10000

T entrada °F 80°Brix iniciales 15°Brix finales 30

0.91

Duhring 212

Balance de materia

F=L+V10000=L+VFxf =Lxl + Vyv10000(0,15)=L(0,30)+V(0)

L= ((10000*0,15)/0,30)L= 5000 Lbm/h

Despejamos VF-L=V10000-5000=5000V= 5000Lbm/h

240°F

214°F

Alimentacion lbm/h

Cp alimentacion btu/lbm °F

Despejamos L asi

Fhf+Shs=Lhl +VHv1000(0,91)(80-214)+S(952,3)=5000(0)+5000(971,2)S=6380

A= 667 pie2

g=6,380(952,3)=(350 btu/h pie2 °F *A*(∆T K)

Tv Saturado °F 240 Area ?

U btu/h pie2 °F 350 Consumo de vapor ?

Balance de energia

Correccion de T

°F=3,2x + 11,2 X^2°F=3,2(0,30)+ 11,2 (0,30)^2°F=1,968

T1=212+1,968T1=213,968

EntoncesEPE = 214-212

hf=cpF(TF-T1) EPE = 2hf=0,90(80-213,968)hf=-121,91 Calor latente 240°F 952,3 BTU/lb

hfg=952,171 BTU/lb Calor latente 212°F 970,3 BTU/lb

hfg=968.929 BTU/lb ∆T = 0,45

Hv= 971,2

Fhf+Shs=Lhl +VHv1000(0,91)(80-214)+S(952,3)=5000(0)+5000(971,2)

Hv= Calor Latente + 2∆T

g=6,380(952,3)=(350 btu/h pie2 °F *A*(∆T K)