Nowmultiplybytheconjugate:
limy→∞
(√y− y) ·
√y + y
√y + y
= limy→∞
y− y2√y + y
= −∞
. . . . . .
Thederivative
First, assume x > 0, so
f′(x) =ddx
(x +
√x)
= 1 +1
2√x
Thisisalwayspositive. Also, weseethat limx→0+
f′(x) = ∞ and
limx→∞
f′(x) = 1. If x isnegative, wehave
f′(x) =ddx
(x +
√−x
)= 1− 1
2√−x
Again, thislooksweirdbecause√−x appearstobeanegative
number. Butsince x < 0, −x > 0.
. . . . . .
Monotonicity
Weseethat f′(x) = 0 when
1 =1
2√−x
=⇒√−x =
12
=⇒ −x =14
=⇒ x = −14
Noticealsothat limx→0−
f′(x) = −∞ and limx→−∞
f′(x) = 1. Wecan’t
makeamulti-factorsignchartbecauseoftheabsolutevalue, buttheconclusionisthis:
..f′(x)
.f(x).
.−14
.0
. max
..0
.∓∞
. cusp
.+
.↗.−.↘
.+
.↗
. . . . . .
Concavity
If x > 0, then
f′′(x) =ddx
(1 +
12x−1/2
)= −1
4x−3/2
Thisisnegativewhenever x < 0. If x < 0, then
f′′(x) =ddx
(1− 1
2(−x)−1/2
)= −1
4(−x)−3/2
whichisalsoalwaysnegativefornegative x. Anotherwayto
writethisis f′′(x) = −14|x|−3/2. Hereisthesignchart:
..f′′(x)
.f(x)..0
.−∞.−−.⌢
.
..−−.⌢
. . . . . .
Synthesis
Nowwecanputthesethingstogether.
..f′(x)
.monotonicity.
.−14
.0 ..0
.∓∞.+
.↗.−.↘
.+
.↗.f′′(x)
.concavity..0
.−∞.−−.⌢
.−−.⌢
.−−.⌢
.f(x)
.shape.
.−1.0
. zero
..−1
4
.14
. max
..0.0
. cusp." . ."
. . . . . .
Graph
.
.f(x)
.shape.
.−1.0
. zero
..−1
4
.14
. max
..0.0
. cusp." . ."
.x
.f(x)
..(−1, 0) .
.(−14 ,
14)
..(0, 0)
. . . . . .
ExampleGraph f(x) = xe−x2
Beforetakingderivatives, wenoticethat f isodd, that f(0) = 0,and lim
x→∞f(x) = 0
. . . . . .
ExampleGraph f(x) = xe−x2
Beforetakingderivatives, wenoticethat f isodd, that f(0) = 0,and lim
x→∞f(x) = 0
. . . . . .
Monotonicity
Now
f′(x) = 1 · e−x2 + xe−x2(−2x) =(1− 2x2
)e−x2
=(1−
√2x
)(1 +
√2x
)e−x2
Thefactor e−x2 isalwayspositivesoitdoesn’tfigureintothesignof f′(x). Sooursignchartlookslikethis:
. .1−√2x.
.√
1/2
.0.+ .+ .−
.1 +√2x.
.−√
1/2
.0.− .+ .+
.f′(x)
.f(x).
.−√
1/2
.0
.min
..√
1/2
.0
. max
.−.↘
.+
.↗.−.↘
. . . . . .
Concavity
Nowwelookat f′′(x):
f′′(x) = (−4x)e−x2 + (1− 2x2)e−x2(−2x) =(4x3 − 6x
)e−x2
= 2x(2x2 − 3)e−x2
. .2x..0.0.− .− .+ .+
.√2x−
√3.
.√
3/2
.0.− .− .− .+
.√2x +
√3.
.−√
3/2
.0.− .+ .+ .+
.f′′(x)
.f(x).
