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    Linear Momentum

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    Enthusiasm is the energyand force that builds literal

    momentum of the humansoul and mind.

    - Bryant H. McGill

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    Linear Momentum

    It is a measure of thedifficulty encountered

    in bringing an object to

    rest.A heavy and fast car is

    harder to stop comparedto less heavy car with the

    same speed.

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    Linear Momentum

    Property of an object related to its mass

    and velocity. In equation; momentumpis

    equal to mass mtimes velocity v

    Momentum is a vector quantity

    vmp

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    Linear Momentum

    Originally, Newtons 2ndLaw is stated in

    terms of momentum:The rate of change of

    momentum of a body is equal to the net force

    applied to it.

    A force is required to change the momentumof abody.

    tpF /

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    Conservation of Momentum

    Consider twoparticles 1 and 2that collide on

    each other andthereby exertingforce on each

    other.

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    Conservation of momentum

    Assuming that the impulsive force isconstant, the change of momentum of a

    particle 1 is

    And the change in momentum of particle 2

    due to the impulsive force of particle 1 is

    )( 11112 ifon vvmtF

    )( 22221 ifon vvmtF

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    Conservation of momentum

    So that the total impulse of the external

    forces acting on the systemis just

    From Newtons 3rdLaw,

    thus

    )()( 2221112112 ififonon vvmvvmtFF 02112 onon FF

    ffii vmvmvmvm 22112211

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    Conservation of Momentum

    or,

    ffii vmvmvmvm 22112211

    Total momentum

    before the

    collision

    Total momentum

    after the

    collision

    fi PP

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    Conservation of Momentum

    In general,

    If the vector sum of the external forces

    on the system is zero, the totalmomentum of the system is constant

    - Principle of Conservation ofMomentum

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    12

    The Principle of Conservation

    of Linear Momentum

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    13

    Principle of Conservation of Linear Momentum:

    The total linear momentum of an isolated system

    remains constant(is conserved). An isolated systemis one for which the vector sum of the average

    external forces acting on the system is zero.

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    Impulse

    Changes in momentum may occur when there iseither a change in the mass of an object,a change invelocity or both.

    If momentum changes due to changing velocitywhile mass remains constant, accelerationoccurs.

    Forceproduces the acceleration

    For changing the momentum of an object, both forceand timeduring which the force acts areimportant.

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    Impulse ImpulseIis the product of the net force Fand the t

    time interval such force has in contact with the

    object or

    Impulse changes momentum in much the same way

    that force changes velocity. Thus

    Impulse = change in momentum

    tFI

    pI

    The change in momentum of a body

    du r ing a time interval equals the impu lse

    of the net force that acts on the bod y

    du r ing that interval .impu lse-momentum

    theorem

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    Impulse changes momentum

    Case 1: Increasing momentum

    If you wish to increase the momentum of

    something as much as possible, you not

    only apply the greatest forceyou can, you

    also extend the time of application as

    much as possible.

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    Impulse changes momentum

    Case 1: Increasing momentumLong-range cannons have long

    barrels. The longer the barrel,

    the greater the velocity of the

    emerging cannonball. Why?The force of exploding

    gunpowder in a long barrel acts

    on the cannonball for a longer

    time. This increased impulseproduces a greater momentum.

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    Impulse changes momentum

    Case 2: Decreasing Momentum over a

    long time.

    If you extend the time of impact 100 times,

    impact force is reduced 100-fold. So

    whenever you wish the force of impact to

    be small, extend the time of impact.

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    Case 2: Decreasing Momentum

    over a long time.

    A wrestler thrown to the floor tries to extend his

    time of arrival on the floor by relaxing his

    muscles and spreading the crash into a

    series of impact as foot, knee, hip ribs, andshoulder fold onto the floor in turn. The

    increased time of impact reduces the force of

    impact.

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    Case 2: Decreasing Momentum

    over a long time. A person jumping from an

    elevated position to a floor

    below bends his knees

    upon making contact,thereby extending the time

    during which his

    momentum is reduced 10

    to 20 times that a stiff-legged, abrupt landing.

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    Case 2: Decreasing Momentum

    over a long time. Bungee jumping puts the

    impulse-momentum

    relationship to a thrilling

    test. The long stretchingtime of the cord ensures a

    small average force to

    bring the jumper to a safe

    halt before hitting theground.

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    Impulse changes momentum

    Case 3: Decreasing Momentum over a

    Short Time

    Short impact times, the impact forces are

    larger.

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    Case 3: Decreasing Momentum

    over a Short Time The idea of short time of

    contact explains how a

    karate expert can sever a

    stack of bricks with the blowof his bare hand. By swift

    execution he makes the

    time of contact very brief

    and correspondingly makesthe force of impact huge.

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    25

    Impulse Example 1.

    A Well-Hit Ball

    A baseball (m=0.14kg) has initial velocity of v0=-

    38m/s as it approaches a bat. The bat applies

    an average force that is much larger than

    the weight of the ball, and the ball departs

    from the bat with a final velocity of vf=+58m.

    (a)Determine the impulse applied to the ball by

    the bat.

    (b) Assuming time of contact is =1.6*10-3s, find

    the average force exerted on the ball by the

    bat.

    F

    t

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    26

    0mvmvJ f

    )/38)(14.0()/58)(14.0( smkgsmkg

    Ns

    smkg

    t

    J

    F 8400106.1

    /.4.13

    3

    = +13.4 kg.m/s

    (a)

    (b)

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    27

    Example 2. A Rain Storm

    Rain comes straight down with velocity of v0=-

    15m/s and hits the roof of a car

    perpendicularly. Mass of rain per second thatstrikes the car roof is 0.06kg/s.Assuming the rain

    comes to rest upon

    striking the car

    (vf=0m/s), find the

    average force exerted

    by the raindrop.

