lesson 5.5--complex numbers and rootsweb.wapak.org/hs/3math/rogers/adv alg 2/2-24-10 lesson...
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Lesson 5.5--Complex Numbers and Roots
You can see in the graph of f(x) = x2 + 1 below that f has no real zeros. If you solve the corresponding equation 0 = x2 + 1, you find that x = ,which has no real solutions.
![Page 2: Lesson 5.5--Complex Numbers and Rootsweb.wapak.org/hs/3Math/Rogers/Adv Alg 2/2-24-10 Lesson 5.5.pdf · Lesson 5.5--Complex Numbers and Roots You can see in the graph of f(x) = x2](https://reader031.vdocuments.net/reader031/viewer/2022022516/5b03993c7f8b9a6c0b8c93de/html5/thumbnails/2.jpg)
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Express the number in terms of i.Example:
Solve the equation.Example:
5x2 + 90 = 0
9x2 + 25 = 0
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Every complex number has a real part a and an imaginary part b.
Real numbers are complex numbers where b = 0. Imaginary numbers are complex numbers where a = 0 and b ≠ 0. These are sometimes called pure imaginary numbers.
Two complex numbers are equal if and only if their real parts are equal and their imaginary parts are equal.
Example:Find the values of x and y that make each equation true.
2x – 6i = –8 + (20y)i
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![Page 4: Lesson 5.5--Complex Numbers and Rootsweb.wapak.org/hs/3Math/Rogers/Adv Alg 2/2-24-10 Lesson 5.5.pdf · Lesson 5.5--Complex Numbers and Roots You can see in the graph of f(x) = x2](https://reader031.vdocuments.net/reader031/viewer/2022022516/5b03993c7f8b9a6c0b8c93de/html5/thumbnails/4.jpg)
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Find the zeros of the function.
Example:
f(x) = x2 + 10x + 26 g(x) = x2 + 4x + 12
If a quadratic equation with real coefficients has nonreal roots, those roots are complex conjugates.
Find each complex conjugate.Example:
A. 8 + 5i B. 6i C. –8iD.
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Lesson Quiz
Solve each equation.
2. 3x2 + 96 = 0 3. x2 + 8x +20 = 0
4. Find the values of x and y that make the equation 3x +8i = 12 – (12y)i true.
5. Find the complex conjugate of
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HW: p. 353 1828 even, 29, 3239, 44, 70, 72, 7679, 83, 91, 94, 96, 98 = 27 problems