mat prisma segilima
TRANSCRIPT
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PROFIL
RUMUS DASAR
JARING –
JARING
LUAS
PERMUKAAN
VOLUME
DEFINISI
UNSUR SOAL
Sumber :
wikipedia.com, yahooanswer.co.id
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Kelompok 4
• Bambang Jati Laksono (05)
• Danang Chrismawan Adi (06)
• Dian Aldira Indrajati (09)
• Kathlyn Wiyono (13)
VIII.6, SMP 2 BLORA
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Prisma segilima adalah
bangun ruang yang
dibatasi oleh dua buah
bidang segilima yang
sejajar dan kongruen
serta bidang-bidang
tegak yang
menghubungkan bidang
segilima tersebut.
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Prisma segi-n beraturan :
1. Jumlah sisi = n + 2
2. Jumlah rusuk = 3n
3. Jumlah titik sudut = 2n
4. Jumlah diagonal sisi = n(n - 1)
5. Jumlah diagonal ruang = n(n - 3)
6. Jumlah bidang diagonal = {n(n -
3)}/2
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7. Luas Permukaan = (2 x Luas alas) +
(Keliling alas x tinggi)
8. Volume = Luas alas x tinggi
Luas alas prisma segilima beraturan
=
1,72 x rusuk alas x rusuk alas
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1. Sisi atau
bidang
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2. Rusuk
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3. Titik
sudut
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4.
Diagonal
sisi
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5. Diagonal
ruang
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6. Bidang
diagonal
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t
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t
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I. Contoh
soal1. Luas alas prisma segilima
beraturan ialah 150 cm2. Jika
volume prisma ialah 6000 cm3,
hitunglah tinggi prisma segilima
beraturan tersebut!
Pembahasan :
V = L alas x t
6000 cm3 = 150 cm2 x t
6000/150 cm = t
40 cm = t
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2. Perhatikan gambar
berikut!
Bila diketahai luas
alas prisma tersebut
ialah 172 cm2. Tentukan
luas permukaan
prisma segilima!
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Pembahasan :
L permukaan = (2 x L alas) +
(Kell alas x t)
= (2 x 172 cm2) + {(5 x 10
cm) x 27 cm}
= 344 cm2 + (50 cm x 27
cm)
= 344 cm2 + 1350 cm2
= 1694 cm2
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3. Dari gambar tersebut
diketahui luas persegi
panjang ABCD ialah 250
cm2, luas alas prisma
ialah 172 cm2. Hitunglah
volumenya!Pembahasan :
L persegi panjang = p x l
250 cm2 = 10 cm x l
250/10 cm = l
25 cm = l
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V = L alas x t
V = 172 cm2 x 25 cm
V = 4300 cm3
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II. Latihan
soal
1. Perhatikan gambar
tersebut! Diketahui
luas alas dari prisma
segilima beraturan di
samping ialah 240
dm2. Hitunglah
volume prisma dalam
satuan liter!
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2. Tentukan luas alas
pada gambar
tersebut jika
deketahui luas
permukaan prisma
ialah 286 cm2!
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3. Perhatikan gambar
di samping! Luas alas
prisma ialah 6,88
cm2 sedangkan
volumenya 27,52 cm3.
Tentukan luas
selubung dari prisma
segilima beraturan
tersebut!
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Pembahasan :
1. V = L alas x t
= 240 dm2 x 15 dm
= 3600 dm3
= 3600 liter
2. L permukaan = (2 x L alas) +
(Kell alas x t)
286 cm2 = (2 x L alas) + {(5 x 5
cm) x 8 cm}
286 cm2 = (2 x L alas) + (25 cm
x 8 cm)
286 cm2 = (2 x L alas) + 200
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286 cm2 – 200 cm2 = 2 x L alas
86 cm2 = 2 x L alas
43 cm2 = L alas
3. V = L alas x t
27,52 cm3 = 6,88 cm2 x t
2752/100 x 100/688 cm = t
4 cm = t
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3. L selubung = Kell alas x
t
L selubung = (5 x 2 cm) x
4 cm
L selubung = 10 cm x 4 cm
L selubung = 40 cm2
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