making dilutions. diluting a solution reduces the number of moles of solute per unit volume, but the...

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Making Dilutions

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Page 1: Making Dilutions. Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles does not change. Higher molarity

Making Dilutions

Page 2: Making Dilutions. Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles does not change. Higher molarity

• Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles does not change.

• Higher molarity = more concentrated

Page 3: Making Dilutions. Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles does not change. Higher molarity

Put in order from most dilute to most concentrated

• 6.0 M

• 0.05 M

• 1.05

• 1.5 M

• 5 x10-3 M

• 3.5 M

Page 5: Making Dilutions. Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles does not change. Higher molarity

How can we change concentration?

• If we want to make 3.0 M hydrochloric acid, but we only have 6.0 M hydrochloric acid, what can we do?

Page 6: Making Dilutions. Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles does not change. Higher molarity

Dilution Equation

• M1V1= M2V2

• Volumes can be in mL or L, but they must be the same on both sides.

• V is total volume of the solution, not the volume of water added!

Page 7: Making Dilutions. Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles does not change. Higher molarity

Practice• I have 20.0 mL of 2.00 M solution. I need to make

0.400 M solution. To what volume should I add?

• M1V1= M2V2

• (2.00 M)(20.0) = (0.400 M)V2

• V2 = 100. mL

Page 8: Making Dilutions. Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles does not change. Higher molarity

• I have 0.25 L of 3.0 M HBr. How much water should be added to produce a 2.0 M solution?

• M1V1= M2V2

• (3.0 M)(0.25 L) = (2.0 M)V2

• V2= 0.375 L

• V is total volume.

• I already have 0.25 L of HBr,

• 0.375 - 0.25 = 0.125

• So I should add 0.13 L of water