.−√
3/2
.0
.IP
..0.0
.IP
..√
3/2
.0
.IP
.−−.⌢
.++.⌣
.−−.⌢
.++.⌣
. . . . . .
Synthesis
..f′(x)
.monotonicity.
.−√
1/2
.0 ..√
1/2
.0.−.↘
.−.↘
.+
.↗.+
.↗.−.↘
.−.↘
.f′′(x)
.concavity.
.−√
3/2
.0 ..0.0 .
.√
3/2
.0.−−.⌢
.++.⌣
.++.⌣
.−−.⌢
.−−.⌢
.++.⌣
.f(x)
.shape.
.−√
1/2
.− 1√2e
.min
..√
1/2
. 1√2e
. max
..−
√3/2
.−√
32e3
.IP
..0.0
.IP
..√
3/2
.√
32e3
.IP
. . . " ." . .
. . . . . .
Graph
.
.x
.f(x)
.
.(−
√1/2,− 1√
2e
)
..(√
1/2, 1√2e
)
.
.(−
√3/2,−
√32e3
)..(0, 0)
..(√
3/2,√
32e3
)
.f(x)
.shape.
.−√
1/2
.− 1√2e
.min
..√
1/2
. 1√2e
. max
..−
√3/2
.−√
32e3
.IP
..0.0
.IP
..√
3/2
.√
32e3
.IP
. . . " ." . .
. . . . . .
Example
Graph f(x) =1x
+1x2
. . . . . .
Step0Findwhen f ispositive, negative, zero, notdefined.
Weneedtofactor f:
f(x) =1x
+1x2
=x + 1x2
.
Thismeans f is 0 at −1 andhastroubleat 0. Infact,
limx→0
x + 1x2
= ∞,
so x = 0 isaverticalasymptoteofthegraph. Wecanmakeasignchartasfollows:
. .x + 1..0.−1
.− .+
.x2..0.0
.+ .+
.f(x)..∞.0
..0.−1
.− .+ .+
. . . . . .
Step0Findwhen f ispositive, negative, zero, notdefined. Weneedtofactor f:
f(x) =1x
+1x2
=x + 1x2
.
Thismeans f is 0 at −1 andhastroubleat 0. Infact,
limx→0
x + 1x2
= ∞,
so x = 0 isaverticalasymptoteofthegraph.
Wecanmakeasignchartasfollows:
. .x + 1..0.−1
.− .+
.x2..0.0
.+ .+
.f(x)..∞.0
..0.−1
.− .+ .+
. . . . . .
Step0Findwhen f ispositive, negative, zero, notdefined. Weneedtofactor f:
f(x) =1x
+1x2
=x + 1x2
.
Thismeans f is 0 at −1 andhastroubleat 0. Infact,
limx→0
x + 1x2
= ∞,
so x = 0 isaverticalasymptoteofthegraph. Wecanmakeasignchartasfollows:
. .x + 1..0.−1
.− .+
.x2..0.0
.+ .+
.f(x)..∞.0
..0.−1
.− .+ .+
. . . . . .
Forhorizontalasymptotes, noticethat
limx→∞
x + 1x2
= 0,
so y = 0 isahorizontalasymptoteofthegraph. Thesameistrueat −∞.
. . . . . .
Monotonicity
Wehavef′(x) = − 1
x2− 2
x3= −x + 2
x3.
Thecriticalpointsare x = −2 and x = 0. Wehavethefollowingsignchart:
. .−(x + 2)..0.−2
.+ .−
.x3..0.0
.− .+
.f′(x)
.f(x)..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.min .VA
. . . . . .
Monotonicity
Wehavef′(x) = − 1
x2− 2
x3= −x + 2
x3.
Thecriticalpointsare x = −2 and x = 0. Wehavethefollowingsignchart:
. .−(x + 2)..0.−2
.+ .−
.x3..0.0
.− .+
.f′(x)
.f(x)..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.min .VA
. . . . . .
Monotonicity
Wehavef′(x) = − 1
x2− 2
x3= −x + 2
x3.