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    28

    00 )( v

    tm

    t

    mvmvF f

    F = -(0.06kg/s)(-15m/s)=0.9

    N

    According to action-reaction law, the

    force exerted on the roof also has a

    magnitude of 0.9 N points downward: -

    0.9N

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    Collision

    Football isn't a contact sport, it's a collision

    sport. Dancing is a contact sport.

    -Duffy Daugherty

    A collisionis an isolated event in which two or

    more moving bodies (colliding bodies) exert

    forces on each other for a relatively short time.

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    Elastic Collision

    An elastic collision is anencounter between two

    bodies in which the total

    kinetic energy of the two

    bodies after the encounter

    is equal to their totalkinetic energy before the

    encounter.

    Elastic collisions are collisions

    in which both momentum and

    kinetic energy are conserved.

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    Inelastic collision

    in inelastic collision, the total kinetic energy

    of the system is not conserved, however,

    the momentum of the system is conserved.

    Some of the kinetic energy before collision

    is transformed into other types of energy.

    The total kinetic energy after the collision is lessthan that before the collision.

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    Inelastic collision

    Completely inelastic collision

    Colliding bodies stick together and move as

    one body after collision.

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    34

    Assembling a Freight Train

    Car 1 has a mass of m1=65*103kg and moves

    at a velocity of v01=+0.8m/s. Car 2 has a

    mass of m2=92*103

    kg and a velocity ofv02=+1.3m/s. Neglecting friction, find the

    common velocity vfof the cars after they

    become coupled.

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    (m1+m2) vf = m1v01 + m2v02

    After collision Before collision

    21

    022011

    mm

    vmvmvf

    )10921065(

    )/3.1)(1092()/8.0)(1065(33

    33

    kgkg

    smkgsmkg

    =+1.1 m/s

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    (m1+m2) vf = m1v01 + m2v02

    After collision Before collision

    21

    022011

    mm

    vmvmvf

    )10921065(

    )/3.1)(1092()/8.0)(1065(33

    33

    kgkg

    smkgsmkg

    =+1.1 m/s

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    37

    A Collision in One Dimension

    A ball of mass

    m1=0.25kg and velocity

    v01=5m/s collides head-on with a ball of mass

    m2=0.8kg that is initially

    at rest(v02=0m/s). No

    external forces act on

    the balls. If the collision

    in elastic, what are the

    velocities of the balls

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    38

    m1=0.25, m2=0.8

    v01 =5 m/s, v02= 0

    smvf

    /62.258.025.0

    8.025.0

    1

    smvf /38.258.025.0

    25.022

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    Collision between two objects of the same mass. One mass is at rest.

    Collision between two objects. One not at rest initially has twice the mass.

    Collision between two objects. One at rest initially has twice the mass.

    Simple Examples of Head-On Collisions

    (ELASTIC COLLISION : Energy and Momentum are Both Conserved)

    vmp

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    Collision between two objects of the same mass. One mass is at rest.

    Collision between two objects. One not at rest initially has twice the mass.

    Collision between two objects. One at rest initially has twice the mass.

    Simple Examples of Head-On Collisions

    (Totally Inelastic Collision, only Momentum Conserved)

    vmp

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    vmp

    Collision between two objects of the same mass. One mass is at rest.

    Example of Non-Head-On Collisions

    (Energy and Momentum are Both Conserved)

    If you vector add the total momentum after collision,

    you get the total momentum before collision.

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    A Collision in Two Dimensions

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    A Collision in Two Dimensions A collision in two dimensions obeys the

    same rules as a collision in one

    dimension: Total momentum in each

    direction is always the same before andafter the collision

    Total kinetic energy is the same before

    and after an elasticcollision

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    Example 1Two objects slide over a

    frictionless horizontal surface. The

    first object, mass m1= 5kg , is

    propelled with speed v1i= 4.5 m/s

    toward the second object, mass

    m2= 2.5 kg, which is initially atrest. After the collision, both

    objects have velocities which are

    directed = 30 on either side of

    the original line of motion of the

    first object. What are the final

    speeds of the two objects? Is the

    collision elastic or inelastic?

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    Center of Mass The center of mass is the location where all of the mass of

    the system could be considered to be located.

    For a solid body it is often possible to replace the entire

    mass of the body with a point mass equal to that of the

    body's mass. This point mass is located at the center of

    mass.

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    Center of Mass For homogenous solid bodies that have a symmetrical

    shape, the center of mass is at the center of body'ssymmetry, its geometrical center.

    The center of mass is the point about which a solid will

    freely rotate if it is not constrained.

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    Center of Mass For a solid body the center of mass is also

    the balance point. The body could besuspended from its center of mass and it

    would not rotate, i.e. not be out of balance.

    The center of mass of a solid body does not

    have to lie within the body. The center of

    mass of a hula-hoop is at its center wherethere is no hoop, just hula.

    The center of mass for a system of

    independently moving particles still has

    meaning and is useful in analyzing the

    interactions between the particles in thesystem.

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    Center of Mass

    In equation, it can be

    summarized as

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    Center of Mass

    In equation, it can be

    summarized as

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    Center of Mass

    For several bodies, the center of mass canbe obtained as

    In three dimensions, it can be written as