mate-casos de factorizacion 1-5
TRANSCRIPT
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CUANDO TODOS LOS TÉRMINOS DE UN POLINOMIO TIENEN UN FACTOR COMÚN.
a2 + 2a=a2 + 2a= a(a+2) R.
2)
a(x + 1)+b(x + 1) = a(x + 1)+b(x + 1) = (x + 1) (a + b) R.
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ax – 2bx – 2ay + 4by= (ax – 2ay) – (2bx + 4by)= a(x – 2y) -2b(x - 2y)= (x – 2y)(a – 2b) R.
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4x2 + 25y2 - 20xyOrdenando el trinomio, tenemos:4x2 - 20xy + 25y2
2x 5y
= (2x - 5y)(2x - 5y) = (2x – 5y) 2 R.
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16x2 - 25y4
2
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2
4
2
2
2
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16x2 - 25y4 = (4x + 5y2)(4x - 5y2) R.
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x4 + x2y2 + y4
x2 y2
(2)x2.y2
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x4 + x2y2 + y4
+ x2y2 - x2y2
x4 + 2x2y2 + y4 - x2y2
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=(x4 + 2x2 y2 + y4 ) - x2y2
=(x2 + y2)2 - x2y2
=(x2 + y2 + xy)( x2 + y2 - xy)
=(x2 + xy + y2)( x2 – xy + y2)R.
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