Thecriticalpointsare x = −2 and x = 0. Wehavethefollowingsignchart:
. .−(x + 2)..0.−2
.+ .−
.x3..0.0
.− .+
.f′(x)
.f(x)..∞.0
..0.−2
.− .+ .−
.↘ .↗ .↘.min .VA
. . . . . .
Monotonicity
Wehavef′(x) = − 1
x2− 2
x3= −x + 2
x3.
Thecriticalpointsare x = −2 and x = 0. Wehavethefollowingsignchart:
. .−(x + 2)..0.−2
.+ .−
.x3..0.0
.− .+
.f′(x)
.f(x)..∞.0
..0.−2
.− .+ .−.↘
.↗ .↘.min .VA
. . . . . .
Monotonicity
Wehavef′(x) = − 1
x2− 2
x3= −x + 2
x3.
Thecriticalpointsare x = −2 and x = 0. Wehavethefollowingsignchart:
. .−(x + 2)..0.−2
.+ .−
.x3..0.0
.− .+
.f′(x)
.f(x)..∞.0
..0.−2
.− .+ .−.↘ .↗
.↘.min .VA
. . . . . .
Monotonicity
Wehavef′(x) = − 1
x2− 2
x3= −x + 2
x3.
Thecriticalpointsare x = −2 and x = 0. Wehavethefollowingsignchart:
. .−(x + 2)..0.−2
.+ .−
.x3..0.0
.− .+
.f′(x)
.f(x)..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.min .VA
. . . . . .
Monotonicity
Wehavef′(x) = − 1
x2− 2
x3= −x + 2
x3.
Thecriticalpointsare x = −2 and x = 0. Wehavethefollowingsignchart:
. .−(x + 2)..0.−2
.+ .−
.x3..0.0
.− .+
.f′(x)
.f(x)..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.min
.VA
. . . . . .
Monotonicity
Wehavef′(x) = − 1
x2− 2
x3= −x + 2
x3.
Thecriticalpointsare x = −2 and x = 0. Wehavethefollowingsignchart:
. .−(x + 2)..0.−2
.+ .−
.x3..0.0
.− .+
.f′(x)
.f(x)..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.min .VA
. . . . . .
Concavity
Wehave
f′′(x) =2x3
+6x4
=2(x + 3)
x4.
Thecriticalpointsof f′ are −3 and 0. Signchart:
. .(x + 3)..0.−3
.− .+
.x4..0.0
.+ .+
.f′(x)
.f(x)..∞.0
..0.−3
.−− .++ .++.⌢ .⌣ .⌣
.IP .VA
. . . . . .
Concavity
Wehave
f′′(x) =2x3
+6x4
=2(x + 3)
x4.
Thecriticalpointsof f′ are −3 and 0. Signchart:
. .(x + 3)..0.−3
.− .+
.x4..0.0
.+ .+
.f′(x)
.f(x)..∞.0
..0.−3
.−− .++ .++.⌢ .⌣ .⌣
.IP .VA
. . . . . .
Concavity
Wehave
f′′(x) =2x3
+6x4
=2(x + 3)
x4.
Thecriticalpointsof f′ are −3 and 0. Signchart:
. .(x + 3)..0.−3
.− .+
.x4..0.0
.+ .+
.f′(x)
.f(x)..∞.0
..0.−3
.−−
.++ .++.⌢ .⌣ .⌣
.IP .VA
. . . . . .
Concavity
Wehave
f′′(x) =2x3
+6x4
=2(x + 3)
x4.
Thecriticalpointsof f′ are −3 and 0. Signchart:
. .(x + 3)..0.−3
.− .+
.x4..0.0
.+ .+
.f′(x)
.f(x)..∞.0
..0.−3
.−− .++
.++.⌢ .⌣ .⌣
.IP .VA
. . . . . .
Concavity
Wehave
f′′(x) =2x3
+6x4
=2(x + 3)
x4.
