math project 2 by: holden greene and joseph young
TRANSCRIPT
Math Project 2Math Project 2
By: Holden Greene and Joseph YoungBy: Holden Greene and Joseph Young
Part 1Part 1
•We plugged the numbers from the table into the formula that was given. h=at^2+bt+c
•1) 23645=4a+2b+c
•2) 32015=400a+20b+c
•3) 33715=1600a+40b+c
•We plugged the numbers from the table into the formula that was given. h=at^2+bt+c
•1) 23645=4a+2b+c
•2) 32015=400a+20b+c
•3) 33715=1600a+40b+c
Part 2Part 2
•First we subtracted problem 1 from problem 2. Using Elimination to get the answer.
32015=400a+20b+c
- 23645=-4a-2b-c
----------------------------
8370=396a-18b
This answer becomes #4.
•First we subtracted problem 1 from problem 2. Using Elimination to get the answer.
32015=400a+20b+c
- 23645=-4a-2b-c
----------------------------
8370=396a-18b
This answer becomes #4.
Part 2 ContinuedPart 2 Continued
•We then subtracted problem 2 from 3 and used elimination to solve it again.
33715=1600a+40b+c
-32015=-400a-20b-c
---------------------------
1700=1200a+20b
This answer becomes problem 5.
•We then subtracted problem 2 from 3 and used elimination to solve it again.
33715=1600a+40b+c
-32015=-400a-20b-c
---------------------------
1700=1200a+20b
This answer becomes problem 5.
Part 2 ContinuedPart 2 Continued
•We then used elimination with problems 4 and 5. We multiplied 4 by 10 and 5 by -9 in order to eliminate.
8370=396a+18b (10)= 83700=3960a+180b
1700=1200a+20b (-9)= -15300=-10800a-180b
-----------------------------------------------------------
68400=-6840a
then divide by -6840 which gives you an answer of -10=a
•We then used elimination with problems 4 and 5. We multiplied 4 by 10 and 5 by -9 in order to eliminate.
8370=396a+18b (10)= 83700=3960a+180b
1700=1200a+20b (-9)= -15300=-10800a-180b
-----------------------------------------------------------
68400=-6840a
then divide by -6840 which gives you an answer of -10=a
Part 2 ContinuedPart 2 Continued
•We then plugged the A(-10) that we got from our earlier solution into problem 5.
1700=1200(-10)+20b
1700=-12000+20b
13700=20b
_____________________
The answer that we got was 685=b.
•We then plugged the A(-10) that we got from our earlier solution into problem 5.
1700=1200(-10)+20b
1700=-12000+20b
13700=20b
_____________________
The answer that we got was 685=b.
Part 2 ContinuedPart 2 Continued
•We then plugged our answers for A(-10) and B(685) into our first problem to find C.
23645=4(-10)+2(685)+C
23645=-40+1370+C
23645+40-1370=C
_____________________
The answer that we got was C=22315.
•We then plugged our answers for A(-10) and B(685) into our first problem to find C.
23645=4(-10)+2(685)+C
23645=-40+1370+C
23645+40-1370=C
_____________________
The answer that we got was C=22315.
Part 2 SummaryPart 2 Summary
• In summation of our work the answers that we got were:
A=-10
B=685
C=22315
• In summation of our work the answers that we got were:
A=-10
B=685
C=22315
Part 3Part 3
•We then plugged our numbers into our equation h=at^2+bt+c.
•This gave us h=-10t^2+685t+22315
•We then plugged our numbers into our equation h=at^2+bt+c.
•This gave us h=-10t^2+685t+22315
Part 4Part 4
•We found the maximum value of the quadratic function by solving for Y from our equation in Part 3. We are then able to come up with our maximum
•We found the maximum value of the quadratic function by solving for Y from our equation in Part 3. We are then able to come up with our maximum
The Solving of Part 4The Solving of Part 4
y=-10t^2+685t+22315
y=-10(t^2-68.5t+1173.0625)+22315+-10(1173.0625)
22315+11730.625
y=-10(t-34.25)^2
y=-10(t-34.25)^2+34045.625•This gives us our graph and the parabola that we will be using for our answer. A=-10 X=T H=-34.25 K=34045.625
y=-10t^2+685t+22315
y=-10(t^2-68.5t+1173.0625)+22315+-10(1173.0625)
22315+11730.625
y=-10(t-34.25)^2
y=-10(t-34.25)^2+34045.625•This gives us our graph and the parabola that we will be using for our answer. A=-10 X=T H=-34.25 K=34045.625
Part 5, The GraphPart 5, The Graph
•We used this equation to get our graph y=-10(t-34.25)^2+34045.625.
•Maximum= 34045.625
•Vertex=(34.25, 34045.625)
•Axis X= 34.25
•We used this equation to get our graph y=-10(t-34.25)^2+34045.625.
•Maximum= 34045.625
•Vertex=(34.25, 34045.625)
•Axis X= 34.25
Part Five, The Graph Continued
Part Five, The Graph Continued
Part 6Part 6
Yes it changed our minds completely about the purpose of math and the way that it can be used in real world situations. It really enlightened our thinking towards the real world examples that math participates in and give credence towards math and the purpose that it serves in the world outside of the boundaries of our educational facilities. Math is an ever important factor in life more so probably then English or a history or social studies class of some sort. This is due to the ever present factor of math in our life while rarely must we remember history or the role that it plays in our world. And english is obviously a very unneeded skill that will serve no purpose later in life, because very rarely do we use english in our lives. That is why math is very important to us and is how this project has revealed to us the importance of math in the real world. We use math alot more then any other subject.
Yes it changed our minds completely about the purpose of math and the way that it can be used in real world situations. It really enlightened our thinking towards the real world examples that math participates in and give credence towards math and the purpose that it serves in the world outside of the boundaries of our educational facilities. Math is an ever important factor in life more so probably then English or a history or social studies class of some sort. This is due to the ever present factor of math in our life while rarely must we remember history or the role that it plays in our world. And english is obviously a very unneeded skill that will serve no purpose later in life, because very rarely do we use english in our lives. That is why math is very important to us and is how this project has revealed to us the importance of math in the real world. We use math alot more then any other subject.