light - calstatela.edu · light we can use different terms to describe light: • color •...
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LightWe can use different terms to describe light:
• Color
• Wavelength
• Frequency
Light is composed of electromagnetic waves that
travel through some medium.
LightThe properties of the medium determine how light
travels through it.
In a vacuum, light waves travel at a speed of 3.00
x 108 m/s or 186,000 miles/s.
The speed of light in a vacuum is a constant that
is tremendously important in nature and
science—it is given the symbol, c.
Because light behaves like a wave, we candescribe it in one of two ways—by itswavelength or by its frequency.
= wavelength—distance between two adjacent wavecrests. has units of distance—frequently nanometers(nm).
= frequency—how many times the wave goes up anddown in a period of time. has units of inverse time(s-1 Hz[hertz]).
Light (con’t.)
Light (con’t.)
If you know either the frequency or thewavelength, you can calculate the other quantitythrough the relationship:
c = •
c = speed of light (3.00 x 108 m/s)
= wavelength (m)
= frequency (s-1)
A “particle” of light is called a photon.
ExamplesDiode laser pointer: = 670 nm
670 nm = 670 x 10-9 m
Photon with frequency: = 4.3 x 1013 Hz
nm 6980 m 6.98 m 10 x 6.98
s 10 x 4.3
s m 10 x 3.00
c
6-
1-13
1-8
=μ====
Light (con’t.)The type of light (ultraviolet, visible, infrared, x-ray,
etc.) is defined by either its frequency or
wavelength:
103 m
102 Hz
wavelength
frequency
gamma rays x-rays ultraviolet infrared microwave radio waves
10-5 nm 10-3 nm 1 nm 400
nm
700
nm
103 nm 106 nm 1 m
1024 Hz 1016 Hz 1012 Hz 1010 Hz 108 Hz 106 Hz 104 Hz1022 Hz 1020 Hz 1018 Hz visible
light
7 x 1014 Hz 4 x 1014 Hz
Light (con’t.)
The energy of light can be determined either from
its wavelength or frequency:
== h E or c h
E
Planck’s constant: h = 6.626 x 10-34 J s
Examples
4.3 x 1013 Hz ( ) light (6980 nm = 6.98 μm):
E = (6.626 x 10-34 J s)(4.3 x 1013 s-1) = 2.85 x 10-20 J
= 17.2 kJ mol-1
670 nm ( ) diode laser:
E = (6.626 x 10-34 J s)(3.00 x 108 m s-1) = 2.97 x 10-19 J
(670 x 10-9 m)
= 179 kJ mol-1
Examples (con’t.)
Violet light from a mercury lamp has a wavelength
of 436 nm:
E = (6.626 x 10-34 J s)(3.00 x 108 m s-1)
(436 x 10-9 m)
= 4.56 x 10-19 J
= 275 kJ mol-1
• Atoms and molecules absorb and emit light inthe ultraviolet (UV), visible (vis), infrared (IR),and microwave (μwave) regions of theelectromagnetic spectrum.
• Absorption or emission of light in the UV and visregions involves movement of electrons in theatom or molecule.• One reason UV light is so damaging is that the light
has enough energy to break chemicalbonds—biological and chemical systems
• E ( = 300 nm) = 399 kJ mol
• Average bond energy = 380 kJ mol-1
Potential Energy Surfaces
Internuclear Distance
1 2 3 4 5 6 7 8 9 10
Re
equilibrium bond length
At large separation, the atoms feel no attractiveforce to each other and represent a brokenchemical bond
As the bond distance decreases, the nuclear repulsioncauses the potential energy to increase dramatically--it requires a lot of energy to hold the positive chargesvery close to each other.
UV/vis Spectroscopy
Transitions in the
UV/visible
portion of the
spectrum
involve
movement of
electrons
between
electronic
energy states:
Distance
1 2 3 4 5 6 7 8 9 10
T1
S0
S1
AbsorptionFluorescence
Phosphorescence
Visible Spectrum of gaseous I2
Wavelength (nm)
500 525 550 575 600 625 6500.0
0.1
0.2
0.3
0.4
0.5
UV/vis Spectroscopy
UV/vis spectroscopy can provide information
about a molecule’s electronic states, its
geometry in the ground state and excited
electronic states, and its ionization potential
UV/vis spectroscopy can also be a powerful
analytical tool to measure concentrations of
atoms and molecules
IR Spectroscopy
Internuclear Distance
1 2 3 4 5 6
v = 0
v = 1
v = 2
v = 3
v = 4
vibrational energy levelsare determined by theirvibrational quantumnumber, v, the geometryof the molecule, and thestrength of the bondsconnecting the atoms
IR transition
Infrared Spectrum of CO2
Frequency (cm-1
)
228023002320234023602380
0.0
0.1
0.2
0.3
0.4
0.5
Infrared Spectrum of C6H6 (benzene)
Frequency (cm-1
)
500100015002000250030003500
0.0
0.2
0.4
0.6
0.8
1.0
x 10
IR Spectroscopy
IR spectroscopy can provide structural
information about a molecule’s geometry and
size and chemical information about which
functional groups the molecule contains
IR spectroscopy can also be used as an
analytical tool to determine concentrations of
species in solution or gas phases
Spectroscopy
Io Ibdx
light source sample cell detector
The intensity of light entering the cell is Io.
Some of the light is absorbed by the sample.
The intensity of light striking the detector is I.
Spectroscopy
Io Ibdx
light source sample cell detector
dx k I- dI =If we look at an infinitesimally
small cross section of the cell,
dx, the change in intensity
across that section is:I is intensity of light entering
that cross sectional area
k is a constant that includes the concentration
of the absorbing species and how strongly it
absorbs light at a specific wavelength
Spectroscopy
dx k- I
dI=
Io Ibdx
light source sample cell detector
Perform separation of variables:
Integrate both sides of
the equality: =b
0
I
I
dx k- I
dI
o
Spectroscopy
b0
II
xk- ln(I)o
=
Io Ibdx
light source sample cell detector
Results of
integration:
Applying limits
of intergration:kb-
I
Iln
o
=
Spectroscopy
exp{-kb} I
Ilnexp
o
=Exponentiate both
side of equality:
After some log
algebra:Cb}exp{- I exp{-kb} I I oo ==
where k = C
= absorption coefficient—a measure of
how strongly the light at a specific
wavelength
C = concentration of absorbing species
Spectroscopy
Cb} - 1{ I I o=
...} CB)(- CB)(- CB)(- {1 I I 32o ++++=
Expand exponential
in a power series:
Truncate series
following linear term:
Rearranging
gives: CB A I
I
o
=I = I-Io
A is the “absorbance”
Spectroscopy
Beer’s Law:
A = Cb
Absorbance is proportional to a species’
absorption coefficient and concentration, and
the path length of light traveling through the
cell
We can also define “transmittance” as:
T = 10-A or A = -log(T)
Optical Spectrometer Design
Light
source
Lens
Monochromator
Data
processing
DetectorSample