Thecriticalpointsof f′ are −3 and 0. Signchart:
. .(x + 3)..0.−3
.− .+
.x4..0.0
.+ .+
.f′(x)
.f(x)..∞.0
..0.−3
.−− .++ .++
.⌢ .⌣ .⌣
.IP .VA
. . . . . .
Concavity
Wehave
f′′(x) =2x3
+6x4
=2(x + 3)
x4.
Thecriticalpointsof f′ are −3 and 0. Signchart:
. .(x + 3)..0.−3
.− .+
.x4..0.0
.+ .+
.f′(x)
.f(x)..∞.0
..0.−3
.−− .++ .++.⌢
.⌣ .⌣
.IP .VA
. . . . . .
Concavity
Wehave
f′′(x) =2x3
+6x4
=2(x + 3)
x4.
Thecriticalpointsof f′ are −3 and 0. Signchart:
. .(x + 3)..0.−3
.− .+
.x4..0.0
.+ .+
.f′(x)
.f(x)..∞.0
..0.−3
.−− .++ .++.⌢ .⌣
.⌣
.IP .VA
. . . . . .
Concavity
Wehave
f′′(x) =2x3
+6x4
=2(x + 3)
x4.
Thecriticalpointsof f′ are −3 and 0. Signchart:
. .(x + 3)..0.−3
.− .+
.x4..0.0
.+ .+
.f′(x)
.f(x)..∞.0
..0.−3
.−− .++ .++.⌢ .⌣ .⌣
.IP .VA
. . . . . .
Concavity
Wehave
f′′(x) =2x3
+6x4
=2(x + 3)
x4.
Thecriticalpointsof f′ are −3 and 0. Signchart:
. .(x + 3)..0.−3
.− .+
.x4..0.0
.+ .+
.f′(x)
.f(x)..∞.0
..0.−3
.−− .++ .++.⌢ .⌣ .⌣
.IP
.VA
. . . . . .
Concavity
Wehave
f′′(x) =2x3
+6x4
=2(x + 3)
x4.
Thecriticalpointsof f′ are −3 and 0. Signchart:
. .(x + 3)..0.−3
.− .+
.x4..0.0
.+ .+
.f′(x)
.f(x)..∞.0
..0.−3
.−− .++ .++.⌢ .⌣ .⌣
.IP .VA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+
.HA . .IP . .min . " .0 . " .VA . .HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA
. .IP . .min . " .0 . " .VA . .HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA .
.IP . .min . " .0 . " .VA . .HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA . .IP
. .min . " .0 . " .VA . .HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA . .IP .
.min . " .0 . " .VA . .HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA . .IP . .min
. " .0 . " .VA . .HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA . .IP . .min . "
.0 . " .VA . .HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA . .IP . .min . " .0
. " .VA . .HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA . .IP . .min . " .0 . "
.VA . .HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA . .IP . .min . " .0 . " .VA
. .HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA . .IP . .min . " .0 . " .VA .
.HA
. . . . . .
Synthesis
.
.f′
.monotonicity..∞.0
..0.−2
.− .+ .−.↘ .↗ .↘
.f′′
.concavity..∞.0
..0.−3
.−− .++ .−−.⌢ .⌣ .⌣
.f
.shapeof f..∞.0
..0.−1
..−2.−1/4
..−3.−2/9
.−∞.0
.∞.0
.− .+ .+.HA . .IP . .min . " .0 . " .VA . .HA
. . . . . .
Graph
. .x
.y
..(−3,−2/9)
..(−2,−1/4)
. . . . . .
ProblemGraph f(x) = cos x− x
-5 5 10
-10
-5
5
. . . . . .
ProblemGraph f(x) = cos x− x
-5 5 10
-10
-5
5
. . . . . .
ProblemGraph f(x) = x ln x2
-3 -2 -1 1 2 3
-6
-4
-2
2
4
6
. . . . . .
ProblemGraph f(x) = x ln x2
-3 -2 -1 1 2 3
-6
-4
-2
2
